=> 3^x-2 . (3^2+3+1) = 117

=> 3^x-2 . 13 = 117

=> 3^x-2 = 117 : 13 = 9

=> 3^x-2 = 3^2

=> x-2 = 2

=> x = 4

Vậy x = 4

Tk mk nha

3^x+3^x+1+3^x+2=117

=> 3^x.(1+3+3²)=117

=> 3^x.(1+3+9)=117

=> 3^x.13=117

=> 3^x=117:13

=> 3^x=9

=> 3^x=3²

Vậy x=2.

ai nhanh nhất mình k cho

Bài 1:

\(A=\frac{1}{\left(1+2\right)}+\frac{1}{\left(1+2+3\right)}+\frac{1}{\left(1+2+3+4\right)}\)\(+\frac{1}{\left(1+2+3+4+5\right)}+...+\)\(\frac{1}{\left(1+2+3+...+10\right)}\)

\(A=\frac{1}{3}+\frac{1}{6}+....+\frac{1}{55}\)

\(A=2\left(\frac{1}{6}+\frac{1}{12}+....+\frac{1}{110}\right)\)

\(A=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)\)

\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}\right)\)

\(A=2.\left(\frac{1}{2}-\frac{1}{11}\right)\)

\(A=\frac{9}{11}\)

Bài 2 :

2)  Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15

= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15

Mẫu số =  11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19  + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17  

=  (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x  17 = (1+27+125+729) x 13 x 15 x 17 

\(\Rightarrow A< \frac{\left(1+27+125+729\right)\times11\times13\times15}{\left(1+27+125+729\right)\times13\times15\times17}\)

\(=\frac{11}{17}\)

\(=\frac{1111}{1717}=B\)

Vậy \(A=B\)

mình đâu biết

=> 3^x . (1+3+3^2) = 117

=> 3^x . 13 = 117

=> 3^x = 117 : 13 = 9

=> 3^x = 3^2

=> x = 2

Vậy x = 2

Tk mk nha

3^x + 3^x+1 +3^x+2 = 117

=> 3^x + 3^x . 3 + 3^x . 9 = 117

=> 3^x ( 1 + 3 + 9) = 117

=> 3^x . 13 = 117

=> 3^x = 9

=> x = 2

\(3^x+3^{x+1}+3^{x+2}=117\Leftrightarrow3^x+3\cdot3^x+3^2\cdot3^x=117\)

\(\Leftrightarrow3^x\cdot\left(1+3+3^2\right)=117\Leftrightarrow3^x\cdot13=117\)

\(\Leftrightarrow3^x=9\Leftrightarrow3^x=3^2\Leftrightarrow x=2\)

Vậy x = 2

Tích cho mk nhoa !!!! ~~

3^x + 3^x+1 + 3^x+2=117

3^x.(1+3+3^2)=117

3^x.13=117

3^x=117:13

3^x=9

Ta có:9=3^2

Vậy x=2

=>3^x+x+x+1+2=117

=>3^3x+3=117

=>

\(3^x+3^{x+1}+3^{x+2}=117\)

\(\Rightarrow3^x+3^x.3+3^x.3^2=117\)

\(\Rightarrow3^x.\left(1+3+3^2\right)=117\)

\(\Rightarrow3^x.13=117\)

\(\Rightarrow3^x=9\)

\(\Rightarrow3^x=3^2\)

\(\Rightarrow x=2\)

Vậy \(x=2\)

\(\Rightarrow3^x\left(1+3+3^2\right)=117\)

\(\Rightarrow3^x.13=117\)

\(\Rightarrow3^x=9\)

=>x = 2

Vây x = 2

1)\(A=\frac{1}{3}+\frac{1}{6}+...+\frac{1}{55}=2\left(\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\right)=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\right)=2.\left(\frac{1}{2}-\frac{1}{11}\right)=\frac{9}{11}\)

2) Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15

= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15

Mẫu số =  11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19  + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 

lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 

=  (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x  17 = (1+27+125+729) x 13 x 15 x 17

=> \(A

giải giùm mình bài này vớC= (67/111+2/33-15/117)x(1/3-1/4-1/12)

3^x+3^x+1+3^x+2=117

=> 3^x.(1+3+3²)=117

=> 3^x.(1+3+9)=117

=> 3^x.13=117

=> 3^x=117:13

=> 3^x=9

=> 3^x=3²

=> x=2

3^x+3^x+1+3^x+2=117

=> 3^x.(1+3+3²)=117

=> 3^x.(1+3+9)=117

=> 3^x.13=117

=> 3^x=117:13

=> 3^x=9

=> 3^x=3²

=> x= 2

tick nha