\(\frac{2006\times2005-1}{2004\times2006+2005}=\frac{2006\times\left(2004+1\right)-1}{2004\times2006+2005}=\frac{2006\times2004+2006\times1-1}{2004\times2006+2005}=\frac{2006\times2004+2005}{2006\times2004+2005}=1\)

\(\frac{2006\times2005-1}{2004\times2006+2005}=\frac{2006\times\left(2004+1\right)-1}{2004\times2006+2005}=\frac{2004\times2006+2006\times1-1}{2004\times2006+2005}\)

\(=\frac{2004\times2006+2005}{2004\times2006+2005}=1\)

\(\frac{2006x2005-1}{2004x2006+2005}\)

\(=\frac{2006x\left(2004+1\right)-1}{2004x2006+2005}\)

\(=\frac{2006x2004+2006-1}{2004x2006+2005}\)

\(=\frac{2006x2004+2005}{2004x2006+2005}\)

\(=1\)

2006 x 2005 - 1/2004 x 2006 + 2005

= 2006 x ( 2004 + 1 ) - 1/2004 x 2006 + 2005

= 2006 x 2004 + 2006 x 2005/2004 x 2006 + 2005

= 2006 x 2004 + 2005 / 2004 x 2006 + 2005

dung roi ban cam on ban nhe

ừ ko có gì

\(\frac{2006.2005-1}{2004.2006+2005}\)

\(=\frac{2006\left(2004+1\right)-1}{2004.2006+2005}\)

\(=\frac{2006.2004+2006-1}{2004.2006-2005}\)

\(=\frac{2006.2004+2005}{2004.2006+2005}=1\)

nha

bn Nguyễn Minh Anh bn nói rõ hơn đc ko?

giải chi tiết r đó bn

a, 27.5 x 5.43 + 4.57 x 27.5

= 27.5 x ( 5.43 + 4.57 )

= 27.5 x 10

= 275

c,\(\frac{2006x2005-1}{2004x2006+2005}\)

= \(\frac{2006x\left(2004+1\right)-1}{2004x2006+2005}\)

= \(\frac{2006x2004+2006-1}{2004x2006+2005}\)

= \(\frac{2006x2004+2005}{2004x2006+2005}\)

= 1.

Mình chỉ biết từng nấy thôi.

11

a , x+6=49-3-13

x+6=a

x=a-6

x=n

b,231-(x-6)=n

x-6=231-n

x-6=a

x=a+6

x=m

B1:

a)49-3.(x+6)=13

3.(x+6)=49-13

3.(x+6)=36

x+6=36/3

x+6=12

x=12-6

x=6

Ta chỉ việc tách ra thôi VD ta thấy L

           2006x2005 = 2006x2004+2006x 1

Vây ta sẽ có cách làm như sau :
                \(\frac{2006\cdot2005-1}{2004\cdot2006+2005}\)

             \(=\frac{2006\cdot2004+2006\cdot1-1}{2004\cdot2006+2005}\)

               \(=\frac{2006\cdot2004+2006-1}{2006\cdot2004+2005}\)

                \(=\frac{2006\cdot2004+2005}{2004\cdot2006+2005}=1\)

\(\frac{2006\cdot2005-1}{2004\cdot2006+2005}=\frac{2006\cdot\left(2004+1\right)}{2004\cdot2006+2005}=\frac{2006\cdot2004+2006\cdot1-1}{2004\cdot2006+2005}=\frac{2006\cdot2004+2005}{2004\cdot2006+2005}=1\)

\(\frac{2006x2005-1}{2004x2006+2005}=\frac{2006x\left(2004+1\right)-1}{2004x2006+2005}\)

\(=\frac{2006x2004+2006-1}{2004x2006+2005}\)

\(=\frac{2006x2004+2005}{2004x2006+2005}\)

\(=1\)

Giải như mình là chuẩn rồi đó :)