x : 60 = 120 + 60
x - (28 - x) = x - 24x−(28−x)=x−24.
(60/x+5)+(60/x-4)=120/x
Giải phương trình: \(\frac{60}{\frac{120}{x}-4}+\frac{60}{\frac{120}{x}-5}=x\)
\(ĐKXĐ:\hept{\begin{cases}x\ne0\\x\ne30\\x\ne24\end{cases}}\)
Ta có \(\frac{60}{\frac{120}{x}-4}+\frac{60}{\frac{120}{x}-5}=x\)
\(\Leftrightarrow\frac{60}{\frac{120-4x}{x}}+\frac{60}{\frac{120-5x}{x}}=x\)
\(\Leftrightarrow\frac{60x}{120-4x}+\frac{60x}{120-5x}=x\)
\(\Leftrightarrow\frac{60}{120-4x}+\frac{60}{120-5x}=1\left(Do\text{ }x\ne0\right)\)
\(\Leftrightarrow\frac{15}{30-x}=1-\frac{12}{24-x}\)
\(\Leftrightarrow\frac{15}{30-x}=\frac{24-x-12}{24-x}\)
\(\Leftrightarrow\frac{15}{30-x}=\frac{12-x}{24-x}\)
\(\Leftrightarrow360-15x=\left(12-x\right)\left(30-x\right)\)
\(\Leftrightarrow360-15x=360-42x+x^2\)
\(\Leftrightarrow x^2-27x=0\)
\(\Leftrightarrow x\left(x-27\right)=0\)
\(\Leftrightarrow x=27\left(Tm\text{ }ĐKXĐ\right)\)
Tìm x biết
1 + 1/60 + 12/120 < x/36 + (-1)/60 < 58/-30 + 59/72 + (-1)/60
tìm x thuộc z biết 1 + 1/60 + 19/120 < x/36 + -1/60 < 58/90 + 59/72 + -1/60
(60/x+5)+(60/x-4)=120/ x
Viết lời giải chi tiết nha
\(\frac{60}{x+5}+\frac{60}{x-4}=\frac{120}{x}\Rightarrow\frac{1}{x+5}+\frac{1}{x-4}=\frac{2}{x}\)
\(\Rightarrow\frac{x\left(x-4\right)+x\left(x+5\right)-2\left(x+5\right)\left(x-4\right)}{x\left(x+5\right)\left(x-4\right)}=0\)
\(\Rightarrow\frac{x^2-4x+x^2+5x-2x^2-2x+40}{x\left(x+5\right)\left(x-4\right)}=0\)
\(\frac{-x+40}{x\left(x+5\right)\left(x-4\right)}=0\)
mà x(x+5)(x-4) khác 0 nên
-x+40=0
nên x=40
Tìm x thuộc z ,biết:
1+ -1/60+19/120<x/36+ -1/60<58/90+59/72+ -1/60
Số giá trị x∈Z , thỏa mãn 1+\(\dfrac{-1}{60}\)+\(\dfrac{19}{120}\)<\(\dfrac{x}{36}\)+\(\dfrac{-1}{60}\)<\(\dfrac{58}{90}\)+\(\dfrac{59}{72}\)+\(\dfrac{-1}{60}\) là :