\(99^{20}< 9999^{10}\)

\(54^4< 21^{12}\)

\(71^5< 17^{20}\)

\(2^{30}+3^{20}+4^{30}>3\times24^{10}\)
 

\(\dfrac{20}{35}\text{=}\dfrac{4}{7}\)

\(\dfrac{5}{15}\text{=}\dfrac{1}{3}\)

\(\dfrac{12}{21}\text{=}\dfrac{4}{7}\)

\(\dfrac{8}{10}\text{=}\dfrac{4}{5}\)

\(\dfrac{20}{30}\text{=}\dfrac{2}{3}\)

\(\Rightarrow\left(\dfrac{20}{35}\text{=}\dfrac{12}{21}\text{=}\dfrac{4}{7}\right);\left(\dfrac{20}{30}\text{=}\dfrac{2}{3}\right).\)

4/7 = 12/21 = 20/35

HT

20/35=12/21=4/7
2/3=20/30
 

2-4+6-8+10-12+14-16+18-20+22

=(2+18)-(4+16)+(6+14)-(8+12)-(10+20)+22

=20-20+20-20-20+22

=22-20

=2

1999-2000+2999-3000+3999-4000+4999-5000+5999-1000

=(1999-1000)+(2999-2000)+(3999-3000)+(4999-4000)+(5999-5000)

=999x5

=4995

2-4+6-8+10-12+14-16+18-20+22                                                                                                                                                            =2+(6-4)+(10-8)+(14-12)+(18-16)+(22-20)                                                                                                                                                            = 2+2+2+2+2+2                                                                                                                                                             = 12

a=-31 phần 60

b=13 phần 4

c=-2

em mới có lớp 2

\(2x+1+\frac{1}{6}+1+\frac{1}{12}+..+1+\frac{1}{90}=10\)

=> 2x + 8 + \(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}=10\)

=> 2x + \(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}=10-8\)

\(2x+1-\frac{1}{10}=2\)

=> 2x + \(\frac{9}{10}=2\)

=> 2x          = 2 - 9/10

=>2x           = 11/10 

=> x              = 11/10 : 2

x                  =  11/20 

thang Tran ơi,2x+1-1/10 ở đâu vậy

Phải là 2x+1/2-1/10 chứ

mk giải cho nè nhớ tích nha

2x+7/6+13/12+21/20+31/30+43/42+57/56+73/72+91/90=10

2x+(1/6+1)+(1/12+1)+(1/20+1)+(1/30+1)+(1/42+1)+(1/56+1)+(1/72+1)+(1/90+1)=10

2x+(1+1+1+1+1+1+1+1)+(1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90)=10

2x+8+(1/2+3+1/3+4+1/4+5+1/5+6+1/6+7+1/7+8+1/8+9+1/9+10)=10

2x+8+(1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10)=10

2x+8+(1/2-1/10)=10

2x+8+2/5=10

2x=10-8-2/5

2x=1,6

x=1,6:2

x=0,8

Mk thấy đề bài hơi dư nên x mk tìm ra là số thập phân còn đổi lại ra phân số là 4/5

\(\dfrac{21}{36}-\left(-\dfrac{11}{30}\right)=\dfrac{7}{12}+\dfrac{11}{30}=\dfrac{7.5+11.2}{60}=\dfrac{57}{60}=\dfrac{19}{20}\\ ----\\\dfrac{-4}{8}+\left(-\dfrac{3}{10}\right)=\dfrac{-1}{2}-\dfrac{3}{10}=\dfrac{-1.5-3}{10}=\dfrac{-8}{10}=-\dfrac{4}{5}\\ ----\\ \dfrac{7}{12}-\left(-\dfrac{9}{20}\right)=\dfrac{7}{12}+\dfrac{9}{20}=\dfrac{7.5+9.3}{60}=\dfrac{62}{60}=\dfrac{31}{30}\\ ---\\ \dfrac{-2}{5}+\left(-\dfrac{11}{30}\right)=-\dfrac{2}{5}-\dfrac{11}{30}=\dfrac{-2.6-11}{30}=-\dfrac{29}{30}\)