1 + 1 - 1 x 1 =
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LARGE 7)Gfrac{sqrt{x}+1}{x-1}+frac{sqrt{x}-1}{sqrt{x}+1}-frac{2sqrt{x}+2}{x-1}Gfrac{sqrt{x}+1}{sqrt{x}-1}+frac{sqrt{x}-1}{sqrt{x}+1}-frac{2(sqrt{x}+1)}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{sqrt{x}+1}{x-1}+frac{sqrt{x}-1}{sqrt{x}+1}-frac{2}{sqrt{x}-1}Gfrac{(sqrt{x}+1)^2+(sqrt{x}-1)^2-2(sqrt{x}+1)}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{2x-2sqrt{x}}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{2sqrt{x}(sqrt{x}-1)}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{2sqrt{x}}{sqrt{x}+1}8)H(frac{1}{sqrt{x}-1}+frac{sqrt{x}}{x-1}):(frac{sqrt{x}}{sqrt{x}-1}-...
Đọc tiếp
\[\LARGE 7)G=\frac{\sqrt{x}+1}{x-1}+\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{2\sqrt{x}+2}{x-1}\\G=\frac{\sqrt{x}+1}{\sqrt{x}-1}+\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{2(\sqrt{x}+1)}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{\sqrt{x}+1}{x-1}+\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{2}{\sqrt{x}-1}\\G=\frac{(\sqrt{x}+1)^2+(\sqrt{x}-1)^2-2(\sqrt{x}+1)}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{2x-2\sqrt{x}}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{2\sqrt{x}(\sqrt{x}-1)}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{2\sqrt{x}}{\sqrt{x}+1}\\8)H=(\frac{1}{\sqrt{x}-1}+\frac{\sqrt{x}}{x-1}):(\frac{\sqrt{x}}{\sqrt{x}-1}-1)\\H=(\frac{1}{\sqrt{x}-1}+\frac{\sqrt{x}}{(\sqrt{x}-1)(\sqrt{x}+1)}):(\frac{\sqrt{x}-(\sqrt{x}-1)}{\sqrt{x}-1})\\H=\frac{\sqrt{x}+1+\sqrt{x}}{(\sqrt{x}-1)(\sqrt{x}+1)}:\frac{\sqrt{x}-\sqrt{x}+1}{\sqrt{x}-1}\\H=\frac{2\sqrt{x}+1}{(\sqrt{x}-1)(\sqrt{x}+1)}:\frac{1}{\sqrt{x}-1}\\H=\frac{2\sqrt{x}+1}{(\sqrt{x}-1)(\sqrt{x}+1)}.(\sqrt{x}-1)\\H=\frac{2\sqrt{x}}{\sqrt{x}+1}\]
P = 1 1/3 x 1 1/8 x 1 1/15 x 1 1/24 x 1 1/35 x 1 1/48 x 1 1/63 x 1 1/80 x 1 1/99
giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|
ta có :
\(\left|x+1\right|+\left|x-1\right|=1+\left|\left(x-1\right)\left(x+1\right)\right|\)
\(\Leftrightarrow\left|x-1\right|\left|x+1\right|-\left|x-1\right|-\left|x+1\right|+1=0\)
\(\Leftrightarrow\left(\left|x-1\right|-1\right)\left(\left|x+1\right|-1\right)=0\Leftrightarrow\orbr{\begin{cases}\left|x-1\right|=1\\\left|x+1\right|=1\end{cases}}\)
\(\Leftrightarrow x\in\left\{-2,0,2\right\}\)
1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 =
1 nhé bạn
1
(số nào nhân với 1 bằng chính nó)
= 1
#Học tốt!!!
Xem thêm câu trả lời
a) (1 - 1/2) x (1 - 1/3) x (1 - 1/4) x (1 - 1/5) x (1 - 1/6)
b) (1 - 1/2) x (1 - 1/4)x...x (1 - 1/2019) x (1 - 1/2020)
a, \(=\dfrac{1.2.3...5}{2.3...6}=\dfrac{1}{6}\)
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a.A1 1/2 x 1 1/3 x 1 1/4 x 1 1/5 x...x1 1/2020 x 1 1/2021
b.B1 1/2 + 1 1/6 + 1 1/12 +1 1/20+ ... + 1 1/380 + 1 1/420
c.C1 6/8 x 1 6/18 x 1 6/30 x 1 6/44 x ... x 1 6/10700
Đọc tiếp
a.A=1 1/2 x 1 1/3 x 1 1/4 x 1 1/5 x...x1 1/2020 x 1 1/2021
b.B=1 1/2 + 1 1/6 + 1 1/12 +1 1/20+ ... + 1 1/380 + 1 1/420
c.C=1 6/8 x 1 6/18 x 1 6/30 x 1 6/44 x ... x 1 6/10700
tính giá trị của biểu thức
A =( 1+1/15)x( 1+1/24)x(1+1/35)x ......x (1+1/9999)
B =(1+1/2)x(1=1/3)x(1+1/4)x.......x(1+1/2017)
C =(1-1/97)x(1-1/98)x(1-1/99)x.....x(1-1/1000)
tính giá trị biểu thức
A=(1+1/15)x(1+1/24)x(1+1/35)x.......x(1+1/9999)
B=(1+1/2)x(1+1/3)x(1+1/4)x...x(1+1/2017)
C=(1-1/97)x(1-1/98)x(1-1/99)x.......x(1-1/1000)
B=3/2x4/3x...........x2018/2017
=3x4x5x...........x2018/2x3x2x2x............x2017
=2x2018
=4036
A,C tương tự
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tính giá trị biểu thức
A=(1+1/15)x(1+1/24)x(1+1/35)x.......x(1+1/9999)
B=(1+1/2)x(1+1/3)x(1+1/4)x...x(1+1/2017)
C=(1-1/97)x(1-1/98)x(1-1/99)x.......x(1-1/1000)