Tính : \(\frac{\left[\left(125^3\right)\cdot7^5-\frac{\left(175^5\right)}{5}\right]}{2004^{2005}}\)
Ai nhanh nhất mình sẽ tick
Tính giá trị của các biểu thức sau 1) \(A=1+2+2^2+...+2^{2015}\) 2) \(B=\left(\dfrac{1}{4}-1\right)\cdot\left(\dfrac{1}{9}-1\right)\cdot\left(\dfrac{1}{16}-1\right)\cdot\cdot\cdot\cdot\cdot\left(\dfrac{1}{400}-1\right)\) 3) \(C=\left(\dfrac{1}{4\cdot9}+\dfrac{1}{9\cdot14}+\dfrac{1}{14\cdot19}+...+\dfrac{1}{44\cdot49}\right)\cdot\dfrac{1-3-5-7-...-49}{89}\) 4) \(D=\dfrac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\dfrac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\) 5) \(E=\dfrac{\dfrac{1}{2003}+\dfrac{1}{2004}-\dfrac{1}{2005}}{\dfrac{5}{2003}+\dfrac{5}{2004}-\dfrac{5}{2005}}-\dfrac{\dfrac{2}{2002}+\dfrac{2}{2003}-\dfrac{2}{2004}}{\dfrac{3}{2002}+\dfrac{3}{2003}-\dfrac{3}{2004}}\) 6) Cho 13+23+...+103=3025 Tính S= 23+43+63+...+203
Tính A:\(\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
Cho \(\frac{a}{b}=\frac{c}{d}\)Chứng tỏ
\(\frac{\left(a^{2004}+b^{2004}\right)^5}{\left(c^{2004}+d^{2004}\right)^5}=\left(\frac{a^{2005}+b^{2005}}{c^{2005}-d^{2005}}\right)^{2004}\)
Tính và rút gọn các bài toán nâng cao sau
1.Tính
\(A=\left(1-\frac{1}{5}\right).\left(1-\frac{2}{5}\right).\left(1-\frac{3}{5}\right)...\left(1-\frac{9}{5}\right)\)
2 rút gọn
\(B=\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{50}\right)\)
Ai nhanh ai đúng mk sẽ tick :) :D
1. Có 1 thừa số là \(1-\frac{5}{5}=0\) nên tích sẽ bằng 0
2.\(B=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.......\frac{49}{50}=\frac{1}{50}\)
thực hiện phép tính:
A = \(\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49}{\left(125\cdot7\right)^3+5^9\cdot14^3}^2\)
\(TínhA=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
\(B=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{56^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
TÍNH NHANH
\(\left(\frac{5}{13}-\frac{9}{14}\right)-\left(2+\frac{-21}{13}-\frac{5}{-14}\right)=?\)
Ai đúng nhất và sớm nhất mình tick nhé!
\(\left(\frac{5}{13}-\frac{9}{14}\right)-\left(2+-\frac{21}{13}-\frac{5}{-14}\right)\)
\(=-\frac{47}{182}-\frac{135}{182}\)
\(=-1\)
tíc mình nha
(5/13 −9/14 )−(2+−21/13 −5/−14 )
=−47/182 −135/182
=−1
\(\left(\frac{5}{13}-\frac{9}{14}\right)-\left(2+\frac{-21}{13}-\frac{5}{-14}\right)\)
\(=\frac{5}{13}-\frac{9}{14}-2+\frac{21}{13}-\frac{5}{14}\)
\(=\left(\frac{5}{13}+\frac{21}{13}\right)+\left(-\frac{9}{14}+\frac{-5}{14}\right)-2\)
\(=2-1-2=-1\)
tính A=\(y=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
thankS trc nhé =))~~~~