Tk mình đi mọi người mình bị âm nè!

ai tk mình mình tk lại cho!!!

4/5 * ( 3/7 + 4/5 - 4/14 )

rồi bạn tính tiếp đi nhé !

Nếu không thính thì bạn ni đổi đi nhé !

4/5* (3/7+6/7-4/14) = 4/5 * (9/7 - 4/14) = 4/5 *(18/14 -4/14) = 4/5 * 1= 4/5

`4/5 xx 3/7 + 4/5 xx 6/7 - 4/5 xx 4/14`

`= 4/5 xx ( 3/7 + 6/7-4/14)`

`= 4/5 xx 1`

`= 4/5`

= 4/5 x ( 3/7 + 6/7 - 4/14 )

= 4/5 x ( 3/7 + 6/7 - 2/7 )

= 4/5 x 7/7

= 4/5

\(\dfrac{4}{5}\times\dfrac{3}{7}\times\dfrac{4}{5}\times\dfrac{6}{7}\times\dfrac{4}{14}=\dfrac{4}{5}\times\dfrac{3}{7}+\dfrac{4}{5}\times\dfrac{6}{7}-\dfrac{4}{5}\times\dfrac{2}{7}=\dfrac{4}{5}\times\left(\dfrac{6}{7}+\dfrac{3}{7}-\dfrac{2}{7}\right)=\dfrac{4}{5}\)

=4/5 * (3/7+6/7-4/14)

=4/5*(6/14+12/14-4/14)

=4/5*12/14

=48/70

nha ban

8/1225

\(\frac{288}{1225}-\frac{8}{35}=\frac{8}{1225}\) nha bạn k mình nha

= 4/5 x ( 3/7 + 6/7 - 4/14 )

= 4/5 x ( 3/7 + 6/7 - 2/7 )

= 4/5 x 7/7

= 4/5

4/5 x 3/7 + 4/5 x 6/7 - 4/5 x 4/14

= 4/5 x ( 3/7 + 6/7 - 4/14)

= 4/5 x 1

= 4/5

4/5

1,

a, \(x\)x 124= 4829-365

 \(x\)x 124 = 4464

\(x\)= 4464 :124

\(x\)= 36.

b,\(x\)x 137 = 25 x 3 

   \(x\)x 137 = 75

\(x\)= \(\frac{75}{137}\)

2,

\(\frac{4}{5}\)x\(\frac{3}{7}+\frac{4}{5}\)x\(\frac{6}{7}-\frac{4}{5}\)x\(\frac{4}{10}\)

=\(\frac{4}{5}\)x\(\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{10}\right)\)=\(\frac{4}{5}\)x\(\frac{31}{35}\)\(\frac{124}{175}\)

\(\text{Bài }1\text{ : Tìm }x\text{ : }\)

\(a,\text{ }x\text{ x }124=4829-365\)

     \(x\text{ x }124=4464\)

     \(x=4464\text{ : }124\)

     \(x=36\)

\(b,\text{ }x\text{ x }137=25\text{ x }3\)

     \(x\text{ x }137=75\)

     \(x=75\text{ : }137\)

     \(x=\frac{75}{137}\)

\(\text{Bài }2\text{ : Tính bằng cách thuận tiện nhất : }\)

      \(\frac{4}{5}\text{ x }\frac{3}{7}+\frac{4}{5}\text{ x }\frac{6}{7}-\frac{4}{5}\text{ x }\frac{4}{10}\)

\(=\frac{4}{5}\text{ x }\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{10}\right)\)

\(=\frac{4}{5}\text{ x }\left(\frac{9}{7}-\frac{4}{10}\right)\)

\(=\frac{4}{5}\text{ x }\frac{31}{35}\)

\(=\frac{124}{175}\)

mẹ ơi dễ thế để con giải cho:

Bài 1:

a. X x 124=4829-365

    X x 124         =4464

    X                  = 4464:124

    X                 =36

b tương tự như câu a

Bài 2:

\(\frac{4}{5}\)x \(\frac{3}{7}\)+\(\frac{4}{5}\)x \(\frac{6}{7}\)-\(\frac{4}{5}\)x \(\frac{4}{10}\)

=\(\frac{4}{5}\)x(\(\frac{6}{7}\)+ \(\frac{3}{7}\)-\(\frac{4}{10}\))

= \(\frac{4}{5}\)x \(\frac{31}{35}\)

\(\frac{124}{175}\)

a) 145 + 86 + 14 + 55 = ( 145 + 55 ) + (86 + 14 )

= 200 + 100

= 300

b) 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = ( 1+9 +2 + 8) + ( 3 + 7 + 4 + 6 ) + 5

= 20 + 20 + 5

= 45

A  =\(\frac{2}{5}\times\frac{4}{7}+\frac{3}{5}\times\frac{4}{7}\)  B = \(\frac{17}{13}\times\frac{12}{17}-\frac{4}{13}\times\frac{12}{17}\)   C = \(\frac{9}{14}:\frac{6}{7}+\frac{5}{14}:\frac{6}{7}\)  D =\(\frac{9}{12}:\frac{7}{9}\times\frac{12}{19}\)

=  \(\frac{4}{7}\times\left(\frac{2}{5}+\frac{3}{5}\right)\)              =\(\left(\frac{17}{13}-\frac{4}{13}\right)\times\frac{12}{17}\)                = \((\frac{9}{14}+\frac{5}{14}):\frac{6}{7}\)         = \(\frac{9}{12}\times\frac{9}{7}\times\frac{12}{19}\)

=\(\frac{4}{7}\times1\)                                     = \(1\times\frac{12}{17}\)                                       = \(1:\frac{6}{7}\)                               = \(\frac{9\times9\times12}{12\times7\times19}\)

=\(\frac{4}{7}\)                                              =  \(\frac{12}{17}\)                                                =\(\frac{7}{6}\)                                    = \(\frac{9\times9}{7\times19}=\frac{81}{133}\)

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