Ta có: \(S=\left(5-\frac{2}{3}+\frac{3}{2}\right)-\left(7-\frac{5}{4}-\frac{1}{2}\right)-\left(1-\frac{4}{3}+\frac{2}{5}\right).\)

\(\Rightarrow S=\left(\frac{13}{3}+\frac{3}{2}\right)-\left(\frac{23}{4}-\frac{1}{2}\right)-\left(\frac{-1}{3}+\frac{2}{5}\right)\)

\(\Rightarrow S=\frac{35}{6}-\frac{21}{4}-\frac{1}{15}\)

\(\Rightarrow S=\frac{7}{12}-\frac{1}{15}=\frac{31}{60}\)

Vậy \(S=\frac{31}{60}\)

ta có; 

x/5 - 5/2=-31

=>x/5= -31+5/2=-28 1/2

=> x = -57/2* 5

=> x=-142 1/2

ko hiểu cho lắm

Sai rồi nhé Nguyễn Hồng Nhung!

\(2\left(\frac{1}{2}\right)^a< \frac{1}{4^{20}}\)

\(\frac{1}{2^{a-1}}< \frac{1}{2^{40}}\)

\(\Rightarrow a-1>40\)

\(Min_a=42\)

Vậy...

\(\left|x+1\right|,\left|x-2\right|,\left|x+3\right|\ge0\)

\(6\ge0\Rightarrow x\ge0\)

\(\left|x+1\right|+\left|x-2\right|+\left|x+3\right|=6\)

\(\Rightarrow\left(x+1\right)+\left(x-2\right)+\left(x+3\right)=6\)

\(\Rightarrow\left(x+x+x\right)+\left(1-2+3\right)=6\)

\(\Rightarrow3x+2=6\)

\(\Rightarrow3x=6-2\)

\(\Rightarrow3x=4\)

\(\Rightarrow x=\frac{4}{3}\)

( x + 4/3 ) * 7/4 + 7/6 = 5

( x + 4/3 ) *  7/4             = 5 - 7/6

x + 4/3 * 7/4                  = 23/6

x  + 7/3                         = 23/6

x                                   = 23/6 - 7/3

x                                   = 3/2

Chúc bạn hok tốt !

Cảm ơn nhiều

( x + 4/3 ) * 7/4 + 7/6 = 5

( x + 4/3 ) *  7/4             = 5 - 7/6

x + 4/3 * 7/4                  = 23/6

x  + 7/3                         = 23/6

x                                   = 23/6 - 7/3

x                                   = 3/2