phan tích da thức thanh nhan tu
a) 2a(x+y)+y+x
b) 2(x-y)^2-x+y
c) x^2-xy-3x+3y
d) ax^2+6x^2-6x-ax+a+b
2) phan tich da thuc thanh nhan tu ( nhieu phuong phap)
a) 5a^2+20a+20 c) 25-x^2+2xy-y^2
b) 5a^2-10ab+5b^2 d) m^2+2mn+n^2-p^2
Những câu hỏi liên quan
phan tich da thuc thanh nhan tu
a) 2a(x+y)+y+x
b) 2(x-y)^2-x+y
c) x^2-xy-3x+3y
d) ax^2+6x^2-6x-ax+a+b
2) phan tich da thuc thanh nhan ( nhieu phuong phap)
a) 5a^2+20a+20 c) 25-x^2+2xy-y^2
b) 5a^2-10ab+5b^2 d) m^2+2mn+n^2-p^2
phan tich da thuc thanh nhan tu a, (3x+1)^2-(x+1)^2
b, 6x-6y-x^2+xy
\(a,\left(3x+1\right)^2-\left(x+1\right)^2\)
\(=\left(3x+1-x-1\right)\left(3x+1+x+1\right)\)
\(=2x\left(4x+2\right)\)
\(=4x\left(2x+1\right)\)
\(b,6x-6y-x^2+xy\)
\(=\left(6x-6y\right)-\left(x^2-xy\right)\)
\(=6\left(x-y\right)-x\left(x-y\right)\)
\(=\left(x-y\right)\left(6-x\right)\)
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Phan tich da thuc thanh nhan tu :
a) x^2 - x - y^2 - y
b) x^2 - 2 xy + y^2 - z^2
c) 5x - 5y + ax - ay
d) a^3 - a^2 x - ay + xy
e) 4x^2 - y^2 +4x + 1
a) x2-x-y2-y=(x2-y2)-(x+y)=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)
b)x2-2xy+y2-z2=(x-y)2-z2=(x-y-z)(x-y+z)
c)5x-5y+ax-ay=5(x-y)+a(x-y)=(x-y)(5+a)
d)a3-a2x-ay+xy=a2(a-x)-y(a-x)=(a-x)(a2-y)
e)4x2-y2+4x+1=[(2x)2+2.2x.1+12]-y2=(2x+1)2-y2=(2x+1-y)(2x+1+y)
Chúc bạn học tốt!
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phan tich da thuc thanh nhan tu :
5x^2 + 5xy - x - y
7x - 6x^2 - 2
5x^2 + 5xy - x - y
=5x.(x+y)-(x+y)
=(x+y)(5x-1)
7x - 6x^2 - 2
=-6x2+3x+4x-2
=-3x.(2x-1)+2.(2x-1)
=(2x-1)(2-3x)
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a) x^2 + y^2 -25 +2xy
b) a ^2- 2a -4b^2-4b
c)a^2-b^2-5a-5b
phan tich da thuc thanh nhan tu
\(a,=\left(x+y\right)^2-5^2=\left(x+y+5\right)\left(x+y-5\right)\)
\(b,=\left(a-1\right)^2-1-\left(2b+1\right)^2-1=\)
\(c,=\left(a-b\right)\left(a+b\right)-5\left(a+b\right)=\left(a+b\right)\left(a-b-5\right)\)
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a,( x2 + 2xy + y2 ) -25
=( x + y )2 - 52
=( x + y + 5) ( x + y - 5)
b,
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1 . Phan tich da thuc thanh nhan tu :
x^2 + 6x - 9 -y^2
2. Tim x :
x^2 -x - 12 = 0
Bài 1:
\(x^2-6x+9-y^2\)
\(=\left(x-3\right)^2-y^2\)
\(=\left(x-3+y\right)\left(x-3-y\right)\)
Bài 2:
\(x^2-x-12=0\)
\(\Leftrightarrow x^2-4x+3x-12=0\)
\(\Leftrightarrow x\left(x-4\right)+3\left(x-4\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x-4\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+3=0\\x-4=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-3\\x=4\end{array}\right.\)
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1. x2+6x-9-y2
=-(x2-6x+y2)-32
=-(x-y)2-32
=(-x+y-3)(-x+y+3)
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2. x2 - x - 12 = 0
=> x2 - 4x + 3x - 12 = 0
=> x( x - 4 ) + 3( x - 4 ) = 0
=> ( x + 3 )(x - 4 ) = 0
\(\Rightarrow\left[\begin{array}{nghiempt}x+3=0\\x-4=0 \end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x=-3\\x=4\end{array}\right.\)
Vậy x=-3; x=4
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Xem thêm câu trả lời
phan tich da thuc sau thanh nhan tu ab(x^2+y^2)-xy(a^2+b^2)
\(ab\left(x^2+y^2\right)-xy\left(a^2+b^2\right)\)
\(=abx^2+aby^2-a^2xy-b^2xy\)
\(=ax\left(bx-ay\right)+by\left(ay-bx\right)\)
\(=ax\left(bx-ay\right)-by\left(bx-ay\right)\)
\(\left(bx-ay\right)\left(ax-by\right)\)
hãy k nếu bạn thấy đây là câu tl đúng :)
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phan tich da thuc thanh nhan tu
6x2 - 3xy + x + y -1
phan tich da thuc thanh nhan tu
a: 4x^2-20xy +25-[3x-2]^2
b: x^2-6x+5+[x-5]^2
\(x^2-6x+5+\left(x-5\right)^2\)
\(=x^2-6x+5+x^2-10x+25\)
\(=2x^2-6x-10x+30\)
\(=x.\left(2x-6\right)-5.\left(2x-6\right)\)
\(=\left(x-5\right).\left(2x-6\right)\)
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