Rút gọn các biểu thức:
a) \(\left(x+1\right)^2\)- \(\left(x-1\right)^2\)- 3 ( x + 1 ) ( x - 1 )
b) 5(x + 2 ) ( x - 2 ) - \(\frac{1}{2}\)\(\left(6-8x\right)^2\)+ 17
Những câu hỏi liên quan
Rút gọn các biểu thức sau:
\(a,\left(x+1\right)^2-\left(x-1\right)^2-3\left(x+1\right)\left(x-1\right)\)
\(b,5\left(x+2\right)\left(x-2\right)-\frac{1}{2}\left(6-8x\right)^2+17\)
a) = x^2 + 2x + 1 - x^2 +2x - 1 -3x^2 +x - x - 1
= - 3x^2 +4x -1
b) =5x^2 + 10x - 10x - 20 - 1/2 .(36 - 96x + 64x^2 ) +17
= 5x^2 - 20 - 18 - 48 x - 32x^2 +17
= -27x^2 - 48x - 3
Chúc bn hok tốt a !
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rút gọn các biểu thức sau
a) \(\left(x+1\right)^2.\left(x-1\right)^2-3\left(x+1\right).\left(x-1\right)\)
b) \(5.\left(x+2\right).\left(x-2\right)-\frac{1}{2}.\left(6-8x\right)^2+17\)
Rút gọn biểu thức
1. \(5\left(x+2\right)\left(x-2\right)-\frac{1}{2}\left(6-8x\right)^2+17\)
2. \(\left(x^2-1^3\right)-\left(x^4+x^2+1\right)\left(x^2-1\right)\)
\(5\left(x+2\right)\left(x-2\right)-\frac{1}{2}\left(6-8x\right)^2+17\)
\(=5\left(x^2-4\right)-\frac{1}{2}\left(36-96x+64x^2\right)+17\)
\(=5x^2-20+30-32x^2+17=-27x^2+27\)
\(\left(x^2-1^3\right)-\left(x^4+x^2+1\right)\left(x^2-1\right)\)
\(=x^2-1-\left(x^6-x^4+x^4-x^2+x^2-1\right)\)
\(=x^2-1-x^6+1=x^2-x^6\)
1. 5( x + 2 )( x - 2 ) - 1/2( 6 - 8x )2 + 17
= 5( x2 - 4 ) - 1/2( 36 - 96x + 64x2 ) + 17
= 5x2 - 20 - 18 + 48x - 32x2 + 17
= -27x2 + 48x - 21
2. ( x2 - 13 ) - ( x4 + x2 + 1 )( x2 - 1 )
= ( x2 - 1 ) - ( x4 + x2 + 1 )( x2 - 1 )
= ( x2 - 1 )[ 1 - ( x4 + x2 + 1 ) ]
= ( x2 - 1 )( 1 - x4 - x2 - 1 )
= ( x2 - 1 )( -x4 - x2 )
= -x6 - x4 + x4 + x2
= x2 - x6
Rút Gọn:
\(a:\left(x+1\right)-\left(x-1\right)-3\cdot\left(x+1\right)\cdot\left(x-1\right)\)
\(b:5\cdot\left(x+2\right)\cdot\left(x-2\right)-\frac{1}{2}\cdot\left(6-8x\right)^2+17\)
a
(x+1)-(x-1)-3(x+1)(x-1)
=(x+1)-(x-1)-3x+1.(x-1)
=(x+1)-(x-1)-3x+x-1
=x+1-x+1-3x+x-1
=x-x-3x+x+1+1-1
=-2x
b,
5(x+2)(x-2)-1/2(6-8x)^2+17
=5x+10(x-2)-1/2(36-64x2)+17
=5x+10x-20-18+32x2+17
=5x+10x-20-18+17+32x2
=15x-21+32x2
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a
(x+1)-(x-1)-3(x+1)(x-1)
=(x+1)-(x-1)-3x+1.(x-1)
=(x+1)-(x-1)-3x+x-1
=x+1-x+1-3x+x-1
=x-x-3x+x+1+1-1
=-2x
b,
5(x+2)(x-2)-1/2(6-8x)^2+17
=5x+10(x-2)-1/2(36-64x2)+17
=5x+10x-20-18+32x2+17
=5x+10x-20-18+17+32x2
=15x-21+32x2
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a
(x+1)-(x-1)-3(x+1)(x-1)
=(x+1)-(x-1)-3x+1.(x-1)
=(x+1)-(x-1)-3x+x-1
=x+1-x+1-3x+x-1
=x-x-3x+x+1+1-1
=-2x
b,
5(x+2)(x-2)-1/2(6-8x)^2+17
=5x+10(x-2)-1/2(36-64x2)+17
=5x+10x-20-18+32x2+17
=5x+10x-20-18+17+32x2
=15x-21+32x2
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Xem thêm câu trả lời
Rút gọn
\(5\left(x+2\right)\left(x-2\right)-\frac{1}{2}\left(6-8x^2\right)+17\)
\(5\left(x+2\right)\left(x-2\right)-\frac{1}{2}\left(6-8x^2\right)+17\)
\(=5\left(x^2-4\right)-\left(3-4x^2\right)+17\)
\(=5x^2-20-3+4x^2+17\)
\(=9x^2-6\)
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Rút gọn các biểu thức:
a, \(\left(x+1\right)-\left(x-4\right)^2-3\left(x+1\right)\left(x-2\right)\)
b, \(5\left(x+2\right)\left(x-2\right).2\dfrac{1}{2}\left(6-8x\right)^2+17\)
rút gọn biểu thức:A=\(\left(\frac{x^2}{x^3-4x}+\frac{6}{6-3x}+\frac{1}{x+2}\right).\left(x-2+\frac{10-x^2}{x+2}\right)\)
với x khác 0,x khác cộng trừ 2
\(A=\left(\frac{x^2}{x^3-4x}+\frac{6}{6-3x}+\frac{1}{x+2}\right):\left(x-2+\frac{10-x^2}{x+2}\right)\)
\(=\left[\frac{x^2}{x\left(x^2-4\right)}+\frac{-6}{3\left(x-2\right)}+\frac{1}{x+2}\right]:\left[\frac{\left(x-2\right)\left(x+2\right)}{x+2}+\frac{10-x^2}{x+2}\right]\)
\(=\left[\frac{x}{\left(x-2\right)\left(x+2\right)}+\frac{-2}{x-2}+\frac{1}{x+2}\right]:\left[\frac{x^2-4}{x+2}+\frac{10-x^2}{x+2}\right]\)
\(=\left[\frac{x}{\left(x-2\right)\left(x+2\right)}+\frac{-2\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}+\frac{x-2}{\left(x-2\right)\left(x+2\right)}\right]:\left[\frac{x^2-4+10-x^2}{x+2}\right]\)
\(=\frac{x-2x-4+x-2}{\left(x-2\right)\left(x+2\right)}:\frac{6}{x+2}=\frac{-6}{\left(x-2\right)\left(x+2\right)}.\frac{x+2}{6}=\frac{-1}{x-2}\)
Rút gọn biểu thức \(B=\left(\left(x+\frac{1}{x}\right)^6-\left(x^6+\frac{1}{x^6}\right)-2\right):\left(\left(x+\frac{1}{x}\right)^3+x^3+\frac{1}{x^3}\right)\)
Rút gọn biểu thức sau: A=\(\left[\left(x^4-x+\frac{x-3}{x^3+1}\right).\frac{\left(x^3-2x^2+2x-1\right)\left(x+1\right)}{x^9+x^7-3x^2-3}+1-\frac{2\left(x+6\right)}{x^2+1}\right].\frac{4x^2+4x+1}{\left(x+4\right)\left(3-x\right)}\)