tim x: X x 3/5 + X x 3/7 = 31/70
x*3/5+x*2/7=31/70
x*x-1/6=5/18
tim x
x*3/5+x*2/7 = 31/70
\(\Rightarrow\)X*(3/5+2/7)=31/70
\(\Rightarrow\)X*31/35=31/70
\(\Rightarrow\)X=31/70:31/35
\(\Rightarrow\)X=1/2
\(x.\frac{3}{5}+x.\frac{2}{7}=\frac{31}{70}\)
\(x.\frac{31}{35}=\frac{31}{70}\)
\(x=\frac{1}{2}\)
tim y biet:y x 3/5 + y x 2/7=31/70
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\(y\times\frac{3}{5}+y\times\frac{2}{7}=\frac{31}{70}\)
\(y\times\left(\frac{3}{5}+\frac{2}{7}\right)=\frac{31}{70}\)
\(y\times\frac{31}{35}=\frac{31}{70}\)
\(y=\frac{31}{70}:\frac{31}{35}\)
\(y=\frac{31\times35}{70\times31}\)
\(y=\frac{35}{70}=\frac{1}{2}\)
Đáp số: \(y=\frac{1}{2}\)
Cách Tiểu học nhé em
y x(3/5+2/7)=31/70
y x 31/35=31/70
y=31/70:31/35
y=1/2
a ( X + 7 ) x 8 -14 = 66
b 1+2+3+...+X = 1711
c X + 3/5 + X x 2/7 = 31/70
d 1/7 + 6/7 x X = 1/7
a, (X+7)x8-14=66
=>(X+7)x8=66+14
=>(X+7)x8=80
=>X+7=80:8
=>X+7=10
=>X=10-7
=>X=3
b, 1+2+3+...+X=1711
<=>(X+1)xX:2=1711
=>(X+1)xX=1711x2
=>(X+1)xX=3422=59x58
Vì x<x+1 và (x+1)-x=1
=>x=58
c, X+3/5+Xx2/7=31/70
<=>Xx(1+2/7)+3/5=31/70
=>Xx9/7=31/70-3/5
=>Xx9/7=-11/70
=>X=-11/70:9/7
=>X=-11/90
d, 1/7+6/7xX=1/7
=>6/7xX=1/7-1/7
=>6/7xX=0
=>X=0:6/7
=>X=0
Chúc bạn học giỏi nha!!!
K cho mik với nhé cung bảo bình
Y x 3/5 + y x 2/7 = 31/70
Tìm y
\(y\times\frac{3}{5}+y\times\frac{2}{7}=\frac{31}{70}\)
\(\Leftrightarrow y\times\left(\frac{3}{5}+\frac{2}{7}\right)=\frac{31}{70}\)
\(\Leftrightarrow y\times\frac{31}{35}=\frac{31}{70}\)
\(\Leftrightarrow y=\frac{1}{2}\)
y x \(\frac{3}{5}\)+ y x \(\frac{2}{7}\)= \(\frac{31}{70}\)
y x \(\left(\frac{3}{5}+\frac{2}{7}\right)\)= \(\frac{31}{70}\)
y x \(\frac{31}{35}\) = \(\frac{31}{70}\)
y = \(\frac{31}{70}\): \(\frac{31}{35}\)
y = \(\frac{1}{2}\)
a) x*4+2,7=22,7 b)49.8-x:2,4=29,8 c)1/7+2/5*x=3/7 d)x*4+x*15=1919 e)x*0,7-x*0,2=28 f)x*3/5+x*2/7=31/70
a) x*4+2,7=22,7
4x = 20
x=5
b)49,8-x:2,4=29,8
x:2,4 = 20
x = 48
c)1/7+2/5*x=3/7
2/5 * x = 2/7
x=5/7
d)x*4+x*15=1919
x* 19 = 1919
x= 101
e)x*0,7-x*0,2=28
x* 0,5 = 28
x= 56
f)x*3/5+x*2/7=31/70
x * 31/35 = 31/70
x= 1/2
Tim x biet
(x+1/5)-4=-2
(2x+3)*(x-7)=0
31/9(x)-5/2=8/3
Ta có : \(\left(2x+3\right)\left(x-7\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x+3=0\\x-7=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=-3\\x=7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{3}{2}\\x=7\end{cases}}\)
Tìm x,biết :
\(a,\left(x+\frac{1}{5}\right)-4=-2\)
\(\left(x+\frac{1}{5}\right)=2\)
\(x+\frac{1}{5}=2\)
\(x=\frac{9}{5}\)
b,\(\left(2x+3\right)\left(x-7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x+3=0\\x-7=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-\frac{3}{2}\\x=7\end{cases}}\)
\(c,\frac{31}{9}x-\frac{5}{2}=\frac{8}{3}\)
\(\frac{31}{9}x=\frac{8}{3}+\frac{5}{2}\)
\(\frac{31}{9}x=\frac{31}{6}\)
\(x=\frac{3}{2}\)