30 . ( x + 2 ) - 6 . ( x - 5 ) - 24 . x =100
30.(x+2)-6.(x-5)-24.x=100
Tìm x biết 30.(x+2)-6.(x-5)-24.x=100
30.(x+2)-6.(x-5)-24.x=100
30.x+30.2-6.x-(-5.6)-24.x=100
30.x+60-6.x+30-24.x=100
(30x-6x-24x)+60+30=100
x(30-6-24)+90=100
x.0 =100-90
x.0 =10(vô lí)
vậy x=\(\phi\)
30.(x+2)-6.(x-5)-24x=100
<=>30x+60-6x+30-24x=100
<=>(30x-6x-24x)+(60+30)=100
<=>x.0+90=100
<=>x.0+90=100
<=>x.0=100-90=10
Mà 10 ko thể chia cho 0
Nên x ko tồn tại
a) -12.(x-5)+7(3-x)=15
b) 30.(x+2)-6.(x-5)-24.x=100
\(-12\left(x-5\right)+7\left(3-x\right)=15\)
\(-12x+60+21-7x=15\)
\(-12x-7x=15-60-21\)
\(-19x=-66\)
\(x=\frac{66}{19}\)
Vây....
b)
a) -12.(x-5)+7(3-x)=15
<=> - 12x + 60 + 21 - 7x = 15
<=> 12x + 7x = 60 + 21 - 15
<=> 19x = 66
<=> x = \(\frac{66}{19}\)
Vậy x = \(\frac{66}{19}\)
b) 30.(x+2)-6.(x-5)-24.x=100
<=> 30x + 60 - 6x + 30 - 24x = 100
<=> 0x = 10(vô lí)
VẬY x = \(\varnothing\)
-12.(x-5)+7(3-x)\(=\)15
\(\Leftrightarrow\) -12x+60+21-7x\(=\)15
-19x+81=15
-19x=15-81
19x=66
x=66/19
30.(x+2)-6.(x-5)-24.x=100
tìm số nguyên x
30x+60-(6x-30)-24x=100
30x+60-6x+30-24x=100
(30x-6x-24x)+60+30=100
0x+90=100
rồi không biết làm
tìm x biết:
a)-12(x-5)+7(3-x)=5
b)30(x+2)-6(x-5)-24=100
a, => -12x+60+21-7x=5
=> 71-19x=5
=> 19x = 71-5 = 66
=> x = 66 : 19 = 4
b, => 30x+60-6x+30-24=100
=> 24x+76 = 100
=> 24x = 100-76 = 24
=> x = 24 : 24 = 1
Tk mk nha
a, -12x-(-60)+21-7x=5
-19x+81=5
-19x=5-81
-19x=-76
x=-4
b, 30(x+2)-6(x-5)-24=100
30x+60-6x+30-24=100
36x+76=100
36x=34
x=34/36
Tìm x :
a, -12 ( x - 5 ) + 7 ( 3 - x ) = 5
b, 30 ( x + 2 ) - 6 ( x - 5 ) - 24 . x =100
a. -12.(x-5)+7.(3-x)=5
=> -12x+60+21-7x=5
=> -19x+81=5
=> -19x=5-81
=> -19x=-76
=> x=(-76):(-19)
=> x=4
b. 30.(x+2)-6.(x-5)-24.x=100
=> 30x+60-6x+30-24x=100
=> (30x-6x-24x)+(60+30)=100
=> 0x+90=100
=> 0x=100-90
=> 0x=10 (vô lí)
=> không tồn tại x.
Tìm số nguyên x biết: 30.(x+2)-6.(x-5)-24.x=100
30.(x+2)-6.(x-5)-24.x=100
(30x+60)-(6x-30)-24x=100
30x+60-6x+30-24x=100
x(30-6-24)= 100-90
x.0=10(vô lí)
Vậy x\(\in\)\(\varnothing\)
TÌM X THUỘC Z
a , -12 x ( X - 5 ) + 7 x ( 3 - X ) = 5
b , 30 x ( X +2 ) - 6 x ( X - 5 ) - 24 x X =100
a,-12(x-5)+7(3-x)=5
b,-12x-(-12).5+7.3-7.x=5
c,30(x+2)-6(x-3)-24.x=100
a) \(-12\left(x-5\right)+7\left(3-x\right)=5\)
\(-12x+60+21-7x=5\)
\(-19x=5-60-21\)
\(-19x=-76\)
\(x=4\)
vậy \(x=4\)
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