a) (19x+2.5^2):14=(13-8)^2-4^2
b) x+(x+1)+(x+2)+...+(x+30)=1240
c) 11-(-53+x)=97
d) -(x+84)+213=-16
\(\text{Tìm x, biết:}\)
\(a\)) \(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(b\)) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(c\)) \(11-\left(-53+x\right)=97\)
\(d\)) \(-\left(x+84\right)+213=-16\)
(3.4.2^16)^2/11.2^13.4^11-16^9.Tính bằng cách hợp lý
Câu 2:
a,(19x+2.5^2):14=(13-8)^2-4^2
b,x+(x+1)+(x+2)+...+(x+30)=1204
c,11-(-53+x)=97
d,-(x+84)+213=-16
Tìm x,biết :
a)\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
b)x+(x+1)+(x+2)+...+(x+30)=1240
c)11-(-53+x)=97
d)-(x+84)+213=-16
a) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Leftrightarrow\left(19x+2\cdot25\right):14=5^2-4^2\)
\(\Leftrightarrow19x+50=\left(25-16\right)\cdot14\)
\(\Leftrightarrow19x+50=9\cdot14\)
\(\Leftrightarrow19x+50=126-50\)
\(\Leftrightarrow19x=76\)
\(\Leftrightarrow x=76:19\)
\(\Leftrightarrow x=4\)
b) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(\Leftrightarrow\left(x+x+x+x...+x\right)+\left(1+2+3+...+30\right)=1240\)
\(\Leftrightarrow31x+\frac{\left[\left(30-1\right):1+1\right]\cdot\left(30+1\right)}{2}=1240\)
\(\Leftrightarrow31x+465=1240\)
\(\Leftrightarrow31x=775\)
\(\Leftrightarrow x=25\)
c)\(11-\left(-53+x\right)=97\)
\(\Leftrightarrow-53+x=-86\)
\(\Leftrightarrow x=-33\)
d) \(-\left(x+84\right)+213=-16\)
\(\Leftrightarrow-\left(x+84\right)=-229\)
\(\Leftrightarrow x+84=229\)
\(\Leftrightarrow x=145\)
Câu hỏi : Tìm x
a, (19x+2.5 mũ 2):14 = ( 13 - 8) mũ 2 - 4 mũ 2
b, x + ( x + 1 ) + ( x + 2 ) +...+ ( x + 30 )= 1240
c, 11- ( -53 + x ) = 97
d,-(x + 81) + 213 = -16
a) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
\(\left(19x+2\cdot5^2\right):14=9\)
\(19x+2\cdot5^2=9\cdot14=126\)
\(19x+50=126\)
\(19x=126-50=76\)
\(x=\frac{76}{19}=4\)
b) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(\left(x+x+..+x\right)+\left(1+2+3+...+30=1240\right)\)(31 chữ số x)
\(31x+\frac{30\cdot31}{2}=1240\Leftrightarrow31x+465=1240\)
\(31x=1240-465=775\)
\(x=\frac{775}{31}=25\)
c) \(11-\left(-53+x\right)=97\)
\(11+53-x=97\Leftrightarrow64-x=97\)
\(x=64-97=-33\)
d) \(-\left(x+81\right)+213=-16\)
\(-x-81+213=-16\)
\(-x+132=-16\)
\(-x=-16-132=-148\)
\(x=148\)
..........
Bài 1: Thực hiện các phép tính sau một cách hợp lý:
a) ( 102 + 112 + 122 ) : ( 132 + 142 )
b) 1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
c) ( 3.4.216)2 / 11.213.411-169
d) 1152 - ( 374 +1152 ) + ( -65+374 )
e) 13 - 12 +11 +10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1
Bài 2: Tìm x biết:
a) (19x + 2.52) :14 = (13 - 8)2 -42
b) x + ( x+1) + ( x+2) +...+ ( x+30) = 1240
c) 11 - (-53+x) = 97
d) -(x+84) +213 = -16
Bài 1:
A,
(100+121+144)÷(169+196)
=365:365=1
B
,1.2.3...7.8.(9-1-8)
=1.2.3...7.8.0=0
C,
3^2.2^4.2^32/11.2^13.2^22-2^26
=3^2.2^36/11.2^35-2^36
=3^2.2^36/2^35-(11-2)
=9.2/9=2
D,
=1152-374-1152+(-65)+374
=(1152-1152)+(-374+374)+(-65)
=0+0+(-65)=-65
E,
=13-(12-11-10+9)+(8-7-6+5)-(4-3-2+1)
=13-0+0-0=13
Bài 2:
A,(19x+50)÷14=25-16
(19x+50)÷14=9
19x+50=126
19x=76
x=4
B,
31x+(1+2+3+...+30)=1240
31x+465=1240
31x=775
×=25
BÀI 2:
c)11-(-53+x)=97
=> x=97-11-53
=> x=33
K CHO MÌNH NHA
Bài 1: tìm x, biết:
a) (19x + 2.52) : 14 bằng ( 13 -8)2 - 42
b) x+ (x +1)+ ( x+ 2)+...+ ( x+ 30) bằng 1240
c) -( x+ 84)+ 213 bằng -16
AI GIẢI NHANH MÌNH CÁI NHÉ GHI CẢ CÁCH LÀM LUÔN LÀM ĐƯỢC MÌNH TICK CHO
Bài 2 : Tìm x , biết :
a, \(\left(19x+2\cdot5^2\right)\text{ : }14=\left(13-8\right)^2-4^2\)
b, \(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+30\right)=1240\)
c, \(11-\left(-53+x\right)=97\)
d, \(-\left(x+84\right)+213=-16\)
e, \(13-12+11+10-9+8-7-6+5-4+3+2-1=x\)
\(a,\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Leftrightarrow\left(19x+50\right):14=5^2-4^2\)
\(\Leftrightarrow\left(19x+50\right):14=9\)
\(\Leftrightarrow19x+50=126\)
\(\Leftrightarrow19x=76\Leftrightarrow x=4\)
b) x + ( x + 1 ) + ( x + 2 ) + ... + ( x + 30 ) = 1240
x + x + 1 + x + 2 + ... + x + 30 = 1240
( x + x + ... + x ) + ( 1 + 2 + ... + 30 ) = 1240
Số số hạng là : ( 30 - 1 ) : 1 + 1 = 30 ( số )
Tổng là : ( 30 + 1 ) . 30 : 2 = 465
=> 31x + 465 = 1240
=> 31x = 775
=> x = 25
Vậy........
c) 11 - ( -53 + x ) = 97
11 + 53 - x = 97
64 - x = 97
x = 64 - 97
x = -33
Tìm x
a) \(\left(19.x+2.5^1\right):14=\left(13-8\right)^2-4^2\)
b) \(-\left(x+84\right)+213=-16\)
\(\left(19x+2.5^1\right):14=\left(13-8\right)^2-4^2.\)
\(\left(19x+10\right):14=5^2-4^2\)
\(\left(19x:4\right)+\left(10:4\right)=25-16\)
\(\left(19x:4\right)+\frac{5}{2}=9\)
\(19x:4=9-\frac{5}{2}\)
\(19x:4=\frac{13}{2}\)
\(19x=\frac{13}{2}.4=26\)
\(x=\frac{26}{19}\)
B/ \(-\left(x+84\right)+213=\left(-16\right).\)
\(-x-84+213=-16\)
\(-x+129=-16\)
\(-x=\left(-145\right)\)
\(\Rightarrow x=145\)
Bài 1 : Tìm x, biết:
a) (19x+2 nhân 52) :14 bằng (13 -8)2- 42
b) x+(x+1)+(x+2)+...+(x+30) bằng 1240
c)11- (-53 +x) bằng 97
d) -(x+84) +213 bằng -16
Bài 2 : Tìm hai số tự nhiên a và b,biết: BCNN(a,b) bằng 300; ƯCLN(a,b) bằng 15 và a+15 bằng b