a/\(1248:12-2,5\times4+6,03.\)

\(=104-10+6,03\)

\(=94+6,03=100,03\)

b/\(\left(\frac{2}{3}+\frac{5}{7}-\frac{1}{3}\right)\times\frac{7}{11}+3\frac{1}{3}.\)

\(=\left(\frac{29}{21}-\frac{1}{3}\right)\times\frac{7}{11}+3\frac{1}{3}\)

\(=\frac{22}{11}\times\frac{7}{11}+3\frac{1}{3}\)

\(=\frac{2}{3}+3\frac{1}{3}\)

\(=\frac{2}{3}+\frac{10}{3}\)

\(=\frac{12}{3}=4\)

\(=\frac{16}{3}x\frac{30}{7}=\frac{480}{21}=\frac{160}{7}\)

\(\frac{33}{5}:\frac{21}{4}=\frac{33}{5}x\frac{4}{21}=\frac{132}{105}=\frac{44}{35}\)

a) \(5\frac{1}{3}.4\frac{2}{7}=\frac{16}{3}.\frac{30}{7}=\frac{160}{7}\)

b) \(6\frac{3}{5}:5\frac{1}{4}=\frac{33}{5}:\frac{21}{4}=\frac{33}{5}.\frac{4}{21}=\frac{44}{35}\)

5\(\frac{1}{3}\)x 4\(\frac{2}{7}\)=22\(\frac{6}{7}\)

6\(\frac{3}{5}\): 5\(\frac{1}{4}\)= 1\(\frac{9}{35}\)

\(\text{a) }\frac{-4}{x-1}=\frac{x-1}{-9}\)

\(\Leftrightarrow\left(x-1\right).\left(x-1\right)=\left(-4\right).\left(-9\right)\)

\(\Leftrightarrow\left(x-1\right)^2=36\)

\(\Leftrightarrow x-1=\sqrt{36}\)

\(\Leftrightarrow x-1=6\)

\(\Leftrightarrow x=7\)

\(a,\frac{-4}{x-1}=\frac{x-1}{-9}\)

\(\Rightarrow(x-1)(x-1)=(-4)\cdot(-9)\)

\(\Rightarrow(x-1)^2=36\)

\(\Rightarrow(x-1)^2=6^2\)

\(\Rightarrow x-1=\pm6\)

\(\Rightarrow\hept{\begin{cases}x-1=6\\x-1=-6\end{cases}}\Rightarrow\hept{\begin{cases}x=7\\x=-5\end{cases}}\)

\(b,-1,75\cdot x+3\frac{3}{4}=-24\)

\(\Rightarrow-1,75\cdot x+3,75=-24\)

\(\Rightarrow-1,75\cdot x=-24-3,75\)

\(\Rightarrow-1,75\cdot x=-27,75\)

\(\Rightarrow x=-27,75:(-1,75)\)

 Tính rồi tìm ra giá trị của x thôi :v

a) -4/x-1=x-1/-9

<=> (x-1).(x-1)=-4.-9

<=> (x-1)² = 36

<=> (x-1)² = (\(\pm\)6²)

<=>\(\orbr{\begin{cases}x-1=6\\x-1=-6\end{cases}}\)

<=>\(\orbr{\begin{cases}x=6+1=7\\x=-6+1=5\end{cases}}\)

Vậy x \(\in\){7,5}

x=17 nhé

mk kô bt đánh ps đâuu à