rut gon
N = √3 - 2√2 - √6 + 4√2 lèm hộ tui vơi
Những câu hỏi liên quan
4x^4-20x^3+13x^2+30X+9chia cho
(4x^2-1)^2
rut gon ho tui
rut gon A= 1*4/2*3+2*5/2*4+3*6/4*5+...+98*101/99*100
rut gon 5^2.6^11.16^2 6^2.12^6.15^2/2.6^12.10^4-81^2.960^3
Please giup minh nha
Rut gon
c,6^2 . 6^4 -4^3 (3^6 -1)
6^2.6^4-4^3(3^6-1)
=2^2.3^2.2^4.3^4-2^6.3^6+2^6
=2^6.3^6-2^6.3^6+2^6
=0+2^6
=64
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\(6^2.6^4-4^3\left(3^6-1\right)=6^2.6^4-2^6\left(3^6-1\right)\)
\(=6^2.6^4-6^6+2^6=6^6-6^6+2^6=2^6=64\)
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6^2 . 6^4 - 4^3 ( 3^6 - 1)
= (2.3)^2 . (2.3)^4 - (2^2)^3 ( 3^6 -1)
= 2^2 . 3^2 . 2^4 . 3^4 - 2^6 ( 3^6 - 1)
= 2^6 . 3^6 - 2^6 . 3^6 - 2^6 .1
= 0 - 2^6
= - 64
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Rut gon phan so sau:
A=5^2 x 6^11 x 16^2+6^2x12^6x15^2/2x6^12x10^4-81^2 x 960^3
rut gon 5^2.6^11.16^2+6^2.12^6.15^2/2.6^12.10^4-81^2.960^3
Ta có:
\(\frac{5^2.6^{11}.16^2.6^2.12^6.15^2}{2.6^{12}.10^4-81^2.960^3}\) = \(\frac{5^2.6^{11}.6^2.6^2.6^6.2^6.3^2.5^2}{2.2^{12}.3^{12}.2^4.5^4-3^8.2^{15}.3^3}\) = \(\frac{5^6.6^{21}.2^8.3^2}{2^{17}.3^{12}.5^4-3^{11}.2^{15}}\) = \(\frac{5^6.3^{23}.2^{29}}{3^{11}.2^{15}.\left(2^2.3.5^4-1\right)}\)
= \(\frac{5^6.3^{13}.2^{14}}{2^2.3.5^4-1}\)
Nhớ cho mk nha bạn!
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rut gon
x^7+x^6+x^5+x^4+x^3+x^2+x+1/x^2-1
cho ps a\b rut gon 3\5 neu them 6 vao mau giu nguyen tu ta duoc 1 ps moi rut gon =2\3 tim ps a\b
A= [3/2-(x^4-x^4+1/x^2+1)*x^2-x(4*x-1)-4/x^7+6*x^4-x-6]/x^3+29*x+78/3*x^2+12*x-36.rut gon