a) \(2075:5=\frac{x\times75}{5+40}\)

\(415=\frac{x\times75}{45}\)

\(\Rightarrow x\times75=415\times45\)

\(x\times75=18675\)

\(x=18675:75\)

\(x=249\)

b) \(x+x:5\times7,5+x:2\times9=315\)

\(x+x\times\frac{1}{5}\times7,5+x\times\frac{1}{2}\times9=315\)

\(x\times\left(1+\frac{1}{5}\times7,5+\frac{1}{2}\times9\right)=315\)

\(x\times7=315\)

\(x=315:7\)

\(x=45\)

Lưu ý mình dùng * thay cho dấu nhân và / thay cho dấu chia.

a) 2075/5 = \(\frac{x\cdot75}{5+40}\)

\(\frac{x\cdot75}{5+40}\) = \(\frac{x\cdot75}{45}\) = 415

(x * 75) / 45 = 415

x * 75 = 415 * 45 = 18675

x = 18675 / 75

x = 249

b) x + x / 5 * 7,5 + x / 2 * 9 = 315

x + x * \(\frac{7,5}{5}\)+ x * \(\frac{9}{2}\)= 315

x * 1 + x * \(\frac{7,5}{5}\)+ x * \(\frac{9}{2}\)= 315

x * (1 + \(\frac{7,5}{5}\)+ \(\frac{9}{2}\)) = 315

x * 7 = 315

x = 315 / 7

x = 45

Chúc bạn học tốt !

415 ở đâu vậy

\(\left(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}\right).y=\frac{2}{3}\)

\(\frac{1}{2}.\left(1-\frac{1}{3}\right)+\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{5}\right)+\frac{1}{2}.\left(\frac{1}{5}-\frac{1}{7}\right)+\frac{1}{2}.\left(\frac{1}{7}-\frac{1}{9}\right)+\frac{1}{2}.\left(\frac{1}{9}-\frac{1}{11}\right).y=\frac{2}{3}\)

\(\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right).y=\frac{2}{3}\)

\(\frac{1}{2}.\left(1-\frac{1}{11}\right).y=\frac{2}{3}\)

\(\left(1-\frac{1}{11}\right).y=\frac{4}{3}\)

\(\frac{10}{11}.y=\frac{4}{3}\)

\(\Rightarrow y=\frac{22}{15}\)

   \(4x+5\)\(⋮\)\(x+1\)

\(\Rightarrow\)\(4\left(x+1\right)+1\)\(⋮\)\(x+1\)

Ta thấy     \(4\left(x+1\right)\)\(⋮\)\(x+1\)

\(\Rightarrow\)\(1\)\(⋮\)\(x+1\)

\(\Rightarrow\)\(x+1\)\(\inƯ\left(1\right)=\left\{\pm1\right\}\)

\(\Rightarrow\)\(x\)\(=\left\{-2;0\right\}\)

Vậy...

Ta có :

\(4x+5=4x+4+1=4.\left(x+1\right)+1\)chia hết cho \(x+1\)\(\Rightarrow\)\(1\)chia hết cho \(x+1\)\(\Rightarrow\)\(\left(x+1\right)\inƯ\left(1\right)\)

Mà \(Ư\left(1\right)=\left\{1;-1\right\}\)

Do đó :

\(x+1=1\Rightarrow x=1-1=0\)

\(x+1=-1\Rightarrow x=-1-1=-2\)

Vậy \(x\in\left\{0;-2\right\}\)

Chúc bạn học tốt 

\(4x\)+ \(5\)chia hết cho \(x+1\)

\(4x\)+\(4+1\)chia hết cho\(x+1\)

\(4\)x\(\left(x+1\right)\)+1 chia hết cho\(x+1\)

mà \(4\)  x  \(\left(x+1\right)\)chia hết cho\(x+1\)

\(\Rightarrow\)1 chia hết cho \(x+1\)

\(\Rightarrow\) \(x+1\)\(\in\)Ư( 10)

th1: x + 1 = 1               th2: x + 1 = -1

      x = 0                            x = -2

Vậy x \(\in\){0;-2}

x-2x+5y-12=0

y(x+5)-2(x+5)-2=0

(y-2)(x+5)=2

xong thu TH nha 

k cho toi di Hien beo ne

Ba oi thay Hung cung cho de nay a

cảm ơn bà Hiền béo nhìu nha,nhưng tui làm xong từ hôm wa rùi...hihi..

_7.|x+3|=_49

     |x+3|= - 49 : ( - 7 )

     |x+3|= 7 

   => x + 3 = 7

        x       = 7 - 3  

       x        = 4

(2x+1)^3=125

(2x + 1 )³ = 25³

=> 2x + 1 = 25

     2x       = 25 - 1

    2x        = 24

   x           = 24 : 2 

    x           = 12 

bai de ma o lam duoc a

tích hộ cái

\(x-\left[\frac{50x}{100}+\frac{25x}{200}\right]=11\frac{1}{4}\)

\(x-\left[\frac{50x\cdot2}{200}+\frac{25x}{200}\right]=11\frac{1}{4}\)

\(x-\left[\frac{100x}{200}+\frac{25x}{200}\right]=11\frac{1}{4}\)

\(x-\frac{125x}{200}=11\frac{1}{4}\)

\(\frac{200x}{200}-\frac{125x}{200}=11\frac{1}{4}\)

\(\frac{200x-125x}{200}=11\frac{1}{4}\)

\(\frac{75x}{200}=11\frac{1}{4}\)

\(\frac{3x}{8}=11\frac{1}{4}\)

\(3x=11\frac{1}{4}\cdot8\)

\(3x=90\)

\(x=30\)

Vậy x = 30

cảm ơn bn nhé

kb ko