\(a,6\cdot\frac{1}{3}+0,75+\frac{3}{4}:0,25\)

\(< =>6\cdot\frac{1}{3}+\frac{3}{4}+\frac{3}{4}:\frac{1}{4}\)

\(< =>2+\frac{3}{4}:\frac{1}{4}\)

\(< =>2+3\)

\(< =>5\)

\(b,19,5\cdot2,2+8,8\cdot19,5-19,5\)

\(< =>42,9+171,6-19,5\)

\(< =>214,5-19,5\)

\(< =>195\)

a; 0,2.\(\dfrac{15}{36}\) - (\(\dfrac{2}{5}\) + \(\dfrac{2}{3}\)): 1%

   = \(\dfrac{1}{12}\)  - \(\dfrac{16}{15}\): \(\dfrac{1}{100}\)

  =    \(\dfrac{1}{12}\) - \(\dfrac{320}{3}\)

= \(\dfrac{1}{12}\) - \(\dfrac{1280}{12}\)
= - \(\dfrac{1279}{12}\)

b; 75% - 1\(\dfrac{1}{2}\) + 0,5 : \(\dfrac{5}{12}\)

= 0,75 - 1,5 + 1,2

= -0,75 + 1,2

= 0,45

c; 1\(\dfrac{3}{15}.0,75-\left(\dfrac{8}{15}+0,25\right)\).\(\dfrac{24}{47}\)

= \(\dfrac{28}{15}\).0,75 - \(\dfrac{47}{60}\).\(\dfrac{24}{47}\)

= \(\dfrac{7}{5}-\dfrac{2}{5}\)

= 1

d; \(\dfrac{32}{15}\): (-1\(\dfrac{1}{5}\) + 1\(\dfrac{1}{3}\))

= \(\dfrac{32}{15}\): (-\(\dfrac{6}{5}\) + \(\dfrac{4}{3}\))

= \(\dfrac{32}{15}\): \(\dfrac{2}{15}\)

= 16

e; 20 + 9\(\dfrac{1}{4}:2\dfrac{1}{4}\)

= 20 + \(\dfrac{37}{4}\) : \(\dfrac{9}{4}\)

= 20 + \(\dfrac{37}{9}\)

= \(\dfrac{217}{9}\)

g; \(\dfrac{3}{4}.\dfrac{16}{9}\)- \(\dfrac{7}{5}\): (-\(\dfrac{21}{20}\))

=  \(\dfrac{4}{3}\) - (-\(\dfrac{4}{3}\))

= \(\dfrac{4}{3}\) + \(\dfrac{4}{3}\)

= \(\dfrac{8}{3}\)

\(56.0,75+56.0,25+0,25+75%\)%

\(=56.0,75+56.0,25+0,25+75:100\)

\(=56.0,25.3+56.0,25+0,25.1+0,25.3\)

\(=0,25.(56.3+56+1+3)\)

\(=0,25.228\)

\(=57\)

\(#YH\)

\(#NBaoNgoc\)

\(a,\frac{3}{17}+\frac{-5}{13}+\frac{-18}{35}+\frac{14}{17}+\frac{17}{-35}\)

=\(-\frac{5}{13}+\left(\frac{3}{17}+\frac{14}{17}\right)+\left(\frac{-18}{35}+\frac{-17}{35}\right)\)

= \(-\frac{5}{13}+1+\left(-1\right)\)

=\(-\frac{5}{13}\)

\(b,\frac{-3}{8}.\frac{1}{6}+\frac{3}{-8}.\frac{5}{6}+\frac{-10}{6}\)

=\(\frac{-3}{8}.\left(\frac{1}{6}+\frac{5}{6}\right)+\frac{-10}{6}\)

=\(\frac{-3}{8}.1+\frac{-10}{6}\)

=\(-\frac{49}{24}\)

\(c,\frac{-4}{11}.\frac{5}{15}.\frac{11}{-4}\)

=\(\left(\frac{-4}{11}.\frac{11}{-4}\right).\frac{1}{3}\)

=\(1.\frac{1}{3}=\frac{1}{3}\)

\(d,\frac{13}{8}+\frac{1}{8}:\left(0,75-\frac{1}{2}\right)-25\%.\frac{1}{2}\)

=\(\frac{13}{8}+\frac{1}{8}:\left(\frac{3}{4}-\frac{1}{2}\right)-\frac{1}{4}.\frac{1}{2}\)

=\(\frac{13}{8}+\frac{1}{8}:\frac{1}{4}-\frac{1}{8}\)

=\(\frac{13}{8}+\frac{1}{2}+\frac{-1}{8}\)

=\(\left(\frac{13}{8}+\frac{-1}{8}\right)+\frac{1}{2}\)

=\(\frac{3}{2}+\frac{1}{2}=2\)

\(e,\frac{-1}{2^2}-\left(-2\right)^2-5\)

=\(\frac{-1}{4}-4-5\)

=\(-\frac{37}{4}\)

\(f,\frac{121}{3}-\frac{5}{7}:\left(24-\frac{23}{57}\right)\)

=\(\frac{121}{3}-\frac{5}{7}:\frac{1345}{57}\)

=\(\frac{121}{3}-\frac{57}{1883}\)

\(\approx40,4\)

1/1.3 + 1/3.5 +....+1/17.19=1/2( 2/1.3+2/3.5+2/5.7+....+2/17.19)

                                      = 1/2 ( 1-1/3+1/3-1/5+...........+1/17-1/19) 

                                      = 1/2( 1-1/19)

                                      =9/19

bạn có thể tham khảo cái này nhé:1/m-1/n=n-m/m.n 

B=\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{17.19}\)

\(2B=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{17.19}\)

\(2B=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{17}-\frac{1}{19}\)

\(2B=1-\frac{1}{19}=\frac{18}{19}\)

\(B=\frac{18}{19}.\frac{1}{2}=\frac{9}{19}\)

k mk nha

Có thấy bạn trả lời gì đâu

1) 2,75 - 5/6 × 2/5 = 2,75 - (5/6) × (2/5) = 2,75 - 1/3 = 2,75 - 0,33 = 2,42

2) 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 3/4) - 3/5 = 1,25 - (5/6 - 9/12) - 3/5 = 1,25 - (10/12 - 9/12) - 3/5 = 1,25 - 1/12 - 3/5 = 1,25 - 0,08 - 0,6 = 1,25 - 0,68 = 0,57

3) 4/9 × 0,75 + 8/5 + 3,125 = (4/9) × 0,75 + 8/5 + 3,125 = 0,44 + 8/5 + 3,125 = 0,44 + 1,6 + 3,125 = 0,44 + 4,725 = 5,165

4) 1,125 - 4/7 - 0,12 = 1,125 - (4/7) - 0,12 = 1,125 - 0,57 - 0,12 = 0,435 - 0,12 = 0,315

5) (1/3 + 0,4) × 3,5 + (1/6 + 0,75) × 6/5