Câu 3: \(\frac{3}{4x5}+\frac{3}{5x6}+\frac{3}{6x7}+...+\frac{3}{18x19}+\frac{3}{19x20}\)
Những câu hỏi liên quan
Tính nhanh:
a.
\(\frac{16x18-6}{16x17+10}\)
b.
\(\frac{3}{3x4}+\frac{3}{4x5}+\frac{3}{5x6}+\frac{3}{6x7}+\frac{3}{7x8}+\frac{3}{8x9}\)
trình bày ra cho mình nhé!
Tính nhanh
A = \(\frac{3}{1x2}+\frac{7}{3x4}+\frac{11}{5x6}+\frac{15}{7x8}\) và B = \(\frac{5}{2x3}+\frac{9}{4x5}+\frac{13}{6x7}\)
Tính nhanh: \(\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+...\frac{1}{18x19}+\frac{1}{19x20}\)
\(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{19\cdot20}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{19}-\frac{1}{20}\)
\(=\frac{1}{2}-\frac{1}{20}\)
\(=\frac{9}{20}\)
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\(\frac{1}{2x3}\)+ \(\frac{1}{3x4}\)+ \(\frac{1}{4x5}\)+ ... + \(\frac{1}{18x19}\)+ \(\frac{1}{19x20}\)
= \(\frac{1}{2}\)- \(\frac{1}{3}\)+ \(\frac{1}{3}\)- \(\frac{1}{4}\)+ \(\frac{1}{4}\)- \(\frac{1}{5}\)+ ... + \(\frac{1}{18}\)- \(\frac{1}{19}\)+ \(\frac{1}{19}\)- \(\frac{1}{20}\)
= \(\frac{1}{2}\)- \(\frac{1}{20}\)
= \(\frac{18}{40}\)= \(\frac{9}{20}\)
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=1/2-1/3+1/3-1/4+...+1/18-1/19+1/19-1/20 K MIK NHA MOI NGUOI
=1/2-1/20
=10/20-1/20
=9/20
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Xem thêm câu trả lời
A = \(\frac{9}{4x5}+\frac{9}{5X6}+\frac{9}{6X7}.....\frac{9}{34X35}+\frac{9}{35X36}\)
\(A=9\left(\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}+...+\frac{1}{34x35}+\frac{1}{35.36}\right)\)
\(A=9\left(\frac{5-4}{4x5}+\frac{6-5}{5x6}+\frac{7-6}{6x7}+...+\frac{35-34}{34x35}+\frac{36-35}{35x36}\right)\)
\(A=9\left(\frac{1}{4}-\frac{1}{36}\right)=9x\frac{8}{36}=2\)
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Toán lớp 5 à ?
Sao khó quá vậy ?
Nhìn là ngán chả mún làm ! phù...............
Mí bạn k nha !
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\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}+\frac{1}{7x8}+\frac{1}{8x9}+\frac{1}{9x10}\)
\(A=\frac{5}{1x2}+\frac{5}{2x3}+\frac{5}{3x4}+\frac{5}{4x5}+\frac{5}{5x6}+\frac{5}{6x7}+\frac{5}{7x8}\)
Ai nhanh mk tick nha!
\(A=\frac{5}{1.2}+\frac{5}{2.3}+...+\frac{5}{7.8}\)
\(\Rightarrow5A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{7.8}\)
\(\Rightarrow5A=1.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-...-\frac{1}{8}\right)\)
\(\Rightarrow5A=1-\frac{1}{8}\)
\(\Rightarrow A=\left(1-\frac{1}{8}\right).\frac{1}{5}=\frac{7}{40}\)
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\(A=\frac{5}{1.2}+\frac{5}{2.3}+...+\frac{5}{7.8}\)
\(A=5\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{5}{7.8}\right)\)
\(A=5\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{7}-\frac{1}{8}\right)\)
\(A=5\left(1-\frac{1}{8}\right)\)
\(A=5.\frac{7}{8}\)
\(A=\frac{38}{8}\)
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nhầm rồi :)
\(A=5.\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-....-\frac{1}{8}\right)\)
\(\Rightarrow A=\frac{5.7}{8}\)
\(\Rightarrow A=\frac{35}{8}\)
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\(\frac{1}{2x3}\)+\(\frac{1}{3x4}\)+\(\frac{1}{4x5}\)+\(\frac{1}{5x6}\)
=\(\frac{3-2}{2x3}\)+\(\frac{4-3}{3x4}\)+\(\frac{5-4}{4x5}\)+\(\frac{6-5}{5x6}\)
Làm tiếp phần còn lại của phép tính ?
\(\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}\)
\(=\frac{3-2}{2\times3}+\frac{4-3}{3\times4}+\frac{5-4}{4\times5}+\frac{6-5}{5\times6}\)
\(=\frac{3}{2\times3}-\frac{2}{2\times3}+\frac{4}{3\times4}-\frac{3}{3\times4}+\frac{5}{4\times5}-\frac{4}{4\times5}+\frac{6}{5\times6}-\frac{5}{5\times6}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\frac{1}{2}-\frac{1}{6}\)
\(=\frac{1}{3}\)
\(\frac{5-4}{4x5}\)+\(\frac{6-5}{5x6}\)+\(\frac{7-6}{6x7}\)
\(\frac{1}{3x4}\)+ \(\frac{1}{4x5}\) + \(\frac{1}{5x6}\) + \(\frac{1}{6x7}\)+ ............. + \(\frac{1}{11x12}\) = ?