Bài 10:

A. Ta có:

\(\dfrac{99}{100}< 1\) ; \(\dfrac{9}{8}>1\)

Nên \(\dfrac{99}{100}< \dfrac{9}{8}\)

B. \(\dfrac{7}{12}< \dfrac{7}{8}\)

Vì 37>37

=>21/37<21/36

Vì 21<26 và 35<36

=>21/36<26/35

Vậy 21/37<26/35

\(\frac{19}{20}\)và \(\frac{4}{3}\)

Ta có:

\(\frac{19}{20}\)< 1 ; \(\frac{4}{3}\)> 1

Vậy phân số \(\frac{4}{3}\)lớn hơn phân số \(\frac{19}{20}\)

\(\frac{19}{20}\)và \(\frac{15}{29}\)

\(\Rightarrow\frac{19}{20}>\frac{19}{29}>\frac{15}{29}\)

Vậy : \(\frac{19}{20}>\frac{15}{29}\)

Ta có:

\(\frac{19}{15}\)> 1 ; \(\frac{21}{27}< 1\)

Vậy \(\frac{19}{15}>\frac{21}{27}\)

P.S: Ta chỉ cần so sánh với 1 là sẽ làm được

ta có:

\(\frac{19}{15}=\frac{19\times27}{15\times27}=\frac{513}{405}\)

\(\frac{21}{27}=\frac{21\times15}{27\times15}=\frac{315}{405}\)

vậy:........

Vì \(\frac{19}{15}>1;\frac{21}{27}< 1\)

\(\frac{\Rightarrow19}{15}>\frac{21}{27}\)

Ta có: 

\(-\dfrac{9}{19}>-\dfrac{10}{19}>-\dfrac{10}{21}\\ \Rightarrow-\dfrac{9}{19}>-\dfrac{10}{21}\)

-10/19 > -10/21 ...???

\(a,\dfrac{2021}{2020}>1;\dfrac{8954}{88939}< 1\\ nên:\dfrac{8954}{88939}< 1< \dfrac{2021}{2020}\\ Vậy:\dfrac{2021}{2020}>\dfrac{8954}{88939}\)

\(b,\dfrac{14}{21}=\dfrac{14:7}{21:7}=\dfrac{2}{3}\\ \dfrac{51}{85}=\dfrac{51:17}{85:17}=\dfrac{3}{5}\\ Ta.có:\dfrac{2}{3}=\dfrac{10}{15};\dfrac{3}{5}=\dfrac{9}{15}\\ Vì:\dfrac{10}{15}>\dfrac{9}{15}\Rightarrow\dfrac{2}{3}>\dfrac{3}{5}\\ Vậy:\dfrac{14}{21}>\dfrac{51}{85}\)