Bạn học căn thức chưa ?

phan tich cac da thuc sau thanh nhan tu theo mau:

a)\(2x^3-x\)

\(=x\left(2x^2-1\right)\)

\(=x\left(\left(\sqrt{2}x\right)^2-1^2\right)\)\

\(=x\left(\sqrt{2}x-1\right)\left(\sqrt{2}x+1\right)\)

b)\(5x^2\left(x-1\right)-15x\left(x-1\right)\)

\(=\left(5x^2-15x\right)\left(x-1\right)\)

\(=5x\left(x-3\right)\left(x-1\right)\)

d)\(3x\left(x-2y\right)+6y\left(2y-x\right)\)

\(=3x\left(x-2y\right)-6y\left(x-2y\right)\)

\(=\left(3x-6y\right)\left(x-2y\right)\)

\(=3\left(x-2y\right)\left(x-2y\right)\)

\(=3\left(x-2y\right)^2\)

a, = (xy-y^2) + (2x-2y) = y(x-y) + 2.(x-y) = (x-y).(y+2) 

b, = (x+y)^2 - 9 = (x+y-3).(x+y+3)

\(xy-y^2-2x-2y\)   

=(xy-y).(2x-2y)

=y(x-y).2(x-y)

=(x-y).(y-2)

camr ơn bạn nha

x⁴+x³+2x²+x+1=x⁴+x³+x²+x²+x+1=(x⁴+x³+x²)+(x²+x+1)

                                                      =x²(x²+x+1)+(x²+x+1)

                                                       =(x²+x+1)(x²+1)

=(x^4+2x^2+1)+(x^3+x)

=(x^2+1)^2+x(x^2+1)

(x^+1)*(x^2+1+x0

(x² - 3)² + 16

= (x² - 3)² + 4²

= (x² - 3 + 4)(x² - 3 - 4)

= (x² + 1)(x² - 7)

đúng  đi rồi làm cho

a) 27x³-27x²+18x-4

   =27x³-9x²-18x²+6x+12x-4

   =9x²(3x-1)-6x(3x-1)+4(3x-1)

   =(9x²-6x+4)(3x-1)

b) mk k bít lm

c)(x²-3)²+16

=(x²-3)²+4²

=(x²-3+4)(x²-3-4)

=(x²+1)(x²-7)

k mk nha

thanks