[ x * 0.25 + 1999] * 2000=[53+1999] * 2000
(X×0.25+1999)×2000=(53+1999)×2000
( X . 0,25 + 1999).2000 = (53 + 1999).2000
=> X . 0,25 +1999 = 53+1999
=> X . 0,25 = 53
=> X = 53 : 0,25 = 53 . \(\frac{1}{4}\)
=> X = \(\frac{53}{4}\)
(x.0,25+1999) . 2000=(53+1999) . 2000
(x.0,25+1999) . 2000= 2052 . 2000
(x.0,25+1999) . 2000= 4104000
x.0,25+1999 = 4104000 : 2000
x.0,25+1999 = 2052
x.0,25 = 2052-1999
x.0,25 = 53
x = 53:0.25
x = 212
Vậy x=212.
( X x 0.25 + 1999 ) x 2000 = ( 53 +1999 )x 2000
\(\left(x\times0.25+1999\right)\times2000=\)\(\left(53+1999\right)\times2000\)
\(\Rightarrow x\times0.25+1999=53+1999\)
\(\Rightarrow x\times0.25=53\)
\(\Rightarrow x=53\div0.25\)
\(\Rightarrow x=212\)
Vậy \(x=212\)
( x *0,25 + 1999) * 2000= ( 53 + 1999) * 2000
ta thấy 2 vế trên đều có : + 1999 và * 2000
mà 2 vế đều bằng nhau suy ra : x * 0,25 = 53
vậy x = 53 : 0,25 = 212
( X x 0,25 + 1999 ) x 2000= ( 53 + 1999 ) x 2000
( 53 + 1999 ) x 2000 = 4104000
x = (4104000 : 2000 - 1999 ) : 0,25
x = 53 : 0,25
x = 212
tham khẢO
( X x 0,25 + 1999) x 2000=( 53+1999) x 2000
( X x 0,25 + 1999) = ( 53+1999) x 2000 : 2000
( X x 0,25 + 1999) = ( 53+1999)
( X x 0,25 + 1999) = 2052
X x 0,25 = 2052 -1999
X x 0,25 = 53
X = 53 : 0,25
X = 212
(x * 0,25 +1999)* 2000=(53 +1999) *2000
(x * 0,25 +1999)* 2000=(53 +1999) *2000
x* 0.25 = 53
=> x = 53 : 0.25
x = 212
Ta có \(\left(x.0,25+1999\right).2000=\left(53+1999\right).2000\)
\(\Rightarrow\frac{1}{4}x+1999=53+1999\)
\(\Rightarrow\frac{1}{4}x=53\)
\(\Rightarrow x=53.4\)
\(\Rightarrow x=212\)
(x . 0,25 + 1999) . 2000 = (53 + 1999) . 2000
x . 0,25 = 53
x = 53 : 0,25
x = 212
tìm x :
( x x 0,25 + 1999 ) x 2000 = ( 53 + 1999 ) x 2000
( x * 0,25 + 1999 ) * 2000 = ( 53 + 1999 ) * 2000
=> x * 0,25 = 53
=> x = 53 : 0,25
=> x = 212
( 53 + 1999 ) * 2000 = 4104000
x = (4104000 : 2000 - 1999 ) : 0,25
x = 53 : 0,25
x = 212
Tìm X biết ( X x 0,25 + 1999) x 2000=( 53+1999) x 2000
( X x 0,25 + 1999) x 2000=( 53+1999) x 2000
( X x 0,25 + 1999) = ( 53+1999) x 2000 : 2000
( X x 0,25 + 1999) = ( 53+1999)
( X x 0,25 + 1999) = 2052
X x 0,25 = 2052 -1999
X x 0,25 = 53
X = 53 : 0,25
X = 212
mình ko biets nhung cho mình hỏi câu này [18*13-x]*1/4=150*0,25
Tìm x:
a) (X x 0,25 + 1999) x 2000 = ( 53 + 1999 ) x 2000
b) 71 + 65 x 4 = \(\dfrac{x+140}{x}\) + 260
\(a.\left(x\times0,25+1999\right)\times2000=2052\times2000\\ \left(x\times0,25+1999\right)\times2000=4104000\\ x\times0,25+1999=4104000:2000\\ x\times0,25+1999=2052\\ x\times0,25=2052-1999\\ x\times0,25=53\\ x=53:0,25\\ x=212\)
( X x 0,25 + 1999) x 2000=( 53+1999) x2000
( X x 0,25 + 1999) x 2000=( 53+1999) x 2000
( X x 0,25 + 1999) = ( 53+1999) x 2000 : 2000
( X x 0,25 + 1999) = ( 53+1999)
( X x 0,25 + 1999) = 2052
X x 0,25 = 2052 -1999
X x 0,25 = 53
X = 53 : 0,25
X = 212
tim x
a, ( x 0,25+1999).2000=(53+1999).2000
b, 71+65.4=x+140/x+260
a, ( x . 0,25+1999).2000=(53+1999).2000
=> 500x + 1999 . 2000 = 53 . 2000 + 1999 . 2000
=> 500x = 53 . 2000 + 1999 . 2000 - 1999 .2000
=> 500x = 53 . 2000
=> x = 53 . 2000 : 500
=> x = 53 . 4
=> x = 212