x.2 + x.4 + x.6 + x.8 + ... + x.18 + x.20 = 1760/4

x.2.(1 + 2 + 3 + 4 + ... + 9 + 10) = 440

x.2.(10 + 1).10:2 = 440

x.11.10 = 440

x.110 = 440

x = 440 : 110

x = 4

Vậy x = 4

Ủng hộ mk nha ^-^

\(x\cdot\left(\left(2+20\right)\cdot\left(\left(20-2\right):2+1\right):2\right)=440\)

\(x\cdot110=440\)

\(x=440:110\)

\(x=4.\)

1, để 18⋮x

thì x∈Ư(18)\(\left\{18;1;9;2;-2;-1;-18;-9\right\}\)

Mà x<0

Suy ra x=-2;-1;-18;-9

2, để 2⋮x

thì x∈Ư(2)\(\left\{-1;2;1;-2\right\}\)

mà x>0

Suy ra x=2;1

3, để -18⋮x và 12⋮x

thì x∈Ư(-18;12)\(\left\{6;-6\right\}\)

Suy ra x=6;-6

Câu 4; 5 tương tự nhé !

#Mai.T.Loan

Lời giải:

a. $(x+5)-20=123$

$x+5=123+20=143$

$x=143-5=138$

b. 

$-18+(3-x)=25$

$3-x=25+18=43$

$x=3-43=-404

c. $4(x-2)+11=-13$

$4(x-2)=-13-11$

$4(x-2)=-24$

$x-2=-24:4=-6$

$x=-6+2=-4$

d.

$(x+10):(-20)=6$

$x+10=6(-20)=-120$

$x=-120-10=-130$

a)(x+5)-20=123

   (x+5)=123+20

  x+5=143

x=143-5

x=138

b)-18 + (3-x)=25

  (3-x)=25-(-18)

3-X=43

x=3-43

x=-40

c)4.(x-2):(-20)=6

   4.(x-2)=6.(-20)

  4.(x-2)=-120

x-2=(-120):4

x-2=-30

x=(-30)+2

x=-28

d)

 ( x + 10 ) : ( - 20 ) = 6

 x+10=6.(-20)

x+10=-120

x=(-120)-10

x=-130

17)

\(x^3-2x^2+x\\ =x\left(x^2-2x+1\right)\\ =x\left(x-1\right)^2\)

18)

\(3\left(x+4\right)-x^2-4x\\ =3\left(x+4\right)-x\left(x+4\right)\\ =\left(x+4\right)\left(3-x\right)\)

19)

\(x^2+5x-6\\ =x^2+6x-x-6\\ =x\left(x+6\right)-\left(x+6\right)\\ =\left(x+6\right)\left(x-1\right)\)

20)

\(x^2+x-20\\ =x^2+5x-4x-20\\ =x\left(x+5\right)-4\left(x+5\right)\\ =\left(x+5\right)\left(x-4\right)\)

\(17,x^3-2x^2+x=x\left(x^2-2x+1\right)=x\left(x-1\right)^2\)

\(18,3\left(x+4\right)-x^2-4x=3\left(x+4\right)-x\left(x+4\right)=\left(x+4\right)\left(3-x\right)\)

\(19,x^2+5x-6=x^2-x+6x-6=x\left(x-1\right)+6\left(x-1\right)=\left(x-1\right)\left(x+6\right)\)

\(20,x^2+x-20=x^2-4x+5x-20=x\left(x-4\right)+5\left(x-4\right)=\left(x-4\right)\left(x+5\right)\)