3(x-3)(x+7)+(x-4)2+48
khi x=0,5
giup vs moi nguoi oi
Moi nguoi oi giup em gap vs:
tim x
a,6x^2-(2x-3)(3x+2)-1=0
b,(x-3)(x+7)-(x+5)(x-1)=0
moi nguoi co giup nhanh nhat co the ah!!
Ai trả lời câu này giúp em và nhỏ Vi với
a.\(6x^2-\left(2x-3\right)\left(3x+2\right)-1=0\Leftrightarrow6x^2-\left(6x^2-2x-6\right)-1=0\)
\(\Leftrightarrow2x+5=0\Leftrightarrow x=-\frac{5}{2}\)
b. \(\left(x-3\right)\left(x+7\right)-\left(x+5\right)\left(x-1\right)=0\Leftrightarrow x^2+4x-21-\left(x^2+4x-5\right)=0\)
\(\Leftrightarrow-16=0\)
Vậy không có x thỏa mãn.
moi nguoi giai giup mk bai nay vs . gigi phuong trinh
(x+2)^2+(x+3)^3+(x+4)^4=2
3(x-3)(x+7)+(x-4)2+48
khi x= 0,5
giúp mình vs help !!!!
Bài 1\(57+90-\frac{\Delta y}{\Delta z}\)
\(\Delta=\)
Bài 2\(87+\infty\)
\(\infty=\)
Thay x
3(0.5-3)(0.5+7)+(0.5-4)2+48
= -641.0625
=\(-\frac{10257}{16}\)
x^4+3x^2+3>0
chung minh luon duong moi nguoi giup mk vs
Mọi số lớn hơn 0 đều có giá trị là dương .
Cho mk xin cái li ke
\(x^4+3x^2+3\)
Có \(x^4\ge0;3x^2\ge0\)
\(\Rightarrow x^4+3x^2+3\ge3>0\)
=> Luôn dương(ĐPCM)
giup em voi moi nguoi oi
tim so tu nhien x
1+2+3...+99+100+x=6050
3 nhan x tru 18 =x+20
x phan 4 = 14 phan x+1
2000-5 nhan[x-18]= 125 nhan 8
em cam on a
Xin loi moi nguoi. Mong moi nguoi tro giup ;-;
(2/3.x + 5/6) . (3/4.x - 27/8) = 0
\(\left(\frac{2}{3}.x+\frac{5}{6}\right).\left(\frac{3}{4}.x-\frac{27}{8}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}\frac{2}{3}.x+\frac{5}{6}=0\\\frac{3}{4}.x-\frac{27}{8}=0\end{cases}}\Rightarrow\orbr{\begin{cases}\frac{2}{3}.x=\frac{-5}{6}\\\frac{3}{4}.x=\frac{27}{8}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{-5}{4}\\x=\frac{9}{2}\end{cases}}\)
Vậy \(x=\frac{-5}{4}\) hoặc \(x=\frac{9}{2}\).
Học tốt
\(\left(\frac{2}{3}.x+\frac{5}{6}\right).\left(\frac{3}{4}.x-\frac{27}{8}\right)=0=>\orbr{\begin{cases}\left(\frac{3}{4}.x-\frac{27}{8}\right)=0\\\left(\frac{2}{3}.x+\frac{5}{6}\right)=0\end{cases}}\)
\(\orbr{\begin{cases}\frac{2}{3}.x=0-\frac{5}{6}\\\frac{3}{4}.x=0+\frac{27}{8}\end{cases}}=>\orbr{\begin{cases}\frac{2}{3}.x=-\frac{5}{6}\\\frac{3}{4}.x=\frac{27}{8}\end{cases}}=>\orbr{\begin{cases}x=-\frac{5}{6}:\frac{2}{3}\\x=\frac{27}{8}:\frac{3}{4}\end{cases}}=>\orbr{\begin{cases}x=-\frac{5}{4}\\x=\frac{9}{2}\end{cases}}\)
vậy \(\orbr{\begin{cases}x=-\frac{5}{4}\\x=\frac{9}{2}\end{cases}}\)
Bài làm :
\(\left(\frac{2}{3}x+\frac{5}{6}\right).\left(\frac{3}{4}x-\frac{27}{8}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{2}{3}x+\frac{5}{6}=0\\\frac{3}{4}x-\frac{27}{8}=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{2}{3}x=\frac{-5}{6}\\\frac{3}{4}x=\frac{27}{8}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{-5}{4}\\x=\frac{9}{2}\end{cases}}\)
Vậy x=-5/4 hoặc x=9/2
4.x:17=0 ; 7.x-8=713 ; 8.(x-3)=0 . mong moi nguoi giup do :))
4.x:17= 0
4.x=0:17
4.x=0
x=0:4
x=0
7.x-8=713
7.x=713+8
7.x=721
x=721:7=103
x-3=0:8
x.3=0
x=0:3
x=0
moi nguoi hay chieu co giup em vs:
c,3(2x-1)-5(x-3)+6(3x-4)=24
d,2x(5-3x)+2x(3x-5)-3(x-7)=3
xin dc cam on trc ah! Day la bai tim x ah!
c)3(2x-1)-5(x-3)+6(3x-4)=24
<=>6x-3-5x-15+18x-24=24
<=>19x-12=24
<=>19x=36
<=>x=\(\frac{36}{19}\)
d)2x(5-3x)+2x(3x-5)-3(x-7)=3
<=>10x-6x2+6x2-10x-3x-21=3
<=>-3(x-7)=3
<=>21-3x=3
<=>-3x=-18
<=>x=6
moi nguoi oi giup minh voi, ca cach giai nua nhe, dung thi minh se tich cho. thank you moi nguoi
tim x biet
x^2 - 1 < 15