Phan tich da thuc thanh nhsn tu x^-y^3+3x^3+3x+1
phan tich da thuc thanh nhan tu 1-3x-x^3+3x^2
\(1-3x-x^3+3x^2\)\(=\left(1-x^3\right)+\left(3x^2-3x\right)\)
\(=\left(1-x\right)\left(x^2+x+1\right)+3x\left(x-1\right)\)
\(=\left(x-1\right)\left(3x-x^2-x-1\right)=\left(x-1\right)\left(2x-x^2-1\right)\)
phan tich da thuc thanh nhan tu :
2x(x-1)-3x+3
2x(x-1)-3x+3
=2x(x-1)-(3x-3)
=2x(x-1)-3(x-1)
=(x-1)(2x-3)
phan tich da thuc thanh nhan tu
x3-3x2-3x+1
x3-3x2-3x+1=x3+1-3x2-3x
=(x+1)(x2-x+1)-3x(x+1)
=(x+1)(x2-x+1-3x)
=(x+1)(x2-4x+1)
Phan tich da thuc thanh nhan tu:
x^3 - x + 3x^2y + 3xy^2 + y^3 - y
x^2 + 5x - 6
x^3 - x + 3x^2y + 3xy^2 + y^3 - y
=x3+y3+3x2y+3xy2-x-y
=(x+y)(x2-xy+y2)+3xy(x+y)-(x+y)
=(x+y)(x2-xy+y2+3xy-1)
=(x+y)(x2+2xy+y2-1)
=(x+y)[(x+y)2-1]
=(x+y)(x+y-1)(x+y+1)
x^2 + 5x - 6
=x2-x+6x-6
=x.(x-1)+6.(x-1)
=(x-1)(x+6)
phan tich da thuc sau thanh nhan tu:
a) (3x-2)(4x-3)-(2-3x)(x-1)-2(3x-2)(x+1)
b) x^2(y-z)+y^2(z-x)+z^2(x-y)
phan tich da thuc thanh nhan tu :x^5+2x^4+3x^3+2x^2+2x+1
x^5+2x^4+2x^3+2x^2+2x+1
=(x^5+x^4)+(x^4+x^3)+(x^3+x^2)+(x^2+x)+(x+1)
=x^4(x+1)+x^3(x+1)+x^2(x+1)+x(x+1)+(x+1)
=(x+1)(x^4+x^3+x^2+x+1)
tim x bang cach phan tich da thuc thanh nhan tu
x3-3x2+3x-1=0
\(x^3-3x^2+3x-1\) =0
=>\(\left(x-1\right)^3\)=0
=>x-1=0
=>x=1
vậy x =1
\(x^3-3x^2+3x-1=0\)
\(\Leftrightarrow\left(x-1\right)^3\)
\(\Leftrightarrow x-1=0\)
\(\Leftrightarrow x=1\)
phan tich da thuc x^3+3x-4 thanh nhan tu
x^3 + 3x -4 = x^3 - 1 + 3x - 3 = (x-1)(x^2-x+1) + 3(x-1) = (x-1)(x^2-x+1+3) = (x-1)(x^2-x+4)
nhớ cho mik nha
minh h cho 1 cai nhung o cho x^3-1 phai bang (x-1)(x^2+x+1)
phan tich da thuc thanh phan tu x^8+3x^4+1
ứng dụng t/c thêm bớt nà bạn