7 x ( x : 7 ) = 833

        x : 7  = 833 : 7

        x : 7  = 119

        x       = 119 x 7

        x       = 883

Vậy x = 833

7 x ( x : 7 ) = 833
( x : 7 ) = 833 : 7
( x : 7 ) = 119
x = 119 x 7
x = 833
Không biết có đúng hay không!

7x( x:7)=833

x:7=833:7

x:7=119

x=119x7

x=833

Vậy x=833

a) \(6x+15\times8=12\times\left(19-x\right)\)

\(6x+120=228-12x\)

\(6x+120-228+12x=0\)

\(18x-108=0\)

\(18x=108\)

\(x=6\)

b) \(160-\left(35\div x+3\right)\times15=15\)

\(160-\left(35\div x+3\right)=1\)

\(35\div x+3=159\)

\(35\div x=156\)

\(x=\dfrac{35}{156}\)

c) \(2x-\left(1309\div11-19\right)-2=0\)

\(2x-1309\div11-19=2\)

\(2x-119-19=2\)

\(2x-119=21\)

\(2x=140\)

\(x=70\)

d) \(\left(x-7\right)\times\left(2x-16\right)=0\)

\(x-7=0;2x-16=0\)

\(x=7;2x=16\)

\(x=7;x=8\)

a) $6x+15\times 8=12\times \left(19-x\right)$

$6x+120=228-12x$

$6x+120-228+12x=0$

$18x-108=0$

$18x=108$

$x=6$

b) $160-\left(35÷x+3\right)\times 15=15$

$160-\left(35÷x+3\right)=1$

$35÷x+3=159$

$35÷x=156$

�=35156x=15635​
 

Câu 1:

a) = \(\dfrac{-7}{2}\) x \(\dfrac{45}{32}\) = \(\dfrac{-315}{64}\)

b) = \(\dfrac{18}{7}\) : \(\dfrac{-27}{14}\) = \(\dfrac{18}{7}\) x \(\dfrac{14}{-27}\) = \(\dfrac{-4}{3}\)

c) = \(\dfrac{-3}{8}\) x ( \(\dfrac{5}{11}\) + \(\dfrac{6}{11}\) + 2 ) = \(\dfrac{-3}{8}\) x 3 = \(\dfrac{-9}{8}\)

Câu 2:

\(\dfrac{-3}{5}\) . x + \(\dfrac{7}{6}\) = \(\dfrac{5}{4}\)

\(\Leftrightarrow\) \(\dfrac{-3}{5}\) . x = \(\dfrac{5}{4}\) - \(\dfrac{7}{6}\)

\(\Leftrightarrow\) \(\dfrac{-3}{5}\) . x = \(\dfrac{1}{12}\)

\(\Leftrightarrow\) x = \(\dfrac{1}{12}\) : \(\dfrac{-3}{5}\)

\(\Leftrightarrow\) x = \(\dfrac{-5}{36}\)

=210 nha bn

** mk đi

Số số hạng là : ( 20 - 1 ) : 1 + 1 = 20 ( số )

Tổng là : ( 20 + 1 ) x 20 : 2 = 210

~ Chúc học tốt ~

Ai ngang qua xin để lại 1 L - I - K - E 

  1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20

= ( 1 + 20 ) x 20 : 2 

= 210

\(\frac{12}{7}\times\frac{2}{11}+\frac{12}{11}\times\frac{15}{7}-\frac{12}{7}\times\frac{6}{11}\)

\(=\frac{12}{7}\times\frac{2}{11}+\frac{12}{7}\times\frac{15}{11}-\frac{12}{7}\times\frac{6}{11}\)

\(=\frac{12}{7}\times\left(\frac{2}{11}+\frac{15}{11}-\frac{6}{11}\right)\)

\(=\frac{12}{7}\times1=\frac{12}{7}\)

\(\frac{12}{7}.\frac{2}{11}+\frac{12}{11}.\frac{15}{7}-\frac{12}{7}.\frac{6}{11}\)

= \(\frac{24}{77}\)+\(\frac{180}{77}\)-\(\frac{72}{77}\)

=\(\frac{132}{77}\)

\(\frac{12}{7}\cdot\frac{2}{11}+\frac{12}{11}\cdot\frac{15}{7}-\frac{12}{7}\cdot\frac{6}{11}\)

\(=\frac{12}{7}\cdot\frac{2}{11}+\frac{12}{7}\cdot\frac{15}{11}-\frac{12}{7}\cdot\frac{6}{11}\)

\(=\frac{12}{7}\cdot\left(\frac{2}{11}+\frac{15}{11}-\frac{6}{11}\right)\)

\(=\frac{12}{7}\cdot1\)

\(=\frac{12}{7}\)

13 - 12  + 11 + 10 - 9 + 8 - 7 -6+ 5 -4 + 3 + 2 -1

= 13 - ( 12 - 11 - 10 + 9 ) + ( 8-7-6+ 5 ) - ( 4 - 3  - 2 + 1 )

= 13 - 0 + 0 -0

=13

Học tốt !

\(2.x-15=11\)

            \(2x=11+15\)

            \(2x=26\)

              \(x=26:2\)

              \(x=13\)

\(b,4.\left(2-x\right)-5\left(3-x\right)=-12\)

             \(8-4x-15+5x=-12\)

                                     \(x-7=-12\)

                                             \(x=-12+7\)

                                             \(x=-5\)

\(c,\left|x-7\right|+13=25\)

               \(\left|x-7\right|=25-13\)

               \(\left|x-7\right|=12\)

\(\Rightarrow\orbr{\begin{cases}x-7=12\\x-7=-12\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=19\\x=-5\end{cases}}\)

a, 2.x - 15 = 11

           2.x = 11 + 15

           2.x = 26

              x = 26 : 2

              x = 13

b, 4.(2 - x) - 5(3 - x) = -12

        8 - 4x - 15 - 5x = -12

                     -7 + x = -12 

                            x = -12 + 7 

                            x = -5

c, |x - 7| + 13 = 25

            |x - 7|= 25 - 13

            |x - 7 | = 12

                   x = 12 + 7

                  x = 19