y+y:0.5+y:0.25=y:0.125=125

=y+yx2+yx4+yx8=125

=yx15=125

y=125:15

y=25/3

Ta có:

\(\left(x-0,5\right)^2+\left(y+0,25\right)^2=0\)

\(\Leftrightarrow x-0,5=y+0,25=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=0,5\\y=-0,25\end{matrix}\right.\)

`y : 0,125 + y : 0,25 - y : 0, 5 = 1,4`

`yxx8+yxx4-yxx2=1,4`

`yxx(8+4-2)=1,4`

`yxx10=1,4`

`y=1,4:10`

`y=0,14`

Vậy..

`@An`

y:(0,125+0,25-0,5)=1,4

y:0,125=1,4

y=1,4x0,125

y=0,175

\(\left(x-0,5\right)^2+\left(y+0,25\right)^2=0\)

Do \(\hept{\begin{cases}\left(x-0,5\right)^2\ge0\\\left(y+0,25\right)^2\ge0\end{cases}\Rightarrow VT\ge0}\)

Dấu "=" xảy ra \(\Leftrightarrow\hept{\begin{cases}x-0,5=0\\y+0,25=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=0,5\\y=-0,25\end{cases}}}\)

Vậy \(\hept{\begin{cases}x=0,5\\y=-0,25\end{cases}}\)

vì \(\hept{\begin{cases}\left(x-0,5\right)^2\ge0\\\left(y+0,25\right)\ge0\end{cases}}\)

mà \(\left(x-0,25\right)^2+\left(y-0,25\right)^2=0\)

\(\Rightarrow\hept{\begin{cases}\left(x+0,5\right)^2=0\\\left(y-0,25\right)^2=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x+0,5=0\\y-0,25=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=-0,5\\y=0,25\end{cases}}\)

mk nhầm dấu

\(\Leftrightarrow\) y\(\times\)1/4 + y \(\times\)1/2 + y \(\times\)1/4 + y= 20
\(\Leftrightarrow\)y\(\times\) ( 1/4+1/2+1/4+1)=20
\(\Leftrightarrow\) y\(\times\)2=20
\(\Leftrightarrow\) y=10

bài lớp mấy vậy nhìn nó khó khó

Câu 1 ko hiểu đề bài lắm

\(2.Y\times\left(2+0,5\right)=6,25\)

\(Y\times2,5=6,25\)

\(Y=6,25:2,5\)

\(Y=2,5\)

\(3.Y\times6=99,75:4,75\)

\(Y\times6=21\)

\(Y=21:6\)

\(Y=3,5\)