\(\frac{x-20}{x-10}=\frac{x+40}{x+70}=\frac{-20-40}{-10-70}=\frac{6}{8}=\frac{3}{4}.\)

\(\Rightarrow4\cdot\left(x-20\right)=3\cdot\left(x-10\right)\Leftrightarrow4x-80=3x-30\Leftrightarrow x=50.\)

bn dinh thuy linh gioi that, toàn dung ngôn ngữ toán hoc nên bai lam rat ấn tuong

\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)

\(\Rightarrow\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)

\(\Rightarrow x^2+70x-20x-1400=x^2+40x-10x-400\)

\(\Rightarrow x^2+70x-20x-x^2-40x+10x=1400-400\)

\(\Rightarrow20x=1000\Rightarrow x=50\)

a) (x + 15) : x = 4 : 3

=> x : x + 15 : x = \(\frac{4}{3}\)

=> 1 + 15 : x = \(\frac{4}{3}\)

=> 15 : x = \(\frac{4}{3}\)- 1 = \(\frac{1}{3}\)

=> x = 15 : \(\frac{1}{3}\)

=> x = 45

phượng quyên là otaku sa( hình đại diện so cute)

 =>x=45

\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)

\(\Rightarrow\) (x - 20)(x + 70) = (x - 10)(x + 40)

\(\Rightarrow\) x² + 70x - 20x - 140 = x² + 40x - 10x - 400

\(\Rightarrow\) x² + 70x - 20x - x² - 40x + 10x = - 400 + 140

\(\Rightarrow\) 20x = 260

\(\Rightarrow\) x = 130

đề như vậy hả bạn?

\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)

=> \(\left(x-20\right)\left(x+70\right)=\left(x+40\right)\left(x-10\right)\)

=>    \(x^2+70x-20x-1400=x^2-10x+40x-400\)

=>     \(\left(x^2-x^2\right)+\left(70x-20x+10x-40x\right)=-400+1400\)

=>        \(-43x=1000\Rightarrow x=\frac{-1000}{43}\)

pn ơi bạn Nguyễn Lương Bảo Tiên làm sai rui

\(\frac{x+20}{x-10}=\frac{x+40}{x+70}\)

\(\Rightarrow\left(x+20\right)\left(x+70\right)=\left(x+40\right)\left(x-10\right)\)

\(x^2+20x+70x+1400=x^2+40x-10x-400\)

\(90x+1400=30x-400\)

\(60x=-1800\)

\(x=-30\)

\(a,\frac{x+15}{x}=\frac{4}{3}\Rightarrow4x=3x+45\Leftrightarrow x=45\)

\(b,\frac{7,5-x}{3,5+x}=\frac{5}{6}\Rightarrow17,5+5x=45-6x\Leftrightarrow11x=27,5\Rightarrow x=2,5\)

\(c,\frac{x-20}{x-10}=\frac{x+40}{x+70}\Rightarrow\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)

\(\Leftrightarrow x^2+50x-1400=x^2+30x-400\)

\(\Leftrightarrow20x=1000\)

\(\Rightarrow x=50\)

a. \(\frac{\left(x+15\right)}{x}=\frac{4}{3}\Leftrightarrow4x=3\left(x+15\right)\Leftrightarrow4x=3x+45\Leftrightarrow x=45\)

Vậy x=45

b. \(\frac{7,5-x}{3,5+x}=\frac{5}{6}\Leftrightarrow5\left(3,5+x\right)=6\left(7,5-x\right)\Leftrightarrow17,5+5x=45-6x\Leftrightarrow11x=27,5\Leftrightarrow x=2,5\)

Vậy x=2,5

c. \(\frac{x+20}{x-10}=\frac{x+40}{x+70}\Leftrightarrow\left(x+40\right)\left(x-10\right)=\left(x+20\right)\left(x+70\right)\)

\(\Leftrightarrow x^2+30x-400=x^2+90x+1400\Leftrightarrow-60x=-30\Leftrightarrow x=-30\)

Vậy x=-30