Giải:

\(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)

\(=\dfrac{28}{15}.\dfrac{1}{4}.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\)

\(=\dfrac{7}{5}+\left(-\dfrac{47}{60}\right).\dfrac{24}{47}\)

\(=\dfrac{7}{5}+\left(-\dfrac{2}{5}\right)\)

\(=\dfrac{7}{5}-\dfrac{2}{5}\)

\(=1\)

Vậy ...

\(1\dfrac{13}{15}\cdot\left(0,5\right)^2+3\cdot\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)

\(=\dfrac{28}{15}\cdot\dfrac{1}{4}+3\cdot\left(\dfrac{8}{15}+\dfrac{79}{60}\right):\dfrac{47}{24}\)

\(=\dfrac{7}{15}+3\cdot\dfrac{37}{20}\cdot\dfrac{24}{47}\)

\(=\dfrac{7}{15}+\dfrac{666}{235}=\dfrac{2327}{705}\)

\(1\dfrac{13}{15}.\left(0,5\right)^2+3.\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\) 

\(=\dfrac{28}{15}.\dfrac{1}{4}+3.\left(\dfrac{8}{15}+\dfrac{79}{60}\right):\dfrac{47}{24}\) 

\(=\dfrac{7}{15}+3.\dfrac{37}{20}:\dfrac{47}{24}\) 

\(=\dfrac{7}{15}+\dfrac{666}{235}\) 

\(=\dfrac{2327}{705}\)

đọc mà phát choáng

\(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\\ =\dfrac{28}{15}.0,25.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\\ =\dfrac{7}{15}.3+\dfrac{-47}{60}:\dfrac{47}{24}\\ =\dfrac{7}{5}+\dfrac{-2}{5}\\ =\dfrac{5}{5}=1\)

( Hỗn số có thể viết thành a + b/c ( đối với hỗn số âm thì không). VD: \(1\frac{1}{2}=1+\frac{1}{2}\)) mà chỗ và là chỉ hỗn số phải chứ, xem đầu bài mk viết như vậy có đúng không nha bn, nếu ko thì nhắn tin cho mk, để mk sửa nhé!

\(B=1+[\frac{13}{15.\left(0,5\right)^2.3}+\left(\frac{8}{15-1}+\frac{19}{60}\right):1]+\frac{23}{24}\)

\(B=1+\left[\frac{13}{11,25}+\left(\frac{4}{7}+\frac{19}{60}\right)\right]+\frac{23}{24}\)

\(B=1+\left[\frac{52}{45}+\frac{373}{420}\right]+\frac{23}{24}\)

\(B=1+2+\frac{11}{252}+\frac{23}{24}\)

\(B=3+1+\frac{1}{504}\)

\(B=4+\frac{1}{504}\)

\(B=4\frac{1}{504}\)

= 1 nha bạn !

làm thế nào bạn ơi