2

4

8

16

32

64

128

256

512

1024

2048

4096

8192

1+1=2

2+2=4

4+4=8

8+8=16

16+16=32

64+64=128

128+128=256

512+512=1024

2048+2048=4096

xong

1+1=2

2+2=4

4+4=8

8+8=16

16+16=32

32+32=64

64+64=128

128+128=256

256+256=512

512+512=1024

1024+1024=2048

2048+2048=4096

4096+4096=8192

(2+4+6+8+...+98+100)x 10/2+4+8+16+...+512-2
Ta có: 
+) 2 + 4 + 6 + 8 + ... + 98 + 100
= (100 + 2)[(100 - 2) : 2 + 1] : 2
= 102.50:2 = 2550
+)Dặt A = 2 + 4 + 8 + 16 + ... + 512 - 2
A = 2 + 2^2 + 2^3 + 2^4 + ... + 2^9 - 2
A = 2^2 + 2^3 + 2^4 + ... + 2^9
2A = 2(2^2 + 2^3 + 2^4 + .... + 2^9)
2A = 2^3 + 2^4 + 2^5 + ... + 2^10
2A - A = (2^3 + 2^4  + 2^5 + ... + 2^10) - (2^2 + 2^3 + 2^4 + ... + 2^9)
A =  2^10 - 2^2
A = 1024 - 4 = 1020
=> (2 + 4 + 6 + 8 + ... + 98 + 100) x 10/2 + 4 + 8 + 16 + ... + 512 - 2
  = 2550 x 10/1020 = 25500/1020 = 25

chịu thôi

25 nhaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Đặt 

\(S=1+2+4+...+2048+4096\)

\(S=1+2^1+2^2+...+2^{11}+2^{12}\)

\(2S=2+2^2+2^3+...+2^{12}+2^{13}\)

\(2S-S=\left(2+2^2+2^3+...+2^{13}\right)-\left(1+2+2^2+..+2^{12}\right)\)

\(S=2^{13}-1=8192-1=8191\)

Gọi A=1+2+4+8+16+...+1024+2048+4096

2A=2+4+8+16+32+...+2048+4096+8192

2A-A=(2+4+8+16+32+...+2048+4096+8192)-(1+2+4+8+16+...+1024+2048+4096)

A=8192-1

A=8191

                Đặt A = 1 + 2 + 4 + 8 + 16 +...+ 1024 + 2048 + 4096

                A = 1 + 2 + 2² + 2³ + 2⁴ +.... + 2¹⁰ + 2¹¹ + 2¹²

                     2A = 2 + 2² + 2³ + 2⁴ + 2⁵ + ..... + 2¹¹ + 2¹² + 2¹³

               2A - A = (2 + 2² + 2³ + 2⁴ + .... + 2¹¹ + 2¹² + 2¹³) - (1 + 2 + 2² + 2³ + 2⁴ +.....+ 2¹⁰ + 2¹¹ + 2¹²)

              => A = 2¹³ - 1

              => A = 8192 - 1 = 8191

           Ủng hộ mk nha !!! ^_^

Đặt A=1/2+1/4+1/8+1/16+1/32+...+1/2048+1/4096

\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{12}}\)

\(2A=2\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)

\(2A=1+\frac{1}{2}+...+\frac{1}{2^{11}}\)

\(2A-A=\left(1+\frac{1}{2}+...+\frac{1}{2^{11}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)

\(A=1-\frac{1}{2^{12}}\)

Đặt A=\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+................+\frac{1}{2048}+\frac{1}{4096}\)

2A=\(1+\frac{1}{2}+\frac{1}{4}+....................+\frac{1}{1024}+\frac{1}{2048}\)

2A-A=\(\left(1+\frac{1}{2}+\frac{1}{4}+................+\frac{1}{1024}+\frac{1}{2048}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...............+\frac{1}{2048}+\frac{1}{4096}\right)\)

A=\(1-\frac{1}{4096}\)

A=\(\frac{4095}{4096}\)

4095/4096 đó lam lợn hả

các bạn sai rồi bằng 2047/2048 đó chắc chắn 100% luôn mk thi rồi.

Đúng thì nhớ k nha các bạn hihi ^-^

Từ biểu thức trên ta được

A=1/2+1/2^2+1/2^3+....+1/2^11+1/2^12

2A-A=2(1/2+1/2^2+1/2^3+....+1/2^11+1/2^12)-(1/2+1/2^2+1/2^3+....+1/2^11+1/2^12)

A=1+1/2^2+1/2^3+....+1/2^11-1/2-1/2^2-...-1/2^12

A=1/2-1/2^12

Ủng hộ cho mình nha bạn

\(A=\)\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{1024}+\frac{1}{2048}+\frac{1}{4096}\)

\(A=\)\(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{12}}\)

\(2A=\)\(2\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)

\(2A=\)\(1+\frac{1}{2}+...+\frac{1}{2^{11}}\)

\(2A-A=\)\(\left(1+\frac{1}{2}+...+\frac{1}{2^{11}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)

\(A=1-\frac{1}{2^{12}}\)

1+1=2

2+2=4

4+4=8

8+8=16

16+16=32

32+32=64

64+64=128

128+128 = 256

256+256=512

512+512= 1024

1024+1024 = 2048 

2048 + 2048 = 4096

1+1=2

2+2=4

4+4=8

8+8=16

16+16=32

32+32=64

64+64=128

128+128=256

256+256=512

512+512=1024

1024+1024=2048

2048+2048=4096

1+1=2

2+2=4

4+4=8

8+8=16

16+16=32

32+32=64

64+64=128

128+128=256

256+256=512

512+512=1024

1024+1024=2048

2048+2048=4096

Các bạn nữ chiếm số phần trăm của lớp là :

           14 : 32 x 100 = 43,75 %

                                  đáp số : 43,75 %

Tick mìh nhaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa