, mình giải cho

giai kieu gi co giang cho minh di

 1+2+3+4+5+6+7.......17+18+19+20=(29+1)×(20:10)

=21×10

=210

Ta có: 1+2+3+…+20=20.(20+1):2=20.21:2=420:2=210

khoảng cách: 2-1=1

số số hạng là: (20-1):1+1=20(số)

tổng là: (20+1)x20:2=210

Đáp số : 210

k cho mình nha

\(A=1\times3+2\times4+3\times5+4\times6+...+97\times99+98\times100\)

\(B=1\times3+3\times5+...+97\times99\)

\(6\times B=1\times3\times\left(5+1\right)+3\times5\times\left(7-1\right)+5\times7\times\left(9-3\right)+...+97\times99\times\left(101-95\right)\)

\(=1\times3+1\times3\times5+3\times5\times7-1\times3\times5+...+97\times99\times101-95\times97\times99\)

\(=1\times3+97\times99\times101\)

\(B=161651\)

\(C=2\times4+4\times6+...+98\times100\)

\(6\times C=2\times4\times6+4\times6\times\left(8-2\right)+...+98\times100\times\left(102-96\right)\)

\(=2\times4\times6+4\times6\times8-2\times4\times6+...+98\times100\times102-96\times98\times100\)

\(=98\times100\times102\)

\(C=166600\)

\(A=B+C=161651+166600=328251\)

$A=1\times 3+2\times 4+3\times 5+4\times 6+...+97\times 99+98\times 100$

$B=1\times 3+3\times 5+...+97\times 99$

$6\times B=1\times 3\times \left(5+1\right)+3\times 5\times \left(7-1\right)+5\times 7\times \left(9-3\right)+...+97\times 99\times \left(101-95\right)$

$=1\times 3+1\times 3\times 5+3\times 5\times 7-1\times 3\times 5+...+97\times 99\times 101-95\times 97\times 99$

$=1\times 3+97\times 99\times 101$

$B=161651$

$C=2\times 4+4\times 6+...+98\times 100$

$6\times C=2\times 4\times 6+4\times 6\times \left(8-2\right)+...+98\times 100\times \left(102-96\right)$

$=2\times 4\times 6+4\times 6\times 8-2\times 4\times 6+...+98\times 100\times 102-96\times 98\times 100$

$=98\times 100\times 102$

$C=166600$

$A=B+C=161651+166600=328251$

1+2+3+4+5+6+7+8+9+10=55

mik nhầm:D

1+2+3+4+5+6+7+8+9+10=55(không dùng máy tính)

đầu bài: 1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20

= (1+19)+(2+18)+(3+17)+(4+16)+(5+15)+(6+14)+(7+13)+(8+12)+(9+11)+20

=    20   +   20   +   20   +    20  +   20  +    20  +   20   +   20   +   20   +20

=   20.10

=   200

1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20=\(\frac{\left(1+20\right)20}{2}\)=210

45 + 55 + 73 + 53 = 226

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210

hổng có bík

\(B=\frac{1}{3.4}-\frac{1}{4.5}-\frac{1}{5.6}-\frac{1}{6.7}-\frac{1}{7.8}-\frac{1}{8.9}-\frac{1}{9.10}\)

\(=\frac{1}{3}-\frac{1}{4}-\left(\frac{1}{4}-\frac{1}{5}\right)-\left(\frac{1}{5}-\frac{1}{6}\right)-\left(\frac{1}{6}-\frac{1}{7}\right)-\left(\frac{1}{7}-\frac{1}{8}\right)-\left(\frac{1}{8}-\frac{1}{9}\right)-\left(\frac{1}{9}-\frac{1}{10}\right)\)

\(=\frac{1}{3}-\frac{1}{4}-\frac{1}{4}+\frac{1}{10}\)

\(=\frac{-1}{15}\)

 B BANG 8

a)3

b)1/64

c)125

d)9/4

a)\(\frac{3^5}{3^4}=\frac{243}{81}=3\)

b)\(\frac{4^7}{4^{10}}=\frac{16384}{1048576}=\frac{1}{64}\)

c)\(\frac{5^{11}}{5^8}=\frac{48828125}{390625}=125\)

d)\(\frac{6^2}{4^2}=\frac{36}{16}=\frac{9}{4}\)

x+1+2+3+....+100 = 250000

x + 5050 = 250000

x = 250000 - 5050

x = 2244950

x+1+2+3+....+100 = 250000
x + 5050 = 250000
x = 250000 - 5050
x = 2244950

@@ hacker

x+1+2+3+4+5+6+7+.....+100=250000

suy ra x+(1+100)x100:2=250000

suy ra x+101x50=250000

suy ra x+5050=250000

suy ra x=250000-5050

x=244950

1+1+2+2+3+3+4+4+5+5+6+6+7+7+8+9+8+9+10+12+13+14+15+16+17+18+19+20+30+1000000=10000274

10000274

10000274 nha