Tìm x :
a, x x1999=1999x199,8
b,[x x 0,25 +1999]x2000 =[53+1999]x2000
c,71 + 65x4=\(\frac{x+140}{x}\)+260
TIM X:
(2,8X-32):2/3=90
(Xx0,25+1999)x2000=(53+1999)x2000
71+65x4=X +140/X +260
chỗ X +140/X là phân số riêng sau đó mới cộng 260
Tìm x
\(Xx1999+1999x199,8\)
\(\left(Xx0,25+1999\right)x2000=\left(53+1999\right)x2000\)
\(71+65x4=\frac{x+140}{x}+260\)
Nhanh thì tick
(x . 0,25- 1999) x2000=(53+1999)x2000
\(\left(x\cdot0,25-1999\right)\cdot2000=\left(53+1999\right)\cdot2000\)
\(=\left(x\cdot0,25-1999\right)\cdot2000=4104000\)
\(\Rightarrow x\cdot0,25-1999=4104000:2000\)
\(\Rightarrow x\cdot0,25=2052+1999\)
\(\Rightarrow x=4051:0,25\)
\(\Rightarrow x=16204\)
Ủng hộ mk nka!^_^
( X x 0,25 + 1999) x 2000=( 53+1999) x2000
( X x 0,25 + 1999) x 2000=( 53+1999) x 2000
( X x 0,25 + 1999) = ( 53+1999) x 2000 : 2000
( X x 0,25 + 1999) = ( 53+1999)
( X x 0,25 + 1999) = 2052
X x 0,25 = 2052 -1999
X x 0,25 = 53
X = 53 : 0,25
X = 212
bài ; tìm X , biết ;
a , [ X x 0,25 + 1999 ] x 2000 = [ 53 + 1999 ] x2000
[ X x 0,25 + 1999 ] x 2000 = [ 53 + 1999 ] x2000
\(\Rightarrow\)x=212
[ X x 0,25 + 1999 ] x 2000 = [ 53+1999 ] x 2000
[ X x 0,25 + 1999 ] = [ 53+1999 ] x 2000 : 2000
X x 0,25 + 1999 = 53+1999
X x 0,25 = 53 + 1999 - 1999
X x 0,25 = 53
X = 53 : 0,25 =212
\(\Rightarrow X.0,25=53\)
\(\Rightarrow X=212\)
Tìm x:
a) (X x 0,25 + 1999) x 2000 = ( 53 + 1999 ) x 2000
b) 71 + 65 x 4 = \(\dfrac{x+140}{x}\) + 260
\(a.\left(x\times0,25+1999\right)\times2000=2052\times2000\\ \left(x\times0,25+1999\right)\times2000=4104000\\ x\times0,25+1999=4104000:2000\\ x\times0,25+1999=2052\\ x\times0,25=2052-1999\\ x\times0,25=53\\ x=53:0,25\\ x=212\)
tim x
a, ( x 0,25+1999).2000=(53+1999).2000
b, 71+65.4=x+140/x+260
a, ( x . 0,25+1999).2000=(53+1999).2000
=> 500x + 1999 . 2000 = 53 . 2000 + 1999 . 2000
=> 500x = 53 . 2000 + 1999 . 2000 - 1999 .2000
=> 500x = 53 . 2000
=> x = 53 . 2000 : 500
=> x = 53 . 4
=> x = 212
tìm x
( x * 0,25 + 1999 ) * 2000 = ( 53 + 1999 ) * 2000
71 + 65 * 4 = \(\frac{x+140}{x}\) + 260
( X x 0,25+ 1999) x2000= ( 53+1999) x2000
( X x 0,25+ 1999) = ( 53+1999)x2000:2000
( X x 0,25+1999) =( 53+1999)
( X x 0,25+1999) = 2052
X+0,25 = 2052 - 1999
X+ 0,25 = 53
X = 53:0,25
X = 212
71+65 x4 = x+140/x + 260
x+140/x + 260= 71+65x4
x+140/x + 260=71 + 260
x+140/x=71
x/x +140/x=71
1+ 140/x=71
140/x=71-1
140/x=70
x=140/70
x=2
k nha linh
tìm x
A) (\(\chi\)x 0,25 + 1999) x 2000= (53+ 1999) x 2000
b) 71 + 65 x 4=\(\frac{\chi+140}{\chi}\)+ 260.
Ai biết làm thì giúp mik nhé
a)(x.0,25+1999)x2000=(53+1999)x2000
(x.0,25+1999)=53+1999
x.0,25=53
x=53x4
x=210
a)(x.0,25+1999)x2000=(53+1999)x2000
(x.0,25+1999)=53+1999
x.0,25=53
x=53x4
x=210
k mik đi
(x .0,25 + 1999) . 2000 = (53+1999) .2000
(x . 0,25 +1999 )= (53 +1999)
x. 0,25= 53
x = 53 :0, 25
x = 212
dau cham la dau nhan