\(=\frac{2002}{12}+\frac{2002}{20}+\frac{2002}{30}+\frac{2002}{42}+\frac{2002}{56}\)

\(=2002.\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\right)\)

\(=2002.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\right)\)

\(=2002.\left(\frac{1}{3}-\frac{1}{8}\right)\)

\(=2002.\frac{5}{24}\)

\(=\frac{5005}{12}\)

5005/12

tk mình

5005/12 nhé.

A=202202.1/1212+202202.1/2020+202202.1/3030+202202.1/4242+202202.1/5656

A=202202.(1/1212+1/2020+1/3030+1/4242+1/5656)

A=202202.5/2424

A=417/1/12

A=202202.1/1212+202202.1/2020+202202.1/3030+202202.1/4242+202202.1/5656

A=202202.(1/1212+1/2020+1/3030+1/4242+1/5656)

A=202202.5/2424

A=5005/12

\(A=\frac{1}{6.10}+\frac{1}{10.14}+\frac{1}{14.18}+\frac{1}{18.22}+\frac{1}{22.26}+\frac{1}{26.30}\)

  \(=\frac{1}{4}.\left(\frac{1}{6}-\frac{1}{10}+\frac{1}{10}-\frac{1}{14}+\frac{1}{14}-\frac{1}{18}+\frac{1}{18}-\frac{1}{22}+\frac{1}{22}-\frac{1}{26}+\frac{1}{26}-\frac{1}{30}\right)\)

     \(=\frac{1}{4}.\left(\frac{1}{6}-\frac{1}{30}\right)=\frac{1}{4}.\frac{2}{15}=\frac{1}{30}\)

\(B=\frac{5}{2.3}+\frac{5}{3.4}+\frac{5}{4.5}+...+\frac{5}{8.9}\)\(=5.\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{8.9}\right)\)     \(=5.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{8}-\frac{1}{9}\right)\)

  \(=5.\left(\frac{1}{2}-\frac{1}{9}\right)=5.\frac{7}{18}=\frac{35}{18}\)

\(C=\left(\frac{7^2}{2.9}+\frac{7^2}{9.16}+....+\frac{7^2}{65.72}\right):\left(\frac{1}{3}-\frac{7}{36}\right)\)

   \(=7.\left(\frac{7}{2.9}+\frac{7}{9.16}+...+\frac{7}{65.72}\right):\frac{5}{36}\) \(=7.\left(\frac{1}{2}-\frac{1}{9}+\frac{1}{9}-\frac{1}{16}+...+\frac{1}{65}-\frac{1}{72}\right):\frac{5}{36}\)'

    \(=7.\left(\frac{1}{2}-\frac{1}{72}\right):\frac{5}{36}=7.\frac{35}{72}:\frac{5}{36}=\frac{49}{2}\)

\(D=\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{37.38.39}+\frac{2}{38.39.40}\)

     \(=2.\left(\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{37.38.39}+\frac{1}{38.39.40}\right)\)

     \(=2.\frac{1}{2}.\left(\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{37.38}-\frac{1}{38.39}+\frac{1}{38.39}-\frac{1}{39.40}\right)\)

        \(=\frac{1}{2.3}-\frac{1}{39.40}=\frac{259}{1560}\)

\(E=\frac{202202}{1212}+\frac{202202}{2020}+\frac{202202}{3030}+\frac{202202}{4242}+\frac{202202}{5656}\)

    \(=202202.\left(\frac{1}{3.4.101}+\frac{1}{4.5.101}+\frac{1}{5.6.101}+\frac{1}{6.7.101}+\frac{1}{7.8.101}\right)\)

      \(=2002.\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\right)\)

        \(=2002.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\right)\)

         \(=2002.\left(\frac{1}{3}-\frac{1}{8}\right)=2002.\frac{5}{24}=\frac{5005}{12}\)

1212 / 1313 = 12 / 13

201201 / 202202 = 6097 / 6094

ko biết

bạn có phân số nào bé hơn ko gửi đi mik làm co ahihi

\(\frac{1212}{1313}=\frac{12}{13}\)

\(\frac{201201}{202202}=\frac{201}{202}\)

a,3^200 và 2^300

3^200=(3^2)^100=9^100

2^300=(2^3)^100=8^100

Vì 9^100>8^100=>3^200>2^300

Vậy 3^200>2^300

b, 71^50 và 37^75

71^50=(71^2)^25=5041^25

37^75=(37^3)^25=50653^25

Vì 5041^25<50653^25=> 71^50<37^75

Vậy  71^50<37^75

c, 201201/202202 và 201201201/202202202

201201201/202202202=201201/202202

=> 201201/202202=201201201/202202202

Vậy 201201/202202=201201201/202202202

a)

Ta có:3²⁰⁰=3^2.100=(3²)¹⁰⁰=9¹⁰⁰

2³⁰⁰=2^3.100=(2³)¹⁰⁰=8¹⁰⁰

Vì 9¹⁰⁰>8¹⁰⁰

Nên 3²⁰⁰>2³⁰⁰

b) 

Ta có: 71⁵⁰=71^2.25=(71²)²⁵=5041²⁵

37⁷⁵=37^3.25=(37³)²⁵=50653²⁵

Vì 5041²⁵<50653²⁵

Nên 71⁵⁰<37⁷⁵

c)

Ta có:

201201/202202=201.1001/202.1001=201/202

201201201/202202202=201.1001001/202.1001001001= 201/202

Vì 201/202=201/202

Nên 201201/202202=201201201/202202202

\(M=\frac{7}{4}\times\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}+\frac{3333}{5656}\right)\)

\(M=\frac{7}{4}\times\left(\frac{11}{4}+\frac{33}{20}+\frac{11}{10}+\frac{11}{14}+\frac{33}{56}\right)\)

\(M=\frac{7}{4}\times\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}+\frac{33}{56}\right)\)

\(M=\frac{7}{4}\times\left(\frac{33}{3.4}+\frac{33}{4.5}+\frac{33}{5.6}+\frac{33}{6.7}+\frac{33}{7.8}\right)\)

\(M=\frac{7}{4}\times\left[33\cdot\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\right)\right]\)

\(M=\frac{7}{4}\times\left[33\times\left(\frac{1}{3}-\frac{1}{8}\right)\right]\)

\(M=\frac{7}{4}\times\left(33\times\frac{5}{24}\right)=\frac{7}{4}\times\frac{55}{8}=\frac{385}{32}\)

a. 3²⁰⁰ = (3²)¹⁰⁰ = 9¹⁰⁰

2³⁰⁰ = (2³)¹⁰⁰ = 8¹⁰⁰

Vì 9¹⁰⁰ > 8¹⁰⁰ => 3²⁰⁰ > 2³⁰⁰

ét ô ét

Ta có:\(\dfrac{201201}{202202}\)=\(\dfrac{201}{202}\);\(\dfrac{201201201}{202202202}\)=\(\dfrac{201}{202}\)

=>\(\dfrac{201}{202}\)=\(\dfrac{201}{202}\) 

=> \(\dfrac{201201}{202202}\)=\(\dfrac{201201201}{202202202}\)

Vậy: \(\dfrac{201201}{202202}\)=\(\dfrac{201201201}{202202202}\)

                                        (quá dễ)

ét ô ét = sos = cứu tôi với no biết toán lớp 6

\(\frac{201201}{202202}=\frac{201}{202}\)

=201/202

\(\frac{201201}{202202}\) \(=\) \(\frac{201201:1001}{202202:1001}\) \(=\) \(\frac{201}{202}\)

Học tốt !