tinh phep tinh sau toan lop 7 :
x + / x - 3/ = 3
x - /x + 5/ = -5
Tim x biet :
{x+1997 } + 2003 = 5432
329-{129+x } = 14 *7
Day la bai toan lop 4 : Tinh chat ket hop cua phep cong
{x+1997 } + 2003 = 5432
x+1997=5432-2003
x+1997=3429
x=3429-1997
x=1432
329-{129+x } = 14 *7
329-(129+x)=98
129+x=329-98
129+x=231
x=231-129
x=102
thuc hien phep tinh
\(\left(x^2-25\right):\dfrac{2x+10}{3x-7}\)
\(\dfrac{x^2+x}{5x^2-10x+5}:\dfrac{3x+3}{5x-5}\)
\(a.\)
\(\left(x^2-25\right):\dfrac{2x+10}{3x-7}\)
\(=\left(x-5\right)\left(x+5\right).\dfrac{3x-7}{2\left(x+5\right)}\)
\(=\dfrac{\left(x-5\right)\left(x+5\right)\left(3x-7\right)}{2\left(x+5\right)}\)
\(=\dfrac{\left(x-5\right)\left(3x-7\right)}{2}\)
\(b.\)
\(\dfrac{x^2+x}{5x^2-10x+5}:\dfrac{3x+3}{5x-5}\)
\(=\dfrac{x\left(x+1\right)}{5\left(x^2-2x+1\right)}.\dfrac{5\left(x-1\right)}{3\left(x+3\right)}\)
\(=\dfrac{x\left(x+1\right)}{5\left(x-1\right)^2}.\dfrac{5\left(x-1\right)}{3\left(x+1\right)}\)
\(=\dfrac{x\left(x+1\right).5\left(x-1\right)}{5\left(x-1\right)^2.3\left(x+1\right)}\)
\(=\dfrac{x}{3\left(x-1\right)}\)
\(\dfrac{x^2+x}{5x^2-10x+5}:\dfrac{3x+3}{5x-5}=\dfrac{5x\left(x+1\right)\left(x-1\right)}{15\left(x-1\right)^2\left(x+1\right)}=\dfrac{x}{3\left(x-1\right)}\)\(\left(x^2-25\right):\dfrac{2x+10}{3x-7}=\dfrac{\left(x-5\right)\left(x+5\right)\left(3x-7\right)}{2\left(x+5\right)}=\dfrac{\left(x-5\right)\left(3x-7\right)}{2}\)
thuchien phep tinh:
[(2x^2-2x+50):(3x+3)]/{(x^2-1):[4(x-5)^3]}
Cac ban o truong khac than men. Toi la Tran Duy Anh, hoc sinh lop 6A3 cu,nay toi buoc sang lop 7 moi. Nay toi se dua ra mot bai toan nhu sau
1+2+3+4+5+...+99+100
Cac ban hay doc ki yeu cau dau bai nhe
Goi y Cac ban hay su dung cach tinh cua Gau xo de tra loi trong SgK lop 6 tap 1 cua bai phep cong va phep nhan
Số số hạng của tổng trên là: (100 - 1) : 1 + 1 = 100(số)
Tổng trên là: (100+1)x 100 : 2 = 5050
1.Thuc hien phep tinh sau:
a,(3x^2-4x+5)(2x^2-4)-2x(3x^3-4x^2+8)
b,(1-3x+x^2)(2-4x)+2x(2x^2+5)
a ) \(\left(3x^2-4x+5\right)\left(2x^2-4\right)-2x\left(3x^3-4x^2+8\right)\)
\(=\left(3x^2-4x+5\right).2x^2-4\left(3x^2-4x+5\right)-6x^4+8x^3-16x\)
\(=6x^4-8x^3+10x^2-12x^2+16x-20-6x^4+8x^3-16x\)
\(=\left(6x^4-6x^4\right)+\left(8x^3-8x^3\right)-\left(12x^2-10x^2\right)+\left(16x-16x\right)-20\)
\(=-2x^2-20\)
b ) \(\left(1-3x+x^2\right)\left(2-4x\right)+2x\left(2x^2+5\right)\)
\(=2\left(1-3x+x^2\right)-4x\left(1-3x+x^2\right)+4x^3+10x\)
\(=2-6x+2x^2-4x+12x^2-4x^3+4x^3+10x\)
\(=\left(4x^3-4x^3\right)+\left(12x^2+2x^2\right)+\left(10x-6x-4x\right)+2\)
\(=14x^2+2\)
thực hiện cac phep tinh sau:
a. \(\frac{x}{x-3}+\frac{9-6x}{x^2-3x}\)
b.\(\frac{x+2}{3x}+\frac{x-5}{5x}-\frac{x+8}{4x.}\)
a/đkxđ: \(x\ne0;x\ne3\)
\(\frac{x}{x-3}+\frac{9-6x}{x^2-3x}=\frac{x^2}{x\left(x-3\right)}+\frac{9-6x}{x\left(x-3\right)}\)
\(=\frac{\left(x-3\right)^2}{x\left(x-3\right)}=\frac{x-3}{x}\)
b/ đkxđ: \(x\ne0\)
\(\frac{x+2}{3x}+\frac{x-5}{5x}-\frac{x+8}{4x}\) \(=\frac{20x+40}{60x}+\frac{12x-60}{60x}-\frac{15x+120}{60x}\)
\(=\frac{17x-140}{60x}\)
thuc hien phep tinh
a, 516x2,15
b, 2,1655 : 5
c, 15/4 x 8/3 x 16/25 x 1/5
d, 3/7 : 5/4 x 3/5
a, 516 x 2,15 = 1109,4
b, 2,1655 : 5 = 0,4331
c, \(\frac{15}{4}\)x \(\frac{8}{3}\)x \(\frac{16}{25}\)x \(\frac{1}{5}\)
= 10 x \(\frac{16}{25}x\frac{1}{5}\)
= \(\frac{32}{5}x\frac{1}{5}\)
= \(\frac{32}{25}\)
d, \(\frac{3}{7}:\frac{5}{4}x\frac{3}{5}\)
= \(\frac{3}{7}x\frac{4}{5}x\frac{3}{5}\)
= \(\frac{12}{35}x\frac{3}{5}\)
= \(\frac{36}{175}\)
a, 516x2,15=1109,4
b, 2,1655 : 5=0,4331
c, 15/4 x 8/3 x 16/25 x 1/5
=10x16/25 x 1/5
=6,4x1/5
=1.28
d, 3/7 : 5/4 x 3/5=12/35x3/5=36/175
dung 5 so 7 va cac phep toan de tao ra phep tinh co ket qua bang 10.tat nhien la se cho cac ban ghep cac so nua day! lam cang nhanh,tim cang nhieu phep tinh cang tot .cac ban giup minh nhe!
(7 : 7 + 7) + (7 + 7 ) : 2 - 1 = 10 . đề là cho ghép các số nữa mà ?
tôi chịu em mới lớp 2 thôi
đố cac ban ne 1 2 3 4 5 6 7 8 9 10 bai toan tinh nhanh đay cai nay minh hoc tu lop3 roi nhung minh đang hoc lop 5 minh cho lop 3 xem sao.............................................
1+2+3+4+5+6+7+8+9+10 = 55
1+2+3+4+5+6+7+8+9+10=55