Hì hì xin lỗi trả lời muộn thông cảm

\(3+3^2+3^3+...+3^{2012}\)

\(=\left(3+3^2+3^3+3^4\right)+...+\left(3^{2009}+3^{2010}+3^{2011}+3^{2012}\right)\)

\(=3\left(1+3+3^2+3^3\right)+...+3^{2009}\left(1+3+3^2+3^3\right)\)

\(=40\left(3+...+3^{2009}\right)⋮40\)

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rrrrr

có ai giải giúp mình ko mình đang gấp huhu

2^x x 16 = 128 

2^x          = 128 : 16

2 ^x        = 8

2^x         = 2³

3^x : 9 = 27 

3^x      = 27 x 9

3^x      =243

3^x      = 3⁵

[ 2^x + 1 ]³ = 27

2^x3 + 1³   = 27

2^x3 +1      = 27

2^x3           = 27 - 1

2^x3           = 26

a, \(5x^2-10xy+5y^2=5\left(x^2-2xy+y^2\right)=5.\left(x-y\right)^2\)

b, \(x^2-4x+4-y^2=\left(x^2-4x+4\right)-y^2=\left(x-2\right)^2-y^2\)

\(=\left(x-2-y\right)\left(x-2+y\right)\)

c, \(3x^2-2x-5=3x^2-5x+3x-5=x\left(3x-5\right)+3x-5\)

\(=\left(3x-5\right)\left(x+1\right)\)

\(=\left(2^{78}+2^{78}.2+2^{78}.4\right):\left(2^{75}.4+2^{75}.2+2^{75}\right)\)

\(=\left[2^{78}.\left(1+2+4\right)\right]:\left[2^{75}\left(1+2+4\right)\right]\)

\(=\frac{2^{78}.\left(1+2+4\right)}{2^{75}.\left(1+2+4\right)}\)

\(=2^3=8\)

Kết quả là 8.

Bạn nhớ cho mik nha

Kết quả là 8

bạn nhớ cho mik nha

\(a,\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\left(\frac{3}{7}\right)^2\right)^{10}.\frac{3}{7}:\left(\frac{9}{49}\right)^6=\left(\frac{9}{49}\right)^{10}.\frac{3}{7}:\left(\frac{9}{49}\right)^6\)

\(=\left(\left(\frac{9}{49}\right)^{10}:\left(\frac{9}{49}\right)^6\right).\frac{3}{7}=\left(\frac{9}{49}\right)^{10-6}.\frac{3}{7}=\left(\frac{9}{49}\right)^4.\frac{3}{7}=\left(\left(\frac{3}{7}\right)^2\right)^4.\frac{3}{7}\)

\(=\left(\frac{3}{2}\right)^8.\frac{3}{7}=\left(\frac{3}{2}\right)^9\)

\(b,3-\left(-\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2=3-1+\left(\frac{1}{2}\right)^2.\frac{1}{2}=2+\left(\frac{1}{2}\right)^3=2+\frac{1}{6}=2\frac{1}{6}\)

\(c,\left(0,125\right)^3.51=\left(\frac{1}{8}\right)^3.51=\frac{1^3}{8^3}.51=\frac{1}{512}.51=\frac{51}{512}\)