12/7 x 14/3 = 168/21 = 8

\(=\dfrac{12}{7}\times\dfrac{14}{3}=8\)

\(\dfrac{12}{7}.\dfrac{14}{3}=\dfrac{168}{21}\)

thay m= 30 và n= 12

ta có 30 x 12 - 25

= 360 - 25 

= 335

thay m = 30; n = 12 vào biểu thức :

30 x 12 - 25 = 360 - 25 = 335

giúp mình với

 My favorite sport is football. It is considered a king sport. In the world, there are many players and fans though it does not know when it was there. I have known football since I was 4 years old because my father is also a football fan. He instilled in me the love of football and I am so grateful for that. I've been practicing playing football ever since, it's still an habit I can't quit. Football has helped me entertain after stressful lessons, help me exercise and find joy in life. Whenever I think of football, I am always full of energy and optimism. In particular, I really admire Messi because he is really a good player, an example that I try to follow. Finally, I want to say, I cannot live without football, just like people cannot live without oxygen. Be strong and never give up your passion. Goodbye !

3 + 3 + 3 - 3 - 3 = 3 

3 - 3 - 3 : 3 + 1 = 2 

3 + 3 - 3 + 3 : 3 = 2

CÒN LẠI ĐNAG NGHĨ 

3 + 3 - 3 - 3 : 3 = 2 

3 + 3 - 3 + 3 - 3 = 3 

3 + 3 - 3 + 3 : 3 = 4 

3 + 3 : 3 + 3 : 3 = 5 

3 + 3 + 3 - 3 - 3 = 3

3 + 3 - 3 + 3 : 3 = 4 

3 + 3 - 3 - 3 : 3 = 2

3 + 3 : 3 + 3 : 3 = 5

\(2b,=\left(2x^3-4x^2-4x^2+8x-2x+4-9\right):\left(2x-4\right)\\ =\left[\left(2x-4\right)\left(x^2-2x-2\right)-9\right]:\left(2x-4\right)\\ =x^2-2x-2\left(\text{ dư -9}\right)\)

\(y'=3mx^2-4mx-\left(m+1\right)\)

- Với \(m=0\Rightarrow y'=-1< 0\) hàm nghịch biến trên R (thỏa)

- Với \(m\ne0\) hàm nghịch biến trên R khi:

\(\left\{{}\begin{matrix}3m< 0\\\Delta'=4m^2+3m\left(m+1\right)\le0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}m< 0\\7m^2+3m\le0\\\end{matrix}\right.\) 

\(\Leftrightarrow-\dfrac{3}{7}\le m< 0\)

Vậy \(-\dfrac{3}{7}\le m\le0\Rightarrow m=0\)

S có 1 phần tử

(x-5)⁴ = (x-5)⁶

(x-5)⁴ - ( x-5)⁶ = 0

(x-5)⁴.{ 1 - (x-5)² }= 0

\(\left[{}\begin{matrix}x-5=0\\(x-5)^2=1\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=5\\x-5=1\\x-5=-1\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)

\(x\in\) { 4; 5; 6}

\(\dfrac{7}{3}-\dfrac{2}{1}=\dfrac{7-6}{3}=\dfrac{1}{3}\)

7/3 - 6/3 = 1/3

7/3-6/3

1/3