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Tìm x biết
(3x+2)(2x+9)-(x+2)(6x+1)=(x+1)(x-9)
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tim x biet
(3x+2)(2x+9)-(x+2)(6x+1)=x+1-(x-9)
\(\left(3x+2\right)\left(2x+9\right)-\left(x+2\right)\left(6x+1\right)=x+1-\left(x-9\right)\)
\(\Rightarrow6x^2+27x+4x+18-6x^2-x-12x-2=10\)
\(\Rightarrow18x+16=10\)
\(\Rightarrow18x=-6\)
\(\Rightarrow x=-\frac{6}{18}=-\frac{1}{3}\)
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x^2-6x+9=2x(x-3)
(x+3)^2+(x+2)(x-2)
(3x-1)^3-27(x+3)(x^2-3x+9)
x^4+2x^3+x
(3x+y)^2-4(2y-3x)^2
ai giai giup minh vs minh can ngay ngay mai
Tìm x, biết:
(3x + 2)(2x + 9) - (x + 2)(6x + 1)=(x + 1) - (x - 6)
Ai làm đúng mình k nha, mình cần gấp lắm.
(3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)
<=>6x^2+27x+4x+18-(6x^2+x+12x+2)=x+1-x+6
<=>6x^2+27x+4x+18-6x^2-x-12x-2 = 7
<=>18x+16=7
<=>18x=-9
<=>x=-0,5
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: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )30 b) 2x(3-2x) + 2x(2x-1)15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)1 d) (x+2) (x+2)- (x -3)(x+1) 9
e) (4x+1)(6x-3) 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) 14
Đọc tiếp
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
`@` `\text {Ans}`
`\downarrow`
`a)`
`3x(4x-1) - 2x(6x-3) = 30`
`=> 12x^2 - 3x - 12x^2 + 6x = 30`
`=> 3x = 30`
`=> x = 30 \div 3`
`=> x=10`
Vậy, `x=10`
`b)`
`2x(3-2x) + 2x(2x-1) = 15`
`=> 6x- 4x^2 + 4x^2 - 2x = 15`
`=> 4x = 15`
`=> x = 15/4`
Vậy, `x=15/4`
`c)`
`(5x-2)(4x-1) + (10x+3)(2x-1) = 1`
`=> 5x(4x-1) - 2(4x-1) + 10x(2x-1) + 3(2x-1)=1`
`=> 20x^2-5x - 8x + 2 + 20x^2 - 10x +6x - 3 =1`
`=> 40x^2 -17x - 1 = 1`
`d)`
`(x+2)(x+2)-(x-3)(x+1)=9`
`=> x^2 + 2x + 2x + 4 - x^2 - x + 3x + 3=9`
`=> 6x + 7 =9`
`=> 6x = 2`
`=> x=2/6 =1/3`
Vậy, `x=1/3`
`e)`
`(4x+1)(6x-3) = 7 + (3x-2)(8x+9)`
`=> 24x^2 - 12x + 6x - 3 = 7 + (3x-2)(8x+9)`
`=> 24x^2 - 12x + 6x - 3 = 7 + 24x^2 +11x - 18`
`=> 24x^2 - 6x - 3 = 24x^2 + 18x -11`
`=> 24x^2 - 6x - 3 - 24x^2 + 18x + 11 = 0`
`=> 12x +8 = 0`
`=> 12x = -8`
`=> x= -8/12 = -2/3`
Vậy, `x=-2/3`
`g)`
`(10x+2)(4x- 1)- (8x -3)(5x+2) =14`
`=> 40x^2 - 10x + 8x - 2 - 40x^2 - 16x + 15x + 6 = 14`
`=> -3x + 4 =14`
`=> -3x = 10`
`=> x= - 10/3`
Vậy, `x=-10/3`
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Tìm x, biết: (3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)
(3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)
<=>(6x2+27x+4x+18)-(6x2+x+12x+2)=x+1-x+6
<=>6x2+31x+18-6x2-13x-2=7
<=>18x+16=7
<=>18x=-9
<=>x=-1/2
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Tìm x biết:
a,(3x+2)(2x+9)-(x+2)(6x+1)=(x-1)-(x-6)
b,3(2x-1)(3x-1)-(2x-3)(9x-1)=0
tìm x biết (3x+2)(2x+9)-(x+2)(6x+1)=7
a,\(\frac{1}{2x-2}-\frac{x-1}{3x^2+6x+3}\)
b,\(\frac{4}{x^2-1}+\frac{1}{x+1}+\frac{-2}{x-1}\)
c,\(\frac{5}{2x^2+6x}-\frac{4-3x^2}{x^2-9}-3\)
ai jup em vs
Đề bài yêu cầu gì bạn?
tìm x biết (3x+2)(2x+9)-(x+2)(6x+1)-7=0