tìm x : (4x+1)(16x^2-4x+1)-16x(4x^2-5)=17
Tìm x: 4x+1.(16x2-4x+1)-16x.(x2-5)=17
Tìm x: 4x+1.(16x2-4x+1)-16x.(x2-5)=17
(4x+1)(1-4x+16x^2) - 16x(4x^2-5) = 17 tim x
\(\left(4x+1\right)\left(1-4x+16x^2\right)-16x\left(4x^2-5\right)=17\)
\(\Leftrightarrow4x-16x^2+64x^2+1-4x+16x^2-64x^2+80x-17=0\)
\(\Leftrightarrow\left(-16x^2+16x^2\right)+\left(64x^2-64x^2\right)+\left(4x-4x\right)+80x+1-17=0\)
\(\Leftrightarrow80x=16\)
\(\Leftrightarrow x=\dfrac{1}{5}\)
Tìm x:
( 4x + 1 )( 16x^2 - 4x + 1 ) - 16x ( 4x^2 - 5 ) = 17
Tính giá trị biểu thức:
p=(x+1)(x^2-x+1)+x-(x-1)(x^2+x+1)+2010; x=-2010)
q=16x(4x^2-5)-(4x+1)(16x^2-4x+1); x=1/5
\(p=\left(x+1\right)\left(x^2-x+1\right)+x-\left(x-1\right)\left(x^2+x+1\right)+2010\)\(=\left(x^3+1\right)+x-\left(x^3-1\right)+2010=x^3+1+x-x^3+1+2010=x+2012\)Với \(x=-2010\Rightarrow p=-2010+2012=2\)
\(q=16x\left(4x^2-5\right)-\left(4x+1\right)\left(16x^2-4x+1\right)=64x^3-80x-64x^3-1=-80x-1\)Với \(x=\dfrac{1}{5}\Rightarrow q=-80.\dfrac{1}{5}-1=-17\)
(4x+1)(16x^2-4x+1)-16x (4x^2-5)=17
16x (4x²-5) + 17 = (4x + 1) (16x²-4x + 1)
64x³-80x + 17 = 64x³ + 1
64x³-64x³ = 1-17-80x
-80x = -16
x = -16 / ( -80)
x = 0,2
C) 5x-(4-2x+x^2)(x+2)+x (x-1)(x+1)=0
D) (4x+1)(16x^2-4x+1)-16x (4x^2-5)=17
giải
5x-(4-2x+x^2)(x+2)+x(x-1)(x+1)=0
5x-(4x+8-2x^2-4x+x^3+2x^2)+x(x^2-1)=0
5x-4x-8+2x^2+4x-x^3-2x^2+x^3-1x=0
(5x-4x+4x-1x)+(-8)+(2x^2-2x^2)+(-x^3+x^3)=0
4x+(-8)=0
4x=0+8
4x=8
x=8:4
x=2
D)(4x+1)(16x^2-4x+1)-16x(4x^2-5)=17
64x^3-16x^2+4x+16x^2-4x+1-64x^3+80x=17
80x+1=17
80x=17-1
80x=16
x=1/5
\(5x-\left(4-2x+x^2\right)\left(x+2\right)+x\left(x-1\right)\left(x+1\right)=0\)
\(\Rightarrow5x-\left(4x-2x^2+x^3+8-4x+2x^2\right)+\left(x^2-x\right)\left(x+1\right)=0\)
\(\Rightarrow5x-\left(4x-2x^2+x^3+8-4x+2x^2\right)+\left(x^3+x-x^2-x\right)=0\)
\(\Rightarrow5x-4x+2x^2-x^3-8+4x-2x^2+x^3+x-x^2-x=0\)
\(\Rightarrow4x-8=0\Rightarrow4x=8\Rightarrow x=2\)
Tìm x :
a) ( x - 2 )^3 + 6( x + 1 )^2 - x ^3 = -12
b) ( 4x + 1 )( \(16x^2\) - 4x + 1 ) - 16x ( \(4x^2\) - 5 ) = 17
b) \(\left(4x+1\right)\left(16x^2-4x+1\right)-16x\left(4x^2-5\right)=17\)
\(\Leftrightarrow64x^3+1-64x^3+80x=17\)
\(\Leftrightarrow80x=16\)
\(\Leftrightarrow x=\frac{1}{5}\)
rút gọn (a^2-1)(a^2-a+1)(a^2+a+1)
tìm x : (4x+1)(16^2-4x+1)-16x(4x^2-5)=17
rút gọn (a^2-1)(a^2-a+1)(a^2+a+1)
tìm x : (4x+1)(16^2-4x+1)-16x(4x^2-5)=17
Giúp tui với!!