Bài 1 :
a) 1 : \(\frac{1}{10}\)= ............ 1m gấp ............. lần \(\frac{1}{10}\)m
b) \(\frac{1}{10}\): \(\frac{1}{100}\)= ............. \(\frac{1}{10}\)m gấp .............. lần \(\frac{1}{100}\)m
c) \(\frac{1}{100}\): \(\frac{1}{1000}\)= ............. \(\frac{1}{100}\)m gấp .............. lần \(\frac{1}{1000}\)m
Giúp em bài toán này với em đang gấp
\(G=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+....+\frac{1}{3^{100}}\)
\(I=\frac{1}{2}+\frac{1}{14}+\frac{1}{35}+\frac{1}{65}+\frac{1}{104}+\frac{1}{152}\)
\(D=\frac{10}{100}+\frac{10}{150}+\frac{10}{210}+....+\frac{10}{1200}\)
\(G=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+..............+\frac{1}{3^{100}}\)
\(3G=1+\frac{1}{3}+\frac{1}{3^2}+...............+\frac{1}{3^{99}}\)
\(3G-G=\left(1+\frac{1}{3}+\frac{1}{3^2}+..........+\frac{1}{3^{99}}\right)-\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...............+\frac{1}{3^{100}}\right)\)
\(2G=1-\frac{1}{3^{100}}\)
\(\Rightarrow G=\left(1-\frac{1}{3^{100}}\right):2\)
1 gấp bao nhiêu lần \(\frac{1}{10}\)
\(\frac{1}{10}\)gấp bao nhiên lần \(\frac{1}{100}\)
\(\frac{1}{100}\)gấp bao nhiêu lần \(\frac{1}{1000}\)
ai nhanh mik tick
\(1:\frac{1}{10}=1.\frac{10}{1}=\frac{10}{1}=10\)
\(\frac{1}{10}:\frac{1}{100}=\frac{1}{10}.\frac{100}{1}=\frac{100}{10}=10\)
\(\frac{1}{100}:\frac{1}{1000}=\frac{1}{100}.\frac{1000}{1}=\frac{1000}{100}=10\)
\(1\)gap 10 lan \(\frac{1}{10}\)
\(\frac{1}{10}\)gap 10 lan \(\frac{1}{100}\)
\(\frac{1}{100}\)gap 10 lan \(\frac{1}{1000}\)
a)1 gấp bao nhiêu lần \(\frac{1}{10}\)?
b)\(\frac{1}{10}\)gấp bao nhiêu lần \(\frac{1}{100}\)?
c)\(\frac{1}{100}\)gấp bao nhiêu lần \(\frac{1}{1000}\)?
Gửi
TNs tao cuồng:c/m \(B=\frac{1}{2}+\frac{1}{2^2}+\frac{3}{2^3}+....+\frac{100}{2^{100}}<2\)Ta có:\(2B=1+\frac{1}{2}+\frac{3}{2^2}+....+\frac{100}{2^{99}}\)\(\Rightarrow2B-B=B=1+\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+....+\frac{1}{2^{99}}\right)-\frac{100}{2^{100}}\)(*)c/m \(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{99}}<1\)Đặt \(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+....+\frac{1}{2^{99}}\)\(\Rightarrow2A=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{98}}\)\(\Rightarrow2A-A=\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{98}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+....+\frac{1}{2^{99}}\right)\)\(\Rightarrow A=1-\frac{1}{2^{99}}<1\)do đó \(B=1+A-\frac{100}{2^{100}}\Rightarrow B<2-\frac{100}{2^{100}}<2\left(đpcm\right)\)
1 gấp bao nhiêu lần \(\frac{1}{10}\)? \(\frac{1}{10}\)gấp bao nhiêu lần \(\frac{1}{100}\)?
\(\frac{1}{100}\)gấp bao nhiêu lần \(\frac{1}{1000}\)?
1 gấp 10 1/10
1/10 gấp 1/100
1/100 gấp 10 lần 1/1000 nha bạn
cái nào cx gấp 10 lần
1 gấp 10 lần \(\frac{1}{10}\)
\(\frac{1}{100}\) gấp 10 lần
\(\frac{1}{10}\) gấp 10 lần \(\frac{1}{100}\)
\(A=(\frac{1}{7^2}+\frac{1}{7^4}+\frac{1}{7^6}+...+\frac{1}{7^{100}})\div(1-\frac{1}{7^{100}})\)Mình đag cần rất gấp . Mong mn giúp mình với
Ai làm nhanh mình tick
Đặt S = \(\frac{1}{7^2}+\frac{1}{7^4}+\frac{1}{7^6}+...+\frac{1}{7^{100}}\)
=> 72S = 49S = \(1+\frac{1}{7^2}+\frac{1}{7^4}+...+\frac{1}{7^{98}}\)
=> 49S - S = \(\left(1+\frac{1}{7^2}+\frac{1}{7^4}+...+\frac{1}{7^{98}}\right)-\left(\frac{1}{7^2}+\frac{1}{7^4}+\frac{1}{7^6}+...+\frac{1}{7^{100}}\right)\)
=> 48S = \(1-\frac{1}{7^{100}}\)
=> \(S=\frac{1-\frac{1}{7^{100}}}{48}\)
Khi đó A = \(\left(\frac{1-\frac{1}{7^{100}}}{48}\right):\left(1-\frac{1}{7^{100}}\right)=\frac{1}{48}\)
Tính : \(\left(92-\frac{1}{9}-\frac{2}{10}-\frac{3}{11}-...-\frac{92}{100}\right)\) \(\div\left(\frac{1}{45}+\frac{1}{50}+\frac{1}{55}+...+\frac{1}{500}\right)\)
\(A\)\(=\)\((1-\frac{1}{6^{100}})\div(\frac{1}{6}+\frac{1}{6^2}+\frac{1}{6^3}+...+\frac{1}{6^{100}})\)Mình đag cần rất gấp . Các bạn giúp mình với
Đặt S = \(\frac{1}{6}+\frac{1}{6^2}+\frac{1}{6^3}+...+\frac{1}{6^{100}}\)
=> 6S = \(1+\frac{1}{6}+\frac{1}{6^2}+...+\frac{1}{6^{99}}\)
=> 6S - S = \(\left(1+\frac{1}{6}+\frac{1}{6^2}+\frac{1}{6^3}+...+\frac{1}{6^{99}}\right)-\left(\frac{1}{6}+\frac{1}{6^2}+\frac{1}{6^3}+...+\frac{1}{6^{100}}\right)\)
=> \(5S=1-\frac{1}{6^{100}}\)
=> \(S=\frac{1-\frac{1}{6^{100}}}{5}\)
Khi đó A = \(\left(1-\frac{1}{6^{100}}\right):\left(\frac{1-\frac{1}{6^{100}}}{5}\right)=5\)
