\(\left|5x-4\right|=\left|x+2\right|\)

\(\Rightarrow\orbr{\begin{cases}5x-4=x+2\\5x-4+x+2=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}5x-x=2+4\\6x-2=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}4x=6\\6x=2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{1}{3}\end{cases}}\)

b tương tự

\(\left|5x-4\right|=\left|x+2\right|\)

\(\Rightarrow\orbr{\begin{cases}5x-4=x+2\\5x-4=-\left(x+2\right)\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}5x-x=4+2\\5x-4=-x-2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}4x=6\\5x+x=4-2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{6}{4}\\6x=2\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{2}{6}=\frac{1}{3}\end{cases}}\)

\(\text{b) }\left|2+3x\right|=\left|4x-3\right|\)

\(\Rightarrow\orbr{\begin{cases}2+3x=4x-3\\2+3x=-\left(4x-3\right)\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}-4x+3x=-2-3\\2+3x=-4x+3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}-1x=-5\\4x+3x=-2+3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\7x=1\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=\frac{1}{7}\end{cases}}\)

a) \(|5x-3|-x=\text{​​}6\)

\(\Rightarrow|5x-3|=6+x\left(1\right)\)

Vì \(\Rightarrow|5x-3|\ge0\)

\(\Rightarrow6+x\ge0\)

\(\Rightarrow x\ge-6\)

(1) xảy ra\(\Leftrightarrow\orbr{\begin{cases}5x-3=6+x\\5x-3=-6-x\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}5x-x=6+3\\5x+x=-6+3\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}4x=9\\6x=-3\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{9}{4}\\x=-2\end{cases}}\)

Vậy ...

Phần b tương tự

c) \(|x+1|+|x+2|=3\left(1\right)\)

Ta có: \(x+1=0\Leftrightarrow x=-1\)

\(x+2=0\Leftrightarrow x=-2\)

Lập bảng xét dấu :

+) Với \(x< -2\Rightarrow\hept{\begin{cases}x+1< 0\\x+2< 0\end{cases}\Rightarrow}\hept{\begin{cases}|x+1|=-x-1\\|x+2|=-x-2\end{cases}\left(2\right)}\)

Thay(2) vào (1) ta được :

\(\left(-x-1\right)+\left(-x-2\right)=3\)

\(-2x-3=3\)

\(x=-3\)( chọn )

+) Với \(-2\le x< -1\Rightarrow\hept{\begin{cases}x+1< 0\\x+2>0\end{cases}\Rightarrow\hept{\begin{cases}|x+1|=-x-1\\|x+2|=x+2\end{cases}\left(3\right)}}\)

Thay (3) vào (1) ta được 

\(-x-1+x+2=3\)

\(1=3\)( loại )

+) Với \(x\ge1\Rightarrow\hept{\begin{cases}x+1>0\\x+2>0\end{cases}\Rightarrow\hept{\begin{cases}|x+1|=x+1\\|x+2|=x+2\end{cases}\left(4\right)}}\)

THay (4) vào (1) ta được :
\(x+1+x+2=3\)

\(2x+3=3\)

\(x=0\)( loại )

Vậy x=-3 

mk chắc chắn 100% là x>0

\(\left|5x-3\right|\ge7\)

\(\Rightarrow5x-3\ge\pm7\)

TH1 : 

\(5x-3\ge7\)

\(\Rightarrow x\ge2\)

TH2 :

\(5x-3\ge-7\)

\(\Rightarrow x\ge-\frac{4}{5}\)

Vậy ................

hơi sai sai nếu x= 0 sao

a) \(2\left|2x-3\right|=\frac{1}{2}\)

    \(\left|2x-3\right|=\frac{1}{2}:2\)

     \(\left|2x-3\right|=\frac{1}{4}\)

      \(\orbr{\begin{cases}2x-3=\frac{1}{4}\\2x-3=-\frac{1}{4}\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}2x=\frac{13}{4}\\2x=\frac{11}{4}\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=\frac{13}{8}\\x=\frac{11}{8}\end{cases}}\)

b)\(7,5-3\left|5-2x\right|=-4,5\)

                 \(3\left|5-2x\right|=12\)

                     \(\left|5-2x\right|=4\)

\(\orbr{\begin{cases}5-2x=4\\5-2x=-4\end{cases}}\Leftrightarrow\orbr{\begin{cases}2x=1\\2x=9\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{9}{2}\end{cases}}}\)

còn lại mk chịu

|5x-3| -x =7

|5x-3| = 7 +x

Th1: 5x-3 = 7+x

4x =10

x= 10/4

Th2: 5x -3 = -(7+x) 

5x -3 = -7 -x

6x = -4

x= -2/3 

Vậy............

/5x-3/-x =7

/5x-3/ = 7+x

=>\(\orbr{\begin{cases}5x-3=7+x\\5x-3=-\left(7+x\right)\end{cases}}\)=>\(\orbr{\begin{cases}5x-x=3+7\\5x-3=-7-x\end{cases}}\)=>\(\orbr{\begin{cases}4x=10\\5x+x=3-7\end{cases}}\)=>\(\orbr{\begin{cases}x=2,5\\6x=-4\end{cases}}\)=>\(\orbr{\begin{cases}x=2,5\\x=-\frac{2}{3}\end{cases}}\)

|5x-3|-x=7

=>|5x-3|=7+x

=>5x-3=-(7+x) hoặc 7+x

Nếu 5x-3=-(7+x)

=>5x-3=-x-7

=>6x=-4

=>x=\(-\frac{2}{3}\)

Nếu 5x-3=7+x

=>4x=10

=>x=\(\frac{5}{2}\)

I5x-3I-x=7

=> |5x-3|=7+x

=> TH1 : 

5x-3=7+x

=> 5x-x=7+3

=> 4x = 10

=> x=2.5

TH2 :

5x-3=-(x+7)

=> 5x=-(x+7)+3

=> 5x=-x+((-7)+3)

=> 5x=-x+(-4)

=> 5x+x=-4

=> 6x=-4

=> x = -2/3

s mấy you k vào fx cho đẹp, dc tick nhìu

a) 54 – 19i;

b) -15 + i.