Tìm x biết :
\(172x^2-7^9:98^3=2^{-3}\)
\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
Những câu hỏi liên quan
tìm x biết:
a) \(5^x.\left(5^3\right)^2=625\)
b)\(\left(\dfrac{12}{15}\right)^x=\left(\dfrac{5}{3}\right)^{-5}-\left(-\dfrac{3}{5}\right)^4\)
c)\(\left(-\dfrac{3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
d)\(172x^2-7^9:98^3=2^{-3}\)
tìm x:
\(a,5^x.\left(5^2\right)^3=625\)
\(b,\left(\dfrac{12}{15}\right)^x=\left(\dfrac{5}{4}\right)^{-2}-\left(\dfrac{-3}{5}\right)^4\)
\(c,\left(\dfrac{-3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
\(d,172x^2-7^9:98^3=2^{-3}\)
bài 1: Tìm x,y biết rằng: x+(-frac{31}{12})^2left(frac{49}{12}right)^2-xy^2 bài 2: tìm x biết:a.5^x.left(5^3right)^2625 b.left(frac{12}{25}right)^xleft(frac{5}{3}right)^{-2}-left(-frac{3}{5}right)^4 c.left(-frac{3}{4}right)^{3x-1}frac{256}{81} d.172x^2-7^9:98^32^{-3}Bài 3: Tìm x varepsilonN biết:a.8 2^xle2^9times2^{-5} b.27 81^3:3^x 243 left(frac{2}{5}right)^xleft(frac{5}{2}right)^{-3}timesleft(-frac{2}{5}right)^2c.
Đọc tiếp
bài 1: Tìm x,y biết rằng:
\(x+(-\frac{31}{12})^2=\left(\frac{49}{12}\right)^2-x=y^2\)
bài 2: tìm x biết:
a.\(5^x.\left(5^3\right)^2=625\) b.\(\left(\frac{12}{25}\right)^x=\left(\frac{5}{3}\right)^{-2}-\left(-\frac{3}{5}\right)^4\) c.\(\left(-\frac{3}{4}\right)^{3x-1}=\frac{256}{81}\)
d.\(172x^2-7^9:98^3=2^{-3}\)
Bài 3: Tìm x \(\varepsilon\)N biết:
a.\(8< 2^x\le2^9\times2^{-5}\) b.\(27< 81^3:3^x< 243\) \(\left(\frac{2}{5}\right)^x>\left(\frac{5}{2}\right)^{-3}\times\left(-\frac{2}{5}\right)^2\)c.
Bài 1:
Ta có: \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x\)
\(\Leftrightarrow2x=\frac{1440}{144}=10\)
\(\Rightarrow x=5\)
Khi đó: \(y^2=\left(\frac{49}{12}\right)^2-5=\frac{1681}{144}\)
=> \(\hept{\begin{cases}y=\frac{41}{12}\\y=-\frac{41}{12}\end{cases}}\)
tìm x biết
a .\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
b, \(172.x^2-7^9:98^3=2^{-3}\)
giúp mk đi tiên tài ơi mình cho 1000000000000000000 tick
Tìm x, biêt:
a) \(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
b) \(172.x^2-7^9:98^3=2^{-3}\)
TÌm x
a)\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
b) 172 . x2 - 79 : 98 3 = 2 -3
e.(-3/4)3x-1=256/81
f.172x2-79:983=2-3
e.(-3/4)3x-1=256/81
f.172x2-79:983=2-3
e.(-3/4)3x-1=256/81
f.172x2-79:983=2-3
e)
\(\left(-\frac{3}{4}\right)^{3x-1}=\frac{256}{81}\)
\(\left(-\frac{3}{4}\right)^{3x}=\left(-\frac{4}{3}\right)^4\)
\(\left(-\frac{3}{4}\right)^{3x}=\left(-\frac{3}{4}\right)^{-4}\)
\(3x=-4\)
\(x=-\frac{4}{3}\)
f) \(172x^2-7^9:98^3=2^{-3}\)
\(172x^2-\frac{7^9}{\left(7^2.2\right)^3}=\frac{1}{2^3}\)
\(172x^2-\frac{7^3}{2^3}=\frac{1}{2^3}\)
\(172x^2=\frac{7^3}{2^3}+\frac{1}{2^3}=\frac{344}{8}\)
\(x^2=\frac{344}{8}:172=\frac{1}{4}\)
x=1/2 hoặc x=-1/2
Đúng 0
Bình luận (0)