A=988 x 988

B=986 x 990

suy ra A=988 x (988+2)

B=(986+2) x 990 

Â=988 x 988 +988 x 2

B=986 x 2+986 x990

Vậy suy ra tích A> B

tick nha Bảo Anh

A = \(\frac{976}{987}\) + \(\frac{987}{988}\) = \(1,987842971\)

B = \(\frac{986+987}{987+988}\)= \(\frac{1973}{1975}\) = \(0,9989873418\)

Mà \(1,987842971\)> \(0,9989873418\)

Nên: A > B

Ta có: \(\frac{986}{987}>\frac{986}{987+988}\)

\(\frac{987}{988}>\frac{987}{987+988}\)

\(\Rightarrow\frac{976}{987}+\frac{987}{988}>\frac{986+987}{987+988}\)

=> A > B

\(1020+Xx\frac{1}{3}=\frac{4}{5}+1020\)

\(=1020+Xx\frac{1}{3}=\frac{5104}{5}\)

\(=Xx\frac{1}{3}=\frac{5104}{5}-1020\)

\(=Xx\frac{1}{3}=\frac{4}{5}\)

\(=\frac{4}{5}:\frac{1}{3}\)

\(=\frac{12}{5}\)

\(1020+x.\frac{1}{3}=\frac{4}{5}+1020\)

\(1020+x.\frac{1}{3}=\frac{5104}{5}\)

\(x.\frac{1}{3}=\frac{5104}{5}-1020\)

\(x.\frac{1}{3}=\frac{4}{5}\)

\(x=\frac{4}{5}:\frac{1}{3}\)

\(x=\frac{12}{5}\)

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\(1020+x\cdot\frac{1}{3}=\frac{4}{5}+1020\)

\(1020+x\cdot\frac{1}{3}=\frac{5104}{5}\)

\(x\cdot\frac{1}{3}=\frac{5104}{5}-1020\)

\(x\cdot\frac{1}{3}=\frac{4}{5}\)

\(x=\frac{4}{5}\div\frac{1}{3}\)

\(x=\frac{12}{5}\)

√988 = √9,88.√100 = 3,143.10 = 31,43

ĐÁP ÁN :1075

87+988=1075

đúng thì k sai thì thôi nha bạn

SAI PHẢI = 1085 MỚI ĐÚNG

a) √911 = √9,11.√100 = 3,018.10 = 30,18

b) √988 = √9,88.√100 = 3,143.10 = 31,43

899 - 988 = -89

677 - 766 = -89

899-988

=-89

677-766

=-89

a)899-988

=--89

b)677-766

=-89