Giải:

\(\dfrac{1}{2}-\dfrac{43}{100}+\left(-\dfrac{1}{3}\right)-\dfrac{1}{6}\)

\(=-\dfrac{43}{100}+\dfrac{1}{2}+\left(-\dfrac{1}{3}\right)-\dfrac{1}{6}\)

\(=-\dfrac{43}{100}+\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\)

\(=-\dfrac{43}{100}+\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)

\(=-\dfrac{43}{100}+\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)\)

\(=-\dfrac{43}{100}+0=-\dfrac{43}{100}\)

Vậy ...

\(\dfrac{1}{2}-\dfrac{43}{101}+\dfrac{-1}{3}-\dfrac{1}{6}\\ =\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)-\dfrac{43}{101}=0-\dfrac{43}{101}=-\dfrac{43}{101}\)

??? Ơ A cho thừa hả? 

\(\frac{1}{2}-\frac{43}{101}+\left(-\frac{1}{3}\right)-\frac{1}{6}\)

\(=\frac{1}{2}-\frac{43}{101}-\frac{1}{3}-\frac{1}{6}\)

\(=\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)-\frac{43}{101}\)

\(=0-\frac{43}{101}\)

\(=-\frac{43}{101}\)

P/s tham khảo nhaaaa

-43/101

\(=\left(\frac{1}{2}-\frac{1}{3}\right)-\frac{1}{6}-\frac{43}{101}=\left(\frac{3}{6}-\frac{2}{6}\right)-\frac{1}{6}-\frac{43}{101}\)

\(=\frac{1}{6}-\frac{1}{6}-\frac{43}{101}=0-\frac{43}{101}=\frac{-43}{101}\)

Hok tốt! k mk nha^^

a. 2; 25; 3; 1; 5; 4; 87; 65; 98; 12 ;0.

b. 6; 8;11; 30; 79; 9; 101; 15; 56; 43; 111.

a.số nhỏ nhất:0

số lớn nhất:98

bsố nhỏ nhất:6

số lớn nhất:111

a.0

b.6

Mk thấy phần a dễ lên bạn tự làm nha

B=(37373737.43-43434343.37):(1²+2²+3²+............+100²)

B=(37.1010101.43-43.101010101.37):(1²+2²+3²+............+100²)

B=0:(1²+2²+3²+............+100²)

B=0

Vậy B=0

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