Các bạn giúp mk với, nhanh nhé, mk cần gấp

Câu a có 1 số 0 to thôi nhé!

\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)

\(\Rightarrow1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)

\(\Rightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1\)

\(\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{53}{3}\)

\(\Rightarrow\frac{43}{8}+x=\frac{53}{3}+\frac{173}{24}\)

\(\Rightarrow\frac{43}{8}+x=\frac{199}{8}\)

\(\Rightarrow x=\frac{199}{8}-\frac{43}{8}\)

\(\Rightarrow x=\frac{156}{8}=\frac{39}{2}\)

\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)

\(< =>1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)

\(< =>1\left(\frac{43}{8}+x-\frac{173}{24}\right)=0\)

\(< =>\frac{43}{8}+x-\frac{173}{24}=0\)

\(< =>\frac{43}{8}+x=\frac{173}{24}\)

\(< =>x=\frac{173}{24}-\frac{43}{8}\)

\(< =>x=\frac{11}{6}\)

\(\left(-2+\left(\frac{3}{8}-\frac{5}{24}\right)+\frac{37}{9}x\right):\frac{50}{3}=1\)

\(\left(-2\frac{4}{24}+\frac{37}{9}x\right)=\frac{3}{50}\)

\(\frac{37}{9}x=\frac{3}{50}--2\frac{4}{24}=\frac{3}{50}+2\frac{4}{24}=2\frac{26}{100}=2\frac{13}{50}=\frac{113}{50}\)

\(x=\frac{113}{50}:\frac{37}{9}=\frac{113}{50}x\frac{9}{37}=\frac{1017}{1850}\)

vậy x=1017/1850

nếu chưa rút gọn về pstg thì các bn làm tiếp nhé đâu tay lắm

\(\left(-5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16\frac{2}{3}\right)=0\)

\(< =>\left(\frac{-43}{8}+x-\frac{173}{24}\right):\left(\frac{-50}{3}\right)=0\)

\(< =>\frac{-43}{8}+x-\frac{173}{24}=0\)

\(< =>\frac{-43}{8}+x=\frac{173}{24}\)

\(< =>x=\frac{173}{24}+\frac{43}{8}\)

\(< =>x=\frac{151}{12}\)

giúp mk nhanh nhé

ai nhanh mk tk cho

B1

a) \(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)

\(1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)

\(1-\left(x-\frac{11}{6}\right).\frac{3}{50}=0\)

\(\left(x-\frac{11}{6}\right).\frac{3}{50}=1-0\)

\(\left(x-\frac{11}{6}\right).\frac{3}{50}=1\)

\(x-\frac{11}{6}=1:\frac{3}{50}\)

\(x-\frac{11}{6}=\frac{50}{3}\)

\(x=\frac{50}{3}+\frac{11}{6}\)

\(x=\frac{37}{2}\)

b) \(\frac{3}{5}+\frac{5}{7}:x=\frac{1}{3}\)

\(\frac{5}{7}:x=\frac{1}{3}-\frac{3}{5}\)

\(\frac{5}{7}:x=-\frac{4}{15}\)

\(x=\frac{5}{7}:\left(-\frac{4}{15}\right)\)

\(x=-\frac{75}{28}\)

c) \(\left(4\frac{1}{2}-\frac{2}{5}.x\right):\frac{7}{4}=\frac{11}{9}\)

\(\left(\frac{9}{2}-\frac{2}{5}.x\right):\frac{7}{4}=\frac{11}{9}\)

\(\frac{9}{2}-\frac{2}{5}.x=\frac{11}{9}.\frac{7}{4}\)

\(\frac{9}{2}-\frac{2}{5}.x=\frac{11}{2}\)

\(\frac{2}{5}.x=\frac{9}{2}-\frac{11}{2}\)

\(\frac{2}{5}.x=-1\)

\(x=-1:\frac{2}{5}\)

\(x=-\frac{5}{2}\)

B2

a) \(\left(\frac{1}{2}+\frac{1}{3}+\frac{2}{6}\right).24:5-\frac{9}{22}:\frac{15}{121}\)

\(=\left(\frac{3}{6}+\frac{2}{6}+\frac{2}{6}\right).24:5-\frac{9}{22}.\frac{121}{15}\)

\(=\frac{7}{6}.24:5-\frac{33}{10}\)

\(=28:5-\frac{33}{10}\)

\(=\frac{28}{5}-\frac{33}{10}\)

\(=\frac{56}{10}-\frac{33}{10}\)

\(=\frac{23}{10}\)

b) \(\frac{5}{14}+\frac{18}{35}+\left(1\frac{1}{4}-\frac{5}{4}\right):\left(\frac{5}{12}\right)^2\)

\(=\frac{25}{70}+\frac{36}{70}+\left(\frac{5}{4}-\frac{5}{4}\right):\frac{25}{144}\)

\(=\frac{61}{70}+0:\frac{25}{144}\)

\(=\frac{61}{70}+0\)

\(=\frac{61}{70}\)