\(x\left(x-y\right)=\frac{3}{10};y\left(x-y\right)=-\frac{3}{50}\)

\(\Rightarrow\frac{x\left(x-y\right)}{y\left(x-y\right)}=\frac{\frac{3}{10}}{\frac{-3}{50}}\Rightarrow\frac{x}{y}=\frac{3}{10}.\frac{50}{-3}=-5\)

\(\Rightarrow x=-5y\)(1)

Thay (1) vào

\(x\left(x-y\right)=\frac{3}{10}\Rightarrow-5y\left(-5y-y\right)=\frac{3}{10}\)

\(\Rightarrow30y^2=\frac{3}{10}\Leftrightarrow y^2=\frac{3}{10}.\frac{1}{30}=\frac{1}{100}\Rightarrow y=\orbr{\begin{cases}\frac{1}{10}\\-\frac{1}{10}\end{cases}}\)

\(\Rightarrow x=\orbr{\begin{cases}\frac{1}{10}.-5=-\frac{1}{2}\\-\frac{1}{10}.-5=\frac{1}{2}\end{cases}}\)

x*(x-y)=3/10

y*(x-y)=-3/50

=>x*(x-y)-y*(x-y)=3/10-(-3/50)

=>(x-y)*(x-y)=15/50+3/50=18/50=9/25

=>x-y=(3/5;-3/5)

+)Nếu x-y=3/5=>x=1/2;y=-10

+)Nếu x-y=-3/5=>x=-1/2;y=10

Phạm Tuấn Đạt ơi sao suy luôn ra đc 30y^2 z ?

dẽ quá luôn

tự làm nha

siêu dễ luôn

\(\hept{\begin{cases}x\left(x-y\right)=\frac{3}{10}\\y\left(x-y\right)=-\frac{3}{50}\end{cases}}\Rightarrow\frac{x}{y}=-5\Rightarrow x=-5y\)

\(x\left(x-y\right)=-5y\left(-5y-y\right)=30y^2=\frac{3}{10}\Leftrightarrow\orbr{\begin{cases}y=\frac{1}{10}\Rightarrow x=-\frac{1}{2}\\y=-\frac{1}{10}\Rightarrow x=\frac{1}{2}\end{cases}}\)

\(x\left(x-y\right)-y\left(x-y\right)=\frac{3}{10}+\frac{3}{50}=\frac{18}{50}=\frac{9}{25}\)

\(\Rightarrow\left(x-y\right)\left(x-y\right)=\frac{9}{25}\)

\(\Rightarrow\left(x-y\right)^2=\orbr{\begin{cases}\left(\frac{3}{5}\right)^2\\\left(-\frac{3}{5}\right)^2\end{cases}}\)

\(\Rightarrow x-y=\orbr{\begin{cases}\frac{3}{5}\\-\frac{3}{5}\end{cases}}\)

\(\frac{x.\left(x-y\right)}{y.\left(x-y\right)}=\frac{3}{10}:-\frac{3}{50}=-5=\frac{x}{y}\)

\(x=-5y\Rightarrow-5y\left(-5y-y\right)=\frac{3}{10}\Rightarrow30y^2=\frac{3}{10}\Rightarrow y=\frac{1}{10}hoặcy=-\frac{1}{10}\)

với y=1/10 => x=-5.1/10=-1/2

với y= -1/10 => x= 1/2

câu trả lời đúng ko đấy

x/8=ý/10và x+ý=72