a.\(y:\dfrac{4}{5}=\dfrac{11}{8}\)

\(y=\dfrac{11}{8}\times\dfrac{4}{5}\)

\(y=\dfrac{11}{10}\)

b.\(\dfrac{11}{3}-y=\dfrac{1}{9}\)

\(y=\dfrac{11}{3}-\dfrac{1}{9}\)

\(y=\dfrac{32}{9}\)

c.\(\dfrac{1}{7}\times x=\dfrac{8}{5}\)

\(x=\dfrac{8}{5}:\dfrac{1}{7}\)

\(x=\dfrac{56}{5}\)

\(y=\dfrac{11}{8}.\dfrac{4}{5}\)

\(y=\dfrac{44}{40}\)

\(x=\dfrac{11}{3}-\dfrac{1}{9}\)

\(x=\dfrac{99-3}{27}=\dfrac{96}{27}\)

\(x=\dfrac{8}{5}:\dfrac{1}{7}\)

\(x=\dfrac{56}{5}\)

a)\(y=\dfrac{4}{5}\times\dfrac{11}{8}=\dfrac{44}{40}=1\dfrac{4}{40}\)

b)\(y=\dfrac{11}{3}-\dfrac{1}{9}=\dfrac{33}{9}-\dfrac{1}{9}=\dfrac{32}{9}\)

c)\(x=\dfrac{8}{5}\times7=\dfrac{56}{5}\)

a) \(\frac{3x}{-4}=\frac{-9}{6}\)

=> \(\frac{-3x}{4}=\frac{-9}{6}\)

=> \(\frac{-3x}{4}=\frac{-3}{2}\)

=> \(\frac{-3x}{4}=\frac{-6}{4}\)

=> \(-3x=-6\)

=> \(x=\left(-6\right):\left(-3\right)=2\)

b) \(\frac{2}{x}=\frac{y}{10}=\frac{4}{-5}\)

=> \(\frac{2}{x}=\frac{y}{10}=\frac{-4}{5}\)

+) \(\frac{2}{x}=\frac{-4}{5}\)

=> \(\left(-4\right)\cdot x=2\cdot5\)

=> \(\left(-4\right)\cdot x=10\)

=> \(x=\frac{10}{-4}=\frac{-10}{4}=\frac{-5}{2}\)

+) \(\frac{y}{10}=\frac{-4}{5}\)

=> \(5\cdot y=-40\)

=> \(y=\left(-40\right):5=-8\)

Vậy \(x=-\frac{5}{2},y=-8\)

c) \(\frac{7}{-x}=\frac{5}{y}=\frac{2}{34}\)

=> \(\frac{-7}{x}=\frac{5}{y}=\frac{1}{17}\)

+) \(\frac{-7}{x}=\frac{1}{17}\Rightarrow x=\left(-7\right)\cdot17=-119\)

+) \(\frac{5}{y}=\frac{1}{17}\Rightarrow y=5\cdot17=85\)

Vậy \(x=-119,y=85\)

d) \(\frac{x^2}{4}=16\)

=> \(x^2=16\cdot4=64\)

=> \(x\in\left\{8;-8\right\}\)

e) \(\frac{3}{x^3}=\frac{4}{-36}\)

=> \(\frac{3}{x^3}=\frac{1}{-9}=\frac{-1}{9}\)

=> \(x^3=3:\left(-\frac{1}{9}\right)=-27\)

=> \(x=-3\)

Vậy x = -3

bài 1

a)\(\frac{x}{y}=\frac{7}{3}\Rightarrow\frac{x}{7}=\frac{y}{3}\)
\(\Rightarrow\frac{5x}{5.7}=\frac{2y}{2.3}=\frac{5x-2y}{35-6}=\frac{87}{29}=3\)
\(\Rightarrow x=3.7=21;y=3.3=9\)

Bài dưới tướng tự nhé

1

a ) 

( 9407 - 7274 ) : y = 8058 : 34 

       2133         : y =    237 

                         y =     2133 : 237 

                        y =      9

b )

y x 128 - y x 17 - y x 11 = 576000

y x ( 128 - 17 - 11 )       = 576000

y x         100                  = 576000

y                                   = 576000 : 100

y                                  = 5760 

2

a )

( 125 x 36 ) : ( 5 x 9 ) =

    4500       :      45    =

         100

b )

1/10 + 2/10 + 3/10 + 4/10 + 5/10 + 6/10 + 7/10 + 8/10 + 9/10=

( 1/10 + 9/10 ) + ( 2/10 + 8/10 ) + ( 3/10 + 7/10 ) + ( 4/10 + 6/ 10 ) + 5/10=

          1            +            1          +            1           +          1             + 0,5 =

                                    4,

Chúc bạn học giỏi nhé !

bài 5:

tìm y:

y + 1 = 123

y = 123 - 1

y = 122

Bài 1: 

Ta có:

\(y-x=25\Rightarrow y=25+x\)

Mà \(7x=4y\Rightarrow7x=4\cdot\left(25+x\right)\)

\(7x=100+4x\)

\(\Rightarrow7x-4x=100\)

\(3x=100\)

\(x=\frac{100}{3}\)

bài 1 :

Ta có: 7x=4y ⇔ x/4=y/7

áp dụng tính chất dãy tỉ số bằng nhau ta có 

x/4=y/7=(y-x)/(7-4)=100/3

⇒x= 4 x 100/3=400/3 ; y = 7 x 100/3=700/3

bài 2 

ta có x/5 = y/6 ⇔ x/20=y/24

         y/8 = z/7 ⇔ y/24=z/21

⇒x/20=y/24=z/21

ADTCDTSBN(bài 1 có)

x/20=y/24=z/21=(x+y)/(20+24)=69/48=23/16

⇒x= 20 x 23/16 = 115/4

   y= 24x 23/16=138/2

   z=21x23/16=483/16

bài 3

x:y:z=3:8:5  ⇔ x/3=y/8=z/5

ADTCDTSBN

x/3=y/8=z/5=(3x+y-4z)/(9+8-10)=14/7=2

⇒x = 2x3 = 6 ; y= 2x8=`16; z=2x5=10

a, Xét : \(\frac{x}{-30}=-\frac{12}{20}=-\frac{3}{5}\Leftrightarrow5x=90\Leftrightarrow x=18\)

Xét : \(\frac{-36}{y}=\frac{-3}{5}\Leftrightarrow3y=180\Leftrightarrow y=60\)

Vậy \(x=18;y=60\)

b, \(\frac{x-1}{7}=\frac{2y+5}{3}\)và \(x+2y=-16\)

Áp dụng tính chất dãy tỉ số bằng nhau ta có : 

\(\frac{x-1}{7}=\frac{2y+5}{3}=\frac{x+2y-1+5}{7+3}=\frac{-16+4}{10}=\frac{-12}{10}=-\frac{6}{5}\)

\(\Leftrightarrow\frac{x-1}{7}=-\frac{6}{5}\Leftrightarrow5x-5=-42\Leftrightarrow5x=-37\Leftrightarrow x=-\frac{37}{5}\)

\(\Leftrightarrow\frac{2y+5}{3}=-\frac{6}{5}\Leftrightarrow10y+25=-18\Leftrightarrow10y=-43\Leftrightarrow y=-\frac{43}{10}\)