\(\frac{\text{(23,4 + 12,5 ) x 7+(23,4+19,5) x 3 +11 }}{\text{0,55 x 2 x 30 + 5 x 11 + 2,75 x 8}}\)
Những câu hỏi liên quan
[ 23,4 + 15,5 ] x 7 + [ 23,4 + 19,5 ] x 3 + 11 / 0,55 x 2 x 30 + 5 x 11 + 2,75 x 8
giúp mk với nhé !
dấu / là trên nhé. VD như 2/3, a/b
ai nhanh mk sẽ dùng toàn bọ nick và tk cho người đó nha, cần gấp
\(\frac{\left(23,4+15,5\right)\cdot7+\left(23,4+19,5\right)\cdot3+11}{0,55\cdot2\cdot30+5\cdot11+2,75\cdot8}\)
\(=\frac{\left(23,4+15,5\right)\cdot\left(7+3\right)+12+11}{1,1\cdot30+5\cdot11+11\cdot2}\)
\(=\frac{38,9\cdot10+23}{11\cdot\left(3+5+2\right)}=\frac{412}{110}=\frac{206}{55}\)
Chúc em học tốt!
(Mong em đừng đăng câu hỏi linh tinh lên nữa)
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tính nhanh
[23,4+19,5].7+[23,4+19,5].3+11/0,55.2.30+5.11+2,75.8
=1656.11 NHA BN
cac bn ung ho minh nha
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Tính nhanh: a/ 4,7 x 96 + 9,4 x 2 b/ 16,7 - 4,3 - 2,4 c/ 19,15 x X - X x 9,15 d/ 23,4 x 12,5 + 12,5 x 75,6 +12,5
1 Tính:
B=\(\frac{2}{5\text{x}8}+\frac{2}{8\text{x}11}+\frac{2}{11\text{x}14}+..........+\frac{2}{95\text{x}98}\)
a,\(\dfrac{1}{7}\text{x}\dfrac{2}{7}+\dfrac{1}{7}\text{x}\dfrac{5}{7}+\dfrac{6}{7}\) b,\(\dfrac{6}{11}\text{x}\dfrac{4}{9}+\dfrac{6}{11}\text{x}\dfrac{7}{9}-\dfrac{6}{11}\text{x}\dfrac{2}{9}\)
c, \(\dfrac{4}{25}\text{x}\dfrac{5}{8}\text{x}\dfrac{25}{4}\text{x}24\)
`a)1/7xx2/7+1/7xx5/7+6/7`
`=1/7xx(2/7+5/7)+6/7`
`=1/7xx1+6/7`
`=1/7+6/7=1`
`b)6/11xx4/9+6/11xx7/9-6/11xx2/9`
`=6/11xx(4/9+7/9-2/9)`
`=6/11xx9/9`
`=6/11`
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Sorry nãy ghi thiếu.
`c)4/25xx5/8xx25/4xx24`
`=(4xx5xx25xx24)/(25xx8xx4)`
`=(4xx5xx24)/(4xx8)`
`=(5xx24)/8`
`=5xx3=15`
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a, \(\dfrac{1}{7}.\dfrac{2}{7}+\dfrac{1}{7}.\dfrac{5}{7}+\dfrac{6}{7}\)
\(=\dfrac{1}{7}.\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\dfrac{6}{7}\)
\(=\dfrac{1}{7}.1+\dfrac{6}{7}\)
\(=\dfrac{1}{7}+\dfrac{6}{7}=1\)
b, \(\dfrac{6}{11}.\dfrac{4}{9}+\dfrac{6}{11}.\dfrac{7}{9}-\dfrac{6}{11}.\dfrac{2}{9}\)
\(=\dfrac{6}{11}.\left(\dfrac{4}{9}+\dfrac{7}{9}-\dfrac{2}{9}\right)\)
\(=\dfrac{6}{11}.1=\dfrac{6}{11}\)
c, \(\dfrac{4}{25}.\dfrac{5}{8}.\dfrac{25}{4}.24\)
\(=\left(\dfrac{4}{25}.\dfrac{25}{4}\right).\left(\dfrac{5}{8}.24\right)\)
\(=1.15=15\)
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\(\frac{\left(23,4+19,5\right)x7+\left(23,4+19,5\right)x3+11}{0,55x2x30+5x11+2,75x8}\)
giup minh nha
Giải hệ phương trình:
a,left{{}begin{matrix}text{2
x
−
7
y
20
}text{3
x
+
7
y
−
5}end{matrix}right.
b,left{{}begin{matrix}text{2
x
+
3
y
8
}text{−
3
x
+
5
y
7
}end{matrix}right.
c,left{{}begin{matrix}-2x+frac{1}{2}y3text{5
x
+
3
y
11
}end{matrix}right.
d,left{{}begin{matrix}text{(
x
−
16
)(
y
+
6
)
x
y
−
36
}text{(
x
+
8
)(
y
−
3
)
x
y
−
54
}end{matrix}right.
e,left{{}begin{matrix}text{3
x
−
|
y
|
1
}text{5
x
+
3
y
11
}end{matrix}right.
f,left{{}begin{matrix}frac{3}{x}+frac{4}{y}...
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Giải hệ phương trình:
a,\(\left\{{}\begin{matrix}\text{2 x − 7 y = 20 }\\\text{3 x + 7 y = − 5}\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}\text{2 x + 3 y = 8 }\\\text{− 3 x + 5 y = 7 }\end{matrix}\right.\)
c,\(\left\{{}\begin{matrix}-2x+\frac{1}{2}y=3\\\text{5 x + 3 y = 11 }\end{matrix}\right.\)
d,\(\left\{{}\begin{matrix}\text{( x − 16 )( y + 6 ) = x y − 36 }\\\text{( x + 8 )( y − 3 ) = x y − 54 }\end{matrix}\right.\)
e,\(\left\{{}\begin{matrix}\text{3 x − | y | = 1 }\\\text{5 x + 3 y = 11 }\end{matrix}\right.\)
f,\(\left\{{}\begin{matrix}\frac{3}{x}+\frac{4}{y}=5\\\frac{1}{x}-\frac{1}{y}=1\end{matrix}\right.\)
g,\(\left\{{}\begin{matrix}x+2\sqrt{y-1}=3\\3x+4\sqrt{y-1}=7\end{matrix}\right.\)
Giúp mình với ạ!!!
1) Tính nhanh
a) A=\(\frac{3}{11\text{x}13}+\frac{3}{13\text{x}15}+\frac{3}{15\text{x}17}+...+\frac{3}{97\text{x}99}\)
b) B=\(\frac{4}{7\text{x}31}+\frac{6}{7\text{x}11}+\frac{9}{10\text{x}41}+\frac{7}{10\text{x}57}\)
3) Chứng tỏ phân số \(\frac{8n+5}{6n+4}\)tối giản với mọi số nguyên khác 0
\(A=\frac{3}{2}\times\left(\frac{1}{13\times11}+\frac{1}{13\times15}+\frac{1}{15\times17}+.....+\frac{1}{97\times99}\right)\)
\(A=\frac{3}{2}\times\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+......+\frac{1}{97}-\frac{1}{99}\right)\)
\(A=\frac{3}{2}\times\left(\frac{1}{11}-\frac{1}{99}\right)\)
\(A=\frac{3}{2}\times\frac{8}{99}\)
\(A=\frac{4}{33}\)
b] \(\frac{A}{5}=\frac{4}{31.35}+\frac{6}{35.41}+\frac{9}{41.50}+\frac{7}{50.57}\)
\(\frac{A}{5}=\frac{1}{31}-\frac{1}{35}+\frac{1}{35}-\frac{1}{41}+\frac{1}{41}-\frac{1}{50}+\frac{1}{50}-\frac{1}{57}\)
\(\frac{A}{5}=\frac{1}{31}-\frac{1}{57}\)
\(\Rightarrow A=5\left(\frac{1}{31}-\frac{1}{57}\right)=\frac{130}{1767}\)
c] Ta đặt \(\left(8n+5,6n+4\right)=d\)
\(\Rightarrow\frac{8n+5\div d}{6n+4\div d}\Rightarrow4\times\left(6n+4\right)-3\times\left(8n+5\right)=\left(24n+16\right)-\left(24n+15\right):d\)\(\Rightarrow d=1\)
Vậy \(\frac{8n+5}{6n+4}\)là phân số tối giản
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rút gọn biểu thức B = \(\dfrac{\text{20x - 11}}{\text{x - 2012}}.\dfrac{\text{x(x - 2)}}{\text{1982x}^{\text{2}}+30}-\dfrac{20x-11}{1982x^2+30}:\dfrac{x-2012}{x\left(x-3\right)+2012}\)
\(B=\dfrac{\left(x^2-2x\right)\left(20x-11\right)}{\left(x-2012\right)\left(1982x^2+30\right)}-\dfrac{\left(20x-11\right)\left(x^2-3x+2012\right)}{\left(1982x^2+30\right)\left(x-2012\right)}\left(x\ne2012\right)\\ B=\dfrac{\left(20x-11\right)\left(x^2-2x-x^2+3x-2012\right)}{\left(x-2012\right)\left(1982x^2+30\right)} \\ B=\dfrac{\left(20x-11\right)\left(x-2012\right)}{\left(x-2012\right)\left(1982x^2+30\right)}=\dfrac{20x-11}{1982x^2+30}\)
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