Bài 1:

a) \(=\dfrac{8}{15}\left(\dfrac{7}{13}+\dfrac{6}{13}\right)=\dfrac{8}{15}.1=\dfrac{8}{15}\)

b) \(=\dfrac{3.3-7-2.4}{12}=-\dfrac{6}{12}=-\dfrac{1}{2}\)

Bài 2:

 \(\dfrac{x}{2,7}=-\dfrac{2}{3,6}\Rightarrow x=\dfrac{\left(-2\right).2,7}{3,6}\Rightarrow x=-\dfrac{3}{2}\)

Bài 3:

\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{x+y}{2+5}=-\dfrac{21}{7}=-3\)

\(\Rightarrow\left\{{}\begin{matrix}x=\left(-3\right).2=-6\\y=\left(-3\right).5=-10\end{matrix}\right.\)

1. a) 17.85 + 15.17 - 120

= 17.( 85 + 15) - 120

= 17. 100 -120

= 1700 - 120

= 1580

b) 20 - [ 30 - (5 - 1)² ]

= 20 - [ 30 - 4² ]

= 20 - [ 30 - 16 ]

= 20 - 14

= 6

2. a) 70 - 5.(x - 3) = 45

              5.(x - 3) = 70 - 45

              5.(x -3) = 25

                 x - 3 = 25 : 5

                 x - 3 = 5

                 x = 5 + 3

                 x = 8 

b) 10 + 2.x = 4⁵ : 4³

    10 + 2.x = 4²

    10 + 2.x = 16

           2.x = 16 - 10

          2.x = 6

             x = 6 : 2

            x =3

1)a:17.85+15.17-120=17.(85+15)-120=17.100-120=1700-120=1580

b: 20-[30-(5-1)^2 = 20-[30-4^2]=20-(30-16)=20-15=5

2)

a:  70-5(x-3)=45

   5(x-3) = 70-45=25

   x-3 = 25:5=5

   x= 5+3=8

b:  10+2x = 4^5:4^3

   10+2x = 4^2

10+2x = 16

2x = 16-10=6

x = 6:2=3

\(a,\dfrac{4}{15}:\dfrac{4}{7}< x< \dfrac{2}{5}\times\dfrac{10}{3}\\ \Leftrightarrow\dfrac{7}{15}< x< \dfrac{4}{3}\\ \Leftrightarrow x=1\)

\(b,\dfrac{3}{5}\times\dfrac{3}{7}+\dfrac{2}{5}\times\dfrac{4}{7}=\dfrac{9}{35}+\dfrac{8}{35}=\dfrac{17}{35}\)

a) |x + 4| = 17

=> \(\orbr{\begin{cases}x+4=17\\x+4=-17\end{cases}}\)

=> \(\orbr{\begin{cases}x=13\\x=-21\end{cases}}\)

b) (7 - x) - (25 + 7) = -25

=> (7 - x) - 32 = -25

=> 7 - x = -25 + 32

=> 7 - x = 7

=> x = 7 - 7

=> x = 0

c. |x + 5| = |-7|

=> |x + 5 | = 7

=> \(\orbr{\begin{cases}x+5=7\\x+5=-7\end{cases}}\)

=> \(\orbr{\begin{cases}x=2\\x=-12\end{cases}}\)

2) 4 . (-5)² + 2 . (-15)

= 2. 2 . 25 + 2 . (-15)

= 2.(2 . 25 - 15)

= 2 . 35

= 70

1/ 

a) | x+4 | = 17

\(\Rightarrow\)x+4 = 17 hoặc x+4 = -17

        x      = 13         x      = -21

b) ( 7 - x ) - ( 25 + 7 ) = -25

     7 - x                      = -25 + 25 + 7

     7 - x                      = 7

          x                      = 0

c) | x + 5 | = 7

\(\Rightarrow\)x + 5 = 7 hoặc x + 5 = -7

         x        = 2         x        = -12

2/

    4 . ( -5 )² + 2 . ( -15 )

= 4 . 25 + 2 . ( -15 )

= 100 + ( -30 )

= 70

Hk tốt

Mọi người giúp em với em đang cần gấp!!

Câu 1:

\(a,=43\cdot\left(27+93\right)+3111+3363=43\cdot120+6474=11634\\ b,=11^2+2^{15}\cdot2^3:2^{17}=121+2=123\\ c,=11^2+7^2-9=121+49-9=151\)

Câu 2:

\(a,\Rightarrow x-\dfrac{3}{2}=5^2=25\\ \Rightarrow x=25+\dfrac{3}{2}=\dfrac{53}{2}\\ b,\Rightarrow7x=30-2=28\\ \Rightarrow x=4\)

-45 x 65 - 45 x 30 - 45 x 3

= -45 x (65 + 30 + 3)

= -45 x 98

= -230

a) -5x (-9) = -11\(\Rightarrow-5\chi=\frac{11}{9}\Rightarrow\chi=\frac{11}{9}:\left(-5\right)\Rightarrow\chi=\frac{11}{9}.\frac{-1}{5}\Rightarrow\chi=\frac{-11}{45}\)b) 25 - (x + 5 ) = -415 - ( 15-415)\(\Rightarrow25-\left(\chi+5\right)=-415-15+415\)

\(\Rightarrow25-\left(\chi+5\right)=\left(-415+415\right)-15\)

\(\Rightarrow25-\left(\chi+5\right)=-15\Rightarrow\chi+5=25+15\)

\(\Rightarrow\chi+5=40\Rightarrow\chi=35\)

HTDT

1.

-45 x 65 - 45 x 30 - 45 x 3 = 45 (-65-30-3) = 45 x ( -98 ) = -4410

 2.

a) -5x (-9) = -11

45x = -11

x = -11 : 45

x = \(\frac{-11}{45}\)

b) 25 - (x + 5) = -415 - ( 15 - 415)

25 - x - 5 = -415 -15 + 415

(25 - 5) - x = (-415 + 415) - 15

20 - x = -15

x = 20 - (-15)

x = 20 + 15

x = 35

a) (x+10)(2y-5) = 143

=> (x+10);(2y-5) thuộc Ư(143)={-1,-143,1,143}

\(\orbr{\begin{cases}x+10=-143\\2y-5=-1\end{cases}}\Rightarrow\orbr{\begin{cases}x=-153\\y=2\end{cases}}\)

\(\orbr{\begin{cases}x+10=-1\\2y-5=-143\end{cases}}\Rightarrow\orbr{\begin{cases}x=-11\\y=-69\end{cases}}\)

\(\orbr{\begin{cases}x+10=1\\2y-5=143\end{cases}}\Rightarrow\orbr{\begin{cases}x=-9\\y=74\end{cases}}\)

\(\orbr{\begin{cases}x+10=143\\2y-5=1\end{cases}}\Rightarrow\orbr{\begin{cases}x=133\\y=3\end{cases}}\)

Vậy ta có các cặp x,y thõa mãn : (-153,2);(-11,-69);(-9,74);(113,3)

b) x+(x+1)+(x+2)+..+(x+30)=1240

=> (x+x+x+...+x)+(1+2+3+...+30)=1240

=> 31x+465=1240

31x = 1240-465

31x = 775

x = 775 : 31

x= 25

c) 1+2+3+...+x=210

\(\frac{\left(x-1\right)}{1}+1=x\)

=> \(\frac{\left(x+1\right).x}{2}=210\)

(x+1)x = 210:2

(x+1)x = 105

chắc ko có x thõa mãn

d) 2+4+6+...+2x=210

=> 2(1+2+3+...+x)=210

1+2+3+..+x= 210:2 = 105

\(\frac{\left(x-1\right)}{1}+1\) = x

\(\frac{\left(x+1\right).x}{2}=105\)

(x+1)x = 105:2

(x+1)x = 52,5

ko có x thõa mãn đề bài

a, x + 10 và 2y - 5 thuộc Ư(143) = {1;-1;143;-143}

 b, x+(x+1)+(x+2)+........+(x+30) = 1240

=> x+x+1+x+2+...+x+30=1240

=> 31x+(1+2+...+30) = 1240

=> 31x + 465 = 1240

=> 31x = 775

=> x = 25

c, 1+2+...+x=210

=> \(\frac{x\left(x+1\right)}{2}=210\)

=> x(x+1) = 420

Mà 420 = 20.21

=> x = 20

d, 2+4+...+2x = 210

=> 2(1+2+...+x) = 210

=> \(\frac{2x\left(x+1\right)}{2}=210\)

=> x(x + 1) = 210

Mà 210 = 14.15

=> x  = 14

e, 1+3+5+...+(2x-1) = 225

=> \(\frac{\left[\left(2x-1\right)+1\right].x}{2}=225\)

=> \(\frac{2x^2}{2}=225\)

=> x² = \(\left(\pm15\right)^2\)

=> x = 15 hoặc x = -15

c,d ST làm đúng . Mình lận nhân thành chia :(

bài 2

a) 2448:[119-(x-6)]=24                          

119-(x-6)=2448:24                                

119-(x-6)=102

x-6=119-102

x-6=17

x=17+6

x=23