Ta có:

T = \(\frac{2009\times2010+2000}{2011\times2010-2020}=\frac{2009\times2010+2010-10}{2010\times2010+2010-2020}=\frac{2010\times2010-10}{2010\times2010-10}=1\)

Vậy T = 1

2009×2010+2000/2011×2010-2020

=2009×2010+2000/2009×2010+2×2010-2020

=2009×2010+2000/2009×2010+4020-2020

=2000/4020-2020

=2000/2000

=1

K đúng cho mk nha !!!

Cảm ơn các bạn nhiều lắm.

Lời giải:

$t=\frac{2009\times 2010+2000}{2011\times 2010-2020}$

$=\frac{2010\times (2011-2)+2000}{2011\times 2010-2020}$

$=\frac{2010\times 2011-2\times 2010+2000}{2011\times 2010-2020}$

$=\frac{2010\times 2011-2020}{2011\times 2010-2020}=1$

\(A=\frac{2009x2010+2000}{2011x2010-2020}=\frac{2009x2010+2000}{2009x2010+2x2010-2020}=\frac{2009x2010+2000}{2009x2010+4020-2020}=\frac{2000}{4020-2020}=\frac{2000}{2000}=1\)

Nhấn đúng cho mk nha!!!!!!!!!!

=4058210+2016=4060226

=4062240-2014=4060226

2014x2015+2016= 4060226

2016x2015-2014=4060226

4060226

4060226

\(=\frac{\left(2009-1\right)\cdot2009+2000}{2009\cdot\left(2009+1\right)-2018}=\frac{2009^2-9}{2009^2-9}=1\\ \)

\(\frac{2011x2010-1}{2009x2011+2010}=\frac{2011x\left(2009+1\right)-1}{2009x2011+2010}\)

\(=\frac{2011x2009+2011-1}{2009x2011+2010}=\frac{2011x2009+2010}{2009x2011+2010}=1\)

2009x2010+2011x12+1998

      2011x2010-2010x 2009

=2009x2010+2010x12+12+1998

       2010x(2011-2009)

=2010x2009+2010x12+2010x1

              2010x2

=2010x(2009+12+1)

          2010x2

=2010x2022

    2010x2

=2022

     2

=1011