2¹⁰⁵ = 2^3.35 = (2³)³⁵ = 8³⁵ > 5³⁵ (vì 8 > 5) => 2¹⁰⁵ > 5³⁵

a) 35 : 5 và (35 x 4) : (5 x 4)   

35:5= 7

(35 x 4) : (5 x 4) = 140 : 20 =7

=> 35 : 5  =  (35 x 4) : (5 x 4)            

b) 105 : 15 và (105 : 5) : (15 : 5)

105:15 =7

(105 : 5) : (15 : 5)= 7 : 3= 2 (dư 1)

=>105 : 15 > (105 : 5) : (15 : 5)

a) 1763 + (–2) = 1763 – 2 = 1761.

Vậy 1763 + (–2) < 1763.

b) (–105) + 5 = –(105 – 5) = –100.

So sánh –100 và –105:

|–100| = 100, |–105| = 105. Mà 100 < 105 nên (–100) > (–105).

Vậy (–105) + 5 > (–105).

c) (–29) + (–11) = – (29 + 11) = –40.

So sánh –40 và –29:

|–40| = 40; |–29| = 29. Mà 40 > 29 nên (–40) < (–29).

Vậy (–29) + (–11) < (–29).

\(\frac{3}{111}< \frac{4}{111}< \frac{4}{103}\)

\(\frac{91}{93}=\frac{93-2}{93}=1-\frac{2}{93}\)

\(\frac{105}{107}=\frac{107-2}{107}=1-\frac{2}{107}\)

\(\Rightarrow\frac{91}{93}< \frac{105}{107}\)

\(\frac{71}{35}=\frac{70+1}{35}=2+\frac{1}{35}=2+\frac{2}{70}\)

\(\frac{127}{53}=\frac{106+11}{53}=2+\frac{11}{53}\)

\(\frac{2}{70}< \frac{2}{53}< \frac{11}{53}\Rightarrow\frac{71}{35}< \frac{127}{53}\)

c1;=35

c2;=35

35=35

a) <

b) >

c) <

a) 2018 + (– 3)  <  2018

          b) (– 105) + 5 > (– 105)

          c) (– 59) + (– 10) < (–59)

4^40=[2^2]^20=2^40

vậy 2^81>4^40

25^10=[5^2]^10=5^20=5^5.5^15

105^5=21^5.5^5

vì 5^5.5^5<21^5.5^5 nên 25^10<105^5

Ta có

kết quả là:

2^81 > 4^40

105^5 > 25^5

nha bn