\(\frac{-15}{4}\times\frac{9}{11}+\frac{15}{4}\times\frac{15}{11}-\frac{15}{4}\times\frac{6}{11}\)

\(=\frac{15}{4}\times\left(\frac{-9}{11}+\frac{15}{11}-\frac{6}{11}\right)\)

\(=\frac{15}{4}\times0\)

\(=0\)

\(=\frac{15}{4}\times\left(-\frac{9}{11}\right)+\frac{15}{4}\times\frac{15}{11}+\frac{15}{4}\times\left(-\frac{6}{11}\right)\)

\(=\frac{15}{4}\times\left(-\frac{9}{11}+\frac{15}{11}+\left(-\frac{6}{11}\right)\right)\)

\(=\frac{15}{4}\times0\)

\(=0\)

\(x+\frac{4}{9}=\frac{5}{2}:\frac{4}{3}\)

\(x+\frac{4}{9}=\frac{15}{8}\)

\(x=\frac{15}{8}-\frac{4}{9}\)

\(x=\frac{103}{72}\)

nha bn

103/72 chắc luôn tích nhá

\(x+\frac{4}{9}=\frac{5}{2}:\frac{4}{3}\)

\(x+\frac{4}{9}=\frac{15}{8}\)

\(x=\frac{15}{8}-\frac{4}{9}\)

\(x=\frac{135}{72}-\frac{32}{72}\)

\(x=\frac{103}{72}\)

\(\Rightarrow x=\left(\frac{33}{5}.\frac{1}{6}-\frac{1}{8}.8+\frac{2}{15}.\frac{3}{100}\right).\frac{11}{4}\)

\(=\left(\frac{11}{10}-1+\frac{1}{250}\right).\frac{11}{4}=\frac{13}{125}.\frac{11}{4}=\frac{143}{500}\)

 \(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\) 

=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\) 

=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)

2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)

\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\) 

\(\dfrac{35}{12}-\dfrac{7}{5}\)

\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)

4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)

(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\) 

6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)

7 + \(\dfrac{103}{28}\)

\(\dfrac{299}{28}\)

x. \(\dfrac{1}{2}\) =\(\dfrac{3}{4}+\dfrac{1}{5}\)

x . \(\dfrac{1}{2}=\dfrac{15}{20}+\dfrac{4}{20}\)

x.\(\dfrac{1}{2}=\dfrac{19}{20}\)

x      = \(\dfrac{19}{20}:\dfrac{1}{2}\)

x = 19/10

\(x-\dfrac{1}{5}=\dfrac{2}{3}\) . \(\dfrac{9}{4}\)

\(x-\dfrac{1}{5}=\) \(\dfrac{3}{2}\)

x = \(\dfrac{3}{2}+\dfrac{1}{5}\)

x =\(\dfrac{15}{10}\) + \(\dfrac{3}{10}\)

x=\(\dfrac{18}{10}\) =\(\dfrac{9}{5}\)

mik ko bt

có ai giúc mk ko mk đăng nhiều lần rồi răng ko ai chịu giúc nhỉ 

Người ta biết làm thì người ta mới giúp bạn được chứ , không biết làm thì viết linh tinh à .

Đề bài hình như sai : 

\(\frac{3}{4}-2\left|2x-\frac{2}{3}\right|=2\)

\(\Rightarrow2\left|2x-\frac{2}{3}\right|=\frac{3}{4}-2\)

\(\Rightarrow2\left|2x-\frac{2}{3}\right|=\frac{3}{4}-\frac{8}{4}\)

\(\Rightarrow2\left|2x-\frac{2}{3}\right|=-\frac{5}{4}\)

\(\Rightarrow\left|2x-\frac{2}{3}\right|=-\frac{5}{4}:2\)

\(\Rightarrow\left|2x-\frac{2}{3}\right|=-\frac{5}{8}\)

\(\Rightarrow x=\varnothing\)

Vậy \(x=\varnothing\)